chứng minh rằng [2n.(2n-1)...(n+1)]/[n.(n-1)...2.1]>_4^n/n+1 với mọi n thuộc N*
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Lời giải:
46 m2 25 cm2 + 28 dm2 = 4600,25 dm2 + 28 dm2 = 4628,25 dm2
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Lời giải:
Ô tô phải xuất phát từ Hà Nội lúc:
10 giờ 30 phút - 2 giờ 30 phút - 35 phút = 7 giờ 25 phút
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Lời giải:
Ta có:
$\sin B = \frac{AH}{AB}\Rightarrow AB=\frac{AH}{\sin B}=\frac{3}{\frac{3}{4}}=4$
$\sin B=\frac{3}{4}\Rightarrow \widehat{B}=48,6^0$
$\widehat{C}=90^0-\widehat{B}=90^0-48,6^0=41,4^0$
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Lời giải:
Đặt:
$A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2024}}$
$2A=1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2024}}$
$\Rightarrow 2A-A=1-\frac{1}{2^2{2024}}$
$\Rightarrow A=1-\frac{1}{2^{2024}}$
Khi đó:
$223-x.A:(1-\frac{1}{2^{2024}})=2023$
$\Rightarrow 223-x.(1-\frac{1}{2^{2024}}):(1-\frac{1}{2^{2024}})=2023$
$\Rightarrow 223-x=2023$
$\Rightarrow x=223-2023=-1800$
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Lời giải:
$\frac{1}{4}=\frac{3}{12}=\frac{2}{12}+\frac{1}{12}=\frac{1}{6}+\frac{1}{12}$
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\(\dfrac{6}{x-3}=\dfrac{48}{56}\)
\(x-3=6:\dfrac{48}{56}\)
\(x-3=7\)
\(x=7+3\)
\(x=10\)
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Lời giải:
Số số hạng: $100-(x-20)+1=121-x$ (số)
$(x-20)+(x-19)+(x-18)+...+99+100=[100+(x-20)](121-x):2=100$
$(x+80)(121-x)=200$
$121x-x^2+9680-80x=200$
$-x^2+41x+9480=0$
$x^2-41x-9480=0$
$(x-120)(x+79)=0$
$\Rightarrow x=120$ hoặc $x=-79$
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xy+12=x+y
=>xy-x-y+12=0
=>\(xy-x-y+1+11=0\)
=>\(x\left(y-1\right)-\left(y-1\right)=-11\)
=>\(\left(x-1\right)\left(y-1\right)=-11\)
=>\(\left(x-1\right)\left(y-1\right)=1\cdot\left(-11\right)=\left(-1\right)\cdot11=\left(-11\right)\cdot1=11\cdot\left(-1\right)\)
=>\(\left(x-1;y-1\right)\in\left\{\left(1;-11\right);\left(-1;11\right);\left(-11;1\right);\left(11;-1\right)\right\}\)
=>\(\left(x;y\right)\in\left\{\left(2;-10\right);\left(0;12\right);\left(-10;2\right);\left(12;0\right)\right\}\)
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