OA=(O;2cm)= 2 cm

Nha bn! Chúc bn hok tốt!

 have a big family which gives me the biggest love. My parents have three children, and we also live with our grandparents. Both of my parents are out for work to make sure we have a comfortable life. My father works at the office, and my mother works at the bank. They usually leave early in the morning without having breakfast at home, and my grandmother is the one who cooks for me and my siblings. Our grandparents are still young and very healthy; they take care of us pretty well when our parents are busy. I go to school by my own bike, and my grandfather takes care of my two little brothers. My favorite time of the day is dinner time, because the whole family will all gather after a long day. Seven people with seven stories about their days make the atmosphere become very warm and happy. I know my parents work very hard, so I try my best to become a good daughter and sister. I usually help with the chores, cooking, and looking after my little brothers. I love my family a lot, and I will try harder to keep our happiness lasts forever.

 

As a traditional family in Vietnam, I have a big one. My family has 5 members, including Mom, Dad, Grandma, sister, and me. My mom’s name is Giang. She has long hair and black eyes. She is a teacher. My Dad’s name is Trung. He is tall and very strong. His job is doctor. For me, my mom is the most beautiful woman, and my dad is the most wonderful man. And my grandma’s name is Tam. She is 95 years old, and next 5 years, we will organize the 100th longevity wishing ceremony, and I look forward to taking part in this ceremony. Besides, another woman who I love so much is my sister. Her name is Linh. She is 26 years old, and she is a beautiful woman Mom. Now, she is living in Ha Noi capital, because of her jobs. I really love my family, and I hope that we are always together anyway.

TK CHO MIK NHÉ

GIẢI:

Ta thấy: 25%=\(\frac{1}{4}\)

=> Số HS lớp 6A là một số chia hết cho 4, 2, và 8

=> Số HS lớp 6A thuộc BC (4,2,8)

Mà: BCNN (4,2,8)=8

=> Số HS lớp 6A được chia thành 8 phần đều nhau

=> Số HS giỏi chiếm \(\frac{2}{8}\)số HS lớp 6A, số HS khá chiếm\(\frac{4}{8}\) số HS lớp 6A, số HS trung bình chiếm \(\frac{1}{8}\)số HS lớp 6A

Tổng số phần bằng nhau của số HS giỏi , khá, trung bình là:

\(\frac{2}{8}+\frac{4}{8}+\frac{1}{8}=\frac{7}{8}\)( phần)

Mà số HS yếu là 4 HS

=> Số HS yếu chiếm \(\frac{1}{8}\)số HS cả lớp

a) Số HS lớp 6A là:

4.8= 32 ( HS)

b) Số HS giỏi của lớp 6A là:

4.2=8 ( HS)

Số HS khá của lớp 6A là:

32:2=16 ( HS)

ĐS: a. 32 HS

       b. HS giỏi:8 HS

           HS khá : 16 HS

K CHO MIK NHA

bấm và chữ M ngược là đc

\(S=3+\frac{3}{2}+\frac{3}{2^2}+\frac{3}{2^3}+..\frac{3}{2^{10}}\)

\(\Leftrightarrow2S=6+3+\frac{3}{2}+\frac{3}{2^2}+..\frac{3}{2^9}\)

\(\Leftrightarrow2S-S=6+3+\frac{3}{2}+\frac{3}{2^2}+..\frac{3}{2^9}-3-\frac{3}{2}-\frac{3}{2^2}-\frac{3}{2^3}-...-\frac{3}{2^{10}}\)

\(\Leftrightarrow S=6-\frac{3}{2^{10}}\)

\(\Leftrightarrow S=\frac{6144}{1024}-\frac{3}{1024}\)

\(\Leftrightarrow S=\frac{6141}{1024}\)

1.walks

2.listen

3.love

4.studies

5.is carrying

6.ride

7.is sweeping 

8.use

1. Nina (walk)………walks……………….to school every day.

2. I (listen)…………listen……………………to music every night.

3. They (love)…love…………………..English.

4. He (study)…………studies……………..Information Technology every night.

5. He (carry)……carries………………..a big TV.

6. You (ride)……ride………………a bike every day.

7. They (sweep)…………sweep……………….the floor.

8. I (use)………use………………… this pen to draw.

\(\frac{-3}{5}\)+(\(\frac{-2}{5}\)-99)=-100 nha 

tích giùm cái 

tính ra lun giùm đi mà!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!please!!!!!!!

Các bạn ai sau p/s 1/2009 là dấu= chứ ko phải là dấu cộng nha

sau ps 1/2009 trắng tinh nếu thêm vào đấy chứng minh cái gì bạn ???

Vì A có 20125 số hạng \(\Rightarrow A=\frac{1}{3^2}+\frac{1}{4^2}+\frac{1}{5^2}+...+\frac{1}{20125^2}\)

\(\Rightarrow A< \frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+...+\frac{1}{20124\cdot20125}\)

\(\Rightarrow A< \frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{20124}-\frac{1}{20125}\)

\(\Rightarrow A< \frac{1}{2}-\frac{1}{20125}\Rightarrow A< \frac{1}{2}\) ( ĐPCM )