Ta có:

A=abc + bca + cab

=>A=(100a+10b+c)+(100b+10c+a)+(100c+10a+b)

=>A=100a + 10b + c + 100b + 10c + a + 100c + 10a + b

=>A=111a + 111b + 111c

=>A=111(a+b+c)

giúp mik với mik sắp phải nộp bài rùi

Số đó là 368

3A=\(3+3^2+3^2+...+3^{51}\)
\(3A-A=3^{51}-1\)

\(2A=3^{51}-1\)

\(2A+1=3^{51}\)
Ta có: \(3^{51}+1=3^n+1\Leftrightarrow3^{51}=3^n\Leftrightarrow n=51\)

Ta có:

\(3^{11}< 32^{11}=\left(4.8\right)^{11}=4^{11}.8^{11}=2^{22}.8^{11}\)

\(17^{14}>16^{14}=2^{14}.8^{14}=2^{14}.8^3.8^{11}=2^{14}.2^9.8^{11}=2^{23}.8^{11}\)

Vì \(2^{33}.8^{11}>2^{22}.8^{11}\Rightarrow16^{14}>32^{11}\)

Vậy \(17^{14}>16^{14}>32^{11}>31^{11}\Rightarrow17^{14}>31^{11}\)

12 ml = 12cc

12ml=12cc đúng rồi còn gì

Ta có:

31¹¹ < 32¹¹ = ( 2⁵ )¹¹ = 2⁵⁵

17¹⁴ > 16¹⁴ = ( 2⁴ )¹⁴ = 2⁵⁶

Vì 2⁵⁵ < 2⁵⁶

=> 31¹¹ < 17¹⁴

Hok Tốt~~

1120128

=(5016+912). 37 : 13 : 74

=5928.37 : 13 : 74

=219336 : 13 : 74 

=16872:74

=2410

(456.11+912).37:13:74

= (456.11+912):13:(74:37)

= (456.11+456.2):13:2

= 456.(11+2):13:2

= 456.13:13:2

= (456:2).(13:13)

= 228.1

= 228

42;5;9

\(\left(3^3\right)^{14}:\left(3^4\right)^{10}=3^{42}:3^{40}=3^{42-40}=3^2=9\)

(3³)¹⁴:(3⁴)¹⁰=3⁴²:3⁴⁰⁼3²⁼9