Giúp mình với, mình cần gấp !!!!!!!!!!!! Thanks các bạn nhìu!

a;b thuộc N hay Z

thuộc Z bạn ạ !

đoán xem

\(\left(x^2-x+2\right)^2+\left(x-2\right)^2\)

\(=x^4-2x^3+5x^2-4x+4+x^2-4x+4\)

\(=x^4-2x^3+6x^2-8x+8\)

\(=x^4-2x^3+2x^2+4x^2-8x+8\)

\(=x^2\left(x^2-2x+2\right)+4\left(x^2-2x+2\right)\)

\(=\left(x^2+4\right)\left(x^2-2x+2\right)\)

\(A=\left(\frac{1}{x-1}-\frac{x}{1-x^3}.\frac{x^2+x+1}{x+1}\right):\frac{2x+1}{x^2+2x+1}\)

\(A=\left(\frac{1}{x-1}-\frac{x}{\left(1-x\right)\left(1+x+x^2\right)}.\frac{x^2+x+1}{x+1}\right):\frac{2x+1}{x^2+2x+1}\)

\(A=\left(\frac{1}{x-1}-\frac{x}{\left(1-x\right)\left(x+1\right)}\right):\frac{2x+1}{x^2+2x+1}\)

\(A=\left(\frac{-x-1}{\left(1-x\right)\left(x+1\right)}-\frac{x}{\left(1-x\right)\left(x+1\right)}\right):\frac{2x+1}{x^2+2x+1}\)

\(A=\frac{-2x-1}{\left(1-x\right)\left(x+1\right)}:\frac{2x+1}{x^2+2x+1}\)

\(A=\frac{-\left(2x+1\right)}{\left(1-x\right)\left(x+1\right)}.\frac{\left(x+1\right)^2}{2x+1}\)

\(A=\frac{-1}{1-x}.\frac{x+1}{1}\)

\(A=\frac{-x-1}{1-x}\)

\(x^3+x^2-x+a=\)\(x^2\left(x+2\right)-x\left(x+2\right)+x+a\)\(=\left(x^2-x\right)\left(x+2\right)+a+x\)

mà\(\left(x^2-x\right)\left(x+2\right)⋮x+2\)

\(\Rightarrow a+x⋮x+2\)

\(\Rightarrow a=2\)

mình ko biết xin lỗi bạn nha!

mình ko biết xin lỗi bạn nha!

mình ko biết xin lỗi bạn nha!

mình ko biết xin lỗi bạn nha!