anh chị giúp em

Gọi số đội viên cần tìm là: a \(\left(a>0,a\in N\cdot\right)\)

\(500< a< 600\)

a chia hết cho 12,18,21 

=> \(a\in BC\left(12,18,21\right)\)

\(BC\left(12;18;21\right)=\left(0;252;504;756\right)\)

Vậy chỉ có 504 thỏa mãn => đội nghi thức đó có 504 đội viên

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\(3A=5+\dfrac{5}{3}+\dfrac{5}{3^2}+...+\dfrac{5}{3^{19}}\)

\(2A=3A-A=5-\dfrac{5}{3^{20}}\)

\(A=\dfrac{5.3^{20}-5}{2.3^{20}}\)

\(-15+8+12+\left(-5\right)\)

\(=-7+12+\left(-5\right)\)

\(=5+\left(-5\right)\)

\(=0\)

-15+8+12+(-5)

= (-15-5)+(8+12)

=-20+20

=0

     A=2+2^2+2^3+...+2^2023

=>2A=   2^2+2^3+...+2^2023+2^2024

=>2A-A= 2^2024-2

        A  =    (...6) - 2

        A  =      (...4)

  Vậy CSTC của A là 4

\(2A=2^2+2^3+2^4+...+2^{2024}\)

\(A=2A-A=2^{2024}-2=\left(2^4\right)^{506}-2\)

\(\left(2^4\right)^{506}\) có chữ số tận cùng là 6

=> A có chữ số tận cùng là 4

\(\dfrac{4}{15}.\dfrac{-7}{10}=-\dfrac{14}{75}\)

\(\dfrac{4}{15}.-\dfrac{7}{10}=-\dfrac{28}{150}=-\dfrac{14}{75}\)

a) \(75:\left(x-2\right)+4=7\)

\(\Rightarrow75:\left(x-2\right)=7-4\)

\(\Rightarrow75:\left(x-2\right)=3\)

\(\Rightarrow x-2=75:3\)

\(\Rightarrow x-2=25\)

\(\Rightarrow x=27\)

b) \(125-3\left(x+3\right)=65\)

\(\Rightarrow3\left(x+3\right)=125-65\)

\(\Rightarrow3\left(x+3\right)=60\)

\(\Rightarrow x+3=60:3\)

\(\Rightarrow x+3=20\)

\(\Rightarrow x=17\)

a,\(75:\left(x-2\right)+4=7\\ \Rightarrow75:\left(x+2\right)=3\\ \Rightarrow x+2=25\\ \Rightarrow x=23.\)

b, \(125-3\left(x+3\right)=65\\ \Rightarrow3\left(x+3\right)=60\\ \Rightarrow x+3=20\\ \Rightarrow x=17.\)

a) \(...=-\dfrac{1}{4}.\dfrac{4}{17}.\left(-\dfrac{63}{21}\right).\left(-\dfrac{7}{12}\right)\)

\(=-\dfrac{1}{17}.\dfrac{63}{21}.\dfrac{7}{12}\)

\(=-\dfrac{7}{68}\)

b) \(...=-\dfrac{2}{5}.\dfrac{4}{15}-\dfrac{3}{10}.\dfrac{4}{15}\)

\(=\dfrac{4}{15}\left(-\dfrac{2}{5}-\dfrac{3}{10}\right)\)

\(=\dfrac{4}{15}\left(-\dfrac{4}{10}-\dfrac{3}{10}\right)\)

\(=\dfrac{4}{15}.\left(-\dfrac{7}{10}\right)=-\dfrac{14}{75}\)

c) \(...=21-\dfrac{15}{4}:\left(\dfrac{9}{24}-\dfrac{4}{24}\right)\)

\(=21-\dfrac{15}{4}:\dfrac{5}{24}\)

\(=21-\dfrac{15}{4}.\dfrac{24}{5}\)

\(=21-3.6=3\)

d) \(...=\left(-\dfrac{3}{4}+\dfrac{2}{5}\right).\dfrac{7}{3}+\left(\dfrac{3}{5}-\dfrac{1}{4}\right).\dfrac{7}{3}\)

\(=\dfrac{7}{3}\left(-\dfrac{3}{4}+\dfrac{2}{5}+\dfrac{3}{5}-\dfrac{1}{4}\right)\)

\(=\dfrac{7}{3}\left(-\dfrac{3}{4}-\dfrac{1}{4}+\dfrac{2}{5}+\dfrac{3}{5}\right)\)

\(=\dfrac{7}{3}\left(-1+1\right)=0\)

a)(-0,25).4/17.(-3 5/21).(-7/12)

= -1/17 . (-68/21) . ( -7/21)

= -4/63

b) (-2/5).4/15+(-3/10).4/15

= 4/15. [-2/5 + (-3/10)]

= 4/15 . (-7/10)

= -14/75

c)21-3 3/4:(3/8-1/6)

= 21 - 15/4 : 5/24

= 21 - 18

= 3

d) (-3/4+2/5):3/7+(3/5+-1/4):3/7

= [(-3/4 + 2/5) + (3/5 + -1/4)] : 3/7

= [-7/20 + (-17/20)] : 3/7

= -6/5 : 3/7

= -14/5