Bài 5: Tìm x.a, x + \(\frac{2}{5}\) = \(\frac{1}{2}\) ...
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Bài 5: Tìm x.
a, x + \(\frac{2}{5}\) = \(\frac{1}{2}\) b, \(\frac{19}{20}-x=\frac{8}{5}-\frac{3}{4}\)
a, \(x=\dfrac{1}{2}-\dfrac{2}{5}=\dfrac{5-4}{10}=\dfrac{1}{10}\)
b, \(\dfrac{19}{20}-x=\dfrac{32-15}{20}=\dfrac{17}{20}\Rightarrow x=\dfrac{19}{20}-\dfrac{17}{20}=\dfrac{2}{20}=\dfrac{1}{10}\)