Viết kết bài của sơn tinh, thuỷ tinh
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
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p là số nguyên tố lớn hơn 2 => p có dạng 4n + 1 và 4n - 1 ( c/m bổ đề phụ )
a) Xét 2 t/h xảy ra của p :
TH1 : p + 2017 = 4n + 1 + 2017 = 4n + 2018 = 2 ( 2n + 1009 ) chia hết cho 2 => hợp số
TH2 : p + 2017 = 4n - 1 + 2017 = 4n + 2016 = 2 ( 2n + 1008 ) chia hết cho 2 => hợp số
b) tương tự xét 2 t/h của p
Bài 1 :
\(A=2^{12}.25^4=2^8.2^4.5^8=10^8.2^4=10^8.16\)
\(10^8\) có 9 chữ số ( 1 chữ số 1 và 8 chữ số 0 )
Theo tính chất nhân 1 số tự nhiên với 10; 100; 1000; ... ;\(10^n\) ta có :
\(a.10^n=\overline{a00...0}\) ( n chữ số 0 )
Suy ra \(10^8.16\) có 10 chữ số
Vậy \(A\) có 10 chữ số
Bài 2 :
\(B=4+2^2+2^3+2^4+...+2^{35}\)
\(2\left(B-4\right)=2^3+2^4+2^5+...+2^{36}\)
\(2\left(B-4\right)-\left(B-4\right)=\left(2^3+2^4+2^5+...+2^{36}\right)-\left(2^2+2^3+2^4+...+2^{35}\right)\)
\(B-4=2^{36}-4\)
\(B=2^{36}\)
\(B=\left(2^{18}\right)^2\) là số chính phương
Vậy \(B\) là số chính phương
Chúc bạn học tốt ~
Mã Lương thuộc kiểu nhân vật phổ biến trong truyện cổ tích là:
- Nhân vật có tài lạ, luôn dùng tài năng để giúp đỡ người nghèo, chống lại kẻ ác, tham lam.
Một số nhân vật phổ biến là:
Thạch Sanh, Sọ Dừa,...
2x+2 - 2x = 96
<=> 2x × 22 - 2x = 96
<=> 2x.( 22 - 1 ) = 96
<=> 2x . 3 = 96
<=> 2x = 96 : 3
<=> 2x = 32
<=> 2x = 25
<=> x = 5
Vậy x = 5
\(=>\orbr{\begin{cases}\left(2x-3\right)^2=6^2\\\left(2x-3\right)^2=\left(-6\right)^2\end{cases}}\)
\(=>\orbr{\begin{cases}2x-3=6\\2x-3=-6\end{cases}}\)
\(=>\orbr{\begin{cases}2x=9\\2x=-3\end{cases}}\)
\(=>\orbr{\begin{cases}x=\frac{9}{2}\\x=-\frac{3}{2}\end{cases}}\)
( 2x - 3 ) ^2 = 36
(2x-3 ) ^2 = ( + - 6 ) ^2
-> 2x-3 = +- 6
* 2x -3 =6 * 2x -3 = -6
2x = 9 2x= -3
x= 9/2 x = -3 /2
vậy x \(\in\)( 9/2 : -3 /2 )
ý b ) tự làm nha bạn , nó còn dễ hơn 1^ 2
Vậy là mùa bão lụt của năm nay đã qua, nhân dân lại được sống yên bình. Với những máy móc khoa học kĩ thuật, Sơn Tinh lại một lần nữa chiến thắng. Em mong rằng năm sau, nhiều năm nữa Thuỷ Tinh sẽ không dâng nước đánh