1+3+3 mũ 2+ ... 3 mũ 11 = ?
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\(7.3^x+20.3^x=3^{25}\)
\(\Leftrightarrow3^x.27=3^{25}\)
\(\Leftrightarrow3^x=3^{25}:3^3\)
\(\Leftrightarrow x=22\)
( 7 + 20 ) .3x = 325
27 . 3x = 325
33 . 3x = 325
3x = 325 : 33
3x = 325-3
3x = 322
=> x = 22
vậy x = 22
8 + ( x - 9 ) = 125 - 64
8 + ( x - 9 ) = 61
x - 9 = 61 - 8
x - 9 = 53
x = 53 + 9
x = 62
vậy x = 62
\(2^3+x+3^2=5^3-4^3\)
\(\Leftrightarrow8+x+3^2=61\)
\(\Leftrightarrow x+3^2=53\)
\(\Leftrightarrow x=44\)
19 x 25 + 19 x 16 + 41
= 19 x (25 + 16) + 41
= 19 x 41 + 41
= (19 + 1) x 41
= 20 x 41
= 820
\(19\times25+19\times16+41\)
\(=19\times\left(25+16\right)+41\)
\(=41\times20=820\)
A = 82 : 4 . 3 + 2.5^2
A = 64 :4 .3 + 10.5
A = 16 .3 +50
A = 48 + 50
A = 98
x.(2x-1).(3x-126)=0
\(\Rightarrow\left[{}\begin{matrix}x=0\\2x-1=0\\3x-126=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{2}\\3x=126\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{2}\\x=42\end{matrix}\right.\)
X.(2X - 1) .(3X - 126) = 0
X = 0 ;
2x- 1 =0 ⇒ x = 1/2
3x - 126 = 0
x = 126: 3
x = 42
\(A=2+2^2+2^3+.....+2^{2023}+2^{2024}+2^{2025}\)
\(A=2\left(1+2+4\right)+.....+2^{2023}\left(2+2+4\right)\)
\(A=2.7+.....+2^{2023}.7⋮7\left(đpcm\right)\)
\(A=2+2^2+2^3+...+2^{2025}\\ A=\left(2+2^2+2^3\right)+\left(2^4+2^5+2^6\right)+...+\left(2^{2023}+2^{2024}+2^{2025}\right)\\ A=2.\left(1+2+2^2\right)+2^4\left(1+2+2^2\right)+...+2^{2023}\left(1+2+2^2\right)\\ A=2.7+2^4.7+2^7.7+...+2^{2023}.7\\ A=\left(2+2^4+2^7+...+2^{2023}\right).7⋮7\)
Vậy \(A⋮7\left(đpcm\right)\)
\(A=2+2^2+2^3+....+2^{2024}+2^{2025}\)
\(\Leftrightarrow2A=2^2+2^3+2^4+....+2^{2025}+2^{2026}\)
\(\Leftrightarrow2A-A=A=2^{2026}-2\)
\(3\left(x+30\right)=8\)
\(\Leftrightarrow x+30=\dfrac{8}{3}\)
\(\Leftrightarrow x=\dfrac{-82}{3}\)
Đặt A = 1 + 3 + 32 + ... + 311
3A = 3 + 32 + 33 + ... + 312
3A - A = ( 3 + 32 + 33 + ... + 312 ) - ( 1 + 3 + 32 + ... + 311 )
2A = 312 - 1
A = \(\dfrac{3^{12}-1}{2}\)