a) \(\frac{2^7}{6^5}\times\frac{9^3}{8^8}=\frac{2^7}{2^5\times3^5}\times\frac{3^6}{2^{24}}=\frac{2^7\times3^6}{2^{29}\times3^5}=\frac{3}{4194304}\)

b) \(\frac{6^3+3\times6^2+3^3}{-13}=\frac{2^3\times3^3+3\times2^2\times3^2+3^3}{-13}=\frac{3^3\left(2^3+2^2+1\right)}{-13}=\frac{27\times13}{-13}=-27\)

\(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}=\frac{\left(0,2\cdot3\right)^5}{\left(0,2\right)^6}=\frac{\left(0,2\right)^5\cdot3^5}{\left(0,2\right)^6}=\frac{3^5}{0,2}=\frac{3}{\frac{2}{10}}=\frac{3\cdot10}{2}=\frac{30}{2}=15\)

\(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}\)

= \(\frac{\left(0,2.3\right)^5}{\left(0,2\right)^6}\)

= \(\frac{\left(0,2\right)^5.3^5}{\left(0,2\right)^6}\)

= \(\frac{3^5}{0,2}\)

=\(\frac{243}{0,2}\)

= 1215

| x - 1 | = 2x

+ Xét x - 1 > = 0 => x > = 1

Ta có :

x - 1 = 2x

x - 2x = 1

   - x   = 1

=> x   = -1 ( không thỏa mãn x > = 1 )

+ Xét x -1 < = 0 => x < = 1

ta có :

- ( x - 1 ) = 2x

- x + 1    = 2x

- x - 2x    = -1

- 3 x        = -1

=> x        = \(\frac{1}{3}\)( thỏa mãn x < =1 )

Vậy x = \(\frac{1}{3}\)

=> \(\orbr{\begin{cases}x-1=2x\\x-1=-2x\end{cases}}\)=>\(\orbr{\begin{cases}x-2x=1\\x+2x=1\end{cases}}\)=>\(\orbr{\begin{cases}-x=1\\3x=1\end{cases}}\)=>\(\orbr{\begin{cases}x=-1\\x=\frac{1}{3}\end{cases}}\)