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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(3x=7y\)
\(\Rightarrow\frac{x}{7}=\frac{y}{3}=\frac{y-x}{3-7}=\frac{8}{-4}=-2\)
\(\Rightarrow\hept{\begin{cases}x=-14\\y=-6\end{cases}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1: Tính hợp lí:
\(a)\)\(\frac{14}{57}+\frac{29}{23}-\frac{71}{57}+\frac{-6}{23}\)
\(=\)\(\left(\frac{14}{57}-\frac{71}{57}\right)+\left(\frac{29}{23}+\frac{-6}{23}\right)\)
\(=\)\(\left(-\frac{57}{57}\right)+\left(\frac{23}{23}\right)\)
\(=\)\(\left(-1\right)+1\)
\(=\)\(0\)
\(b)\)\(\frac{5}{12}.\left(\frac{-3}{4}\right)+\frac{7}{12}.\left(\frac{-3}{4}\right)\)
\(=\)\(\left(\frac{-3}{4}\right).\left(\frac{5}{12}+\frac{7}{12}\right)\)
\(=\)\(\left(\frac{-3}{4}\right).1\)
\(=\)\(-\frac{3}{4}\)
\(c)\)\(\left(\frac{-3}{11}\div\frac{5}{22}\right).\left(\frac{-15}{3}\div\frac{26}{3}\right)\)
\(=\)\(\left(\frac{-3}{11}.\frac{22}{5}\right).\left(\frac{-15}{3}.\frac{3}{26}\right)\)
\(=\)\(\frac{-6}{5}.\frac{-15}{26}\)
\(=\)\(\frac{9}{13}\)
\(d)\)\(\left(0,25\right)^{100}.4^{103}\)
\(=\)\(\left(\frac{1}{4}\right)^{100}.4^{103}\)
\(=\)\(\left(\frac{1}{4}.4\right)^{100+103}\)
\(=\)\(1^{203}\)
\(=\)\(1\)
Bài 2: Tìm x, biết:
\(a)\)\(\left(\frac{3}{7}-2x\right)^2=\frac{4}{9}\)
\(\Leftrightarrow\)\(\left(\frac{3}{7}-2x\right)^2=\left(\frac{2}{3}\right)^2\)
\(\Leftrightarrow\)\(\frac{3}{7}-2x=\frac{2}{3}\)
\(\Leftrightarrow\)\(2x=\frac{3}{7}-\frac{2}{3}\)
\(\Leftrightarrow\)\(2x=\frac{-5}{21}\)
\(\Leftrightarrow\)\(x=\frac{-5}{21}\div2\)
\(\Leftrightarrow\)\(x=\frac{-5}{42}\)
\(b)\)\(x+5,5=7,5\)
\(\Leftrightarrow\)\(x=7,5-5,5\)
\(\Leftrightarrow\)\(x=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
TL:
5x+2. 4y = 50x
= 53 . 41 = 501
= ( 53 . 41 ) : 50
= 6550 : 50
= 131
![](https://rs.olm.vn/images/avt/0.png?1311)
7,923~7,92
17,418~17,42
79,1364~79,14
50,401~50,40
0,155~0,16
60,996~61,00
17.a)c\(\perp\)b
ta có:a//b
a\(\perp\)c \(\Rightarrow\)c\(\perp\)b
Tính C2
a//b
C2 so le trong D1
\(\Rightarrow\)C2=D1=550