\(6^6:6^3+4^3\cdot4^2\\=6^3+4^5\\=216+1024\\=1240\)

KQ : 1240

giải thích 

= 46656 : 216 + 64 . 16

= 216 + 1024 = 1240

a,3+31  ;5+29    

b,2+7+23

tick mik nha

\(125-5\left(2x+4\right)=25\)

\(\Rightarrow5\left(2x+4\right)=125-25\)

\(\Rightarrow5\left(2x+4\right)=100\)

\(\Rightarrow2x+4=\dfrac{100}{5}\)

\(\Rightarrow2x+4=20\)

\(\Rightarrow2x=20-4\)

\(\Rightarrow2x=16\)

\(\Rightarrow x=\dfrac{16}{2}\)

\(\Rightarrow x=8\)

x = 8

giải thích

125 - 5(2x+4)=25

5(2x+4)= 125 - 25

5(2x+4) = 100

2x+4 =  100 : 5

2x+4 = 20

2x = 20 -4

2x = 16

x = 8

dễ

n=2

Lời giải:
$36.333-108.111=36.3.111-108.111=108.111-108.111=0$

Suy ra:
$(2+4+6+...+100)(36.333-108.111)=(2+4+6+...+100).0=0$

HI

Hình vẽ đâu bạn

Hình vẽ đâu ạ

\((2x-5)^2=49\\\Rightarrow \left[\begin{array}{} 2x-5=7\\ 2x-5=-7 \end{array} \right. \\\Rightarrow \left[\begin{array}{} 2x=12\\ 2x=-2 \end{array} \right. \\\Rightarrow \left[\begin{array}{} x=6\\ x=-1 \end{array} \right.\)

\(Vậy:x\in\left\{-1;6\right\}\)

(2x-5)²=7² 

^2x-5=7

^2x=7+5

^2x=12

^x=6

`#3107.101107`

\(3^{x+1}=27\\ \Rightarrow3^{x+1}=3^3\\ \Rightarrow x+1=3\\ \Rightarrow x=3-1\\ \Rightarrow x=2\)

Vậy, `x = 2.`

\(3^{x+1}=27\)

\(3^{x+1}=3^3\)

\(=>x+1=3\)

\(x=3-1\)

\(=>x=2\)

\(A=5+5^2+5^3+...+5^{20}\)

\(A=\left(5+5^2\right)+\left(5^3+5^4+5^5\right)+...+\left(5^{18}+5^{19}+5^{20}\right)\)

\(A=30+5^3\cdot31+...+5^{18}\cdot31\)

\(A=30+31\cdot\left(5^3+5^6+...+5^{18}\right)\)

Mà: \(31\cdot\left(5^3+5^6+...+5^{18}\right)\) ⋮ 31

\(\Rightarrow A=30+31\cdot\left(5^3+5^6+...+5^{18}\right)\) chia cho 31 dư 30 

A = 5 + 5² + 5³ +...+ 5²⁰

A = 5²⁰ + 5¹⁹ + 5¹⁸ +...+ 5³ + 5² + 5

A = (5²⁰ + 5¹⁹ + 5¹⁸) + (5¹⁷ + 5¹⁶ + 5¹⁵) +...+ (5⁵ + 5⁴ + 5³) + (5²+ 5)

A = 5¹⁸.( 5² + 5 + 1) + 5¹⁵.(5² + 5 + 1) +...+ 5³.(5²+ 5 + 1) + (25 + 5)

A = 5¹⁸. 31 + 5¹⁵.31 +...+ 5³.31 + 30

A = 31.(5¹⁸ + 5¹⁵ +...+ 5³) + 30

31 ⋮ 31 ⇒ 31.(5¹⁸ + 5¹⁵ +...+5³) ⋮ 31 mà 30 : 31 = 0 dư 31 

Vậy A : 31 dư 30