\(4.\left\{3^2\left[\left(5^2+2^3\right):11\right]-26\right\}+2010=4.\left\{3^2\left[\left(25+8\right):11\right]-26\right\}+2010\)

\(4\left\{3^2\left[33:11\right]-26\right\}+2010=4.\left\{3^2.3-26\right\}+2010=4\left\{27-26\right\}+2010\)

\(=4.1+2010=2014\)

\(\left[\left(25-2^2.3\right)+\left(3^2.4+16\right)\right]:5=\left[\left(25-4.3\right)+\left(9.4+16\right)\right]:5\)

\(=\left[\left(25-12\right)+\left(36+16\right)\right]:5=\left[13+52\right]:5=65:5=13\)

\(a,\)\(25+3\left(x-8\right)=106.\)

\(\Rightarrow25+3x-24=106\)

\(\Rightarrow3x+1=106\)

\(\Rightarrow3x=105\)\(\Rightarrow x=35\)

\(b,3^2\left(x+4\right)-5^2=5.22\)

\(\Rightarrow9\left(x+4\right)-25=110\)

\(\Rightarrow9x+36-25=110\)

\(\Rightarrow9x+11=110\)

\(\Rightarrow9x=99\Leftrightarrow x=11\)

\(a,25:3\left(x-8\right)=106\)

\(\Rightarrow25+3x-24=106\)

\(\Rightarrow3x+1=106\)

\(\Rightarrow x=35\)

\(b,3^2\left(x+4\right)-5^2=5.22\)

\(\Rightarrow9x+36-25=110\)

=\(9x+11=110\)

\(\Rightarrow9x=99\)

\(\Rightarrow x=11\)

A=(10²⁰⁰⁰+8)=100..0+8

=> Tổng các chs của A=9 chia hết cho9

200-(2x+6)=4³

^{=>2x-6=200-64=136}

^{=>2x=136+6=142}

^=>x=142/2=71

\(8^{14}:\left(4^4.64^5\right)=2^{42}:\left(2^8.2^{30}\right)=2^{42}:\left(2^{8+30}\right)=2^{42}:2^{38}=2^{42-38}=2^4=16\)

\(\left(9^{10}.27^7\right):\left(81^7.3^{15}\right)=\left(3^{20}.3^{21}\right):\left(3^{28}.3^{15}\right)=\left(3^{20+21}\right)\left(3^{28+15}\right)\)

\(=3^{41}:3^{43}=3^{41-43}=3^{-2}=\frac{1}{9}\)

d. 2^x+2 - 2^x = 96                                                             e. (7x-11)³ = 25 . 5²

=> 2^x.2² - 2^x = 96                                                         => (7x-11)³ = 1000 = 10³  

=> 2^x(2² - 1) = 96                                                         => 7x - 11 = 10

=> 2^x.3 = 2⁵.3                                                               => 7x = 21

=> x = 5                                                                        => x = 3

Câu e đề sai nhé! Mỏi tay ...

d.\(2^{x+2}-2^x=96\) 

  \(2^x\left(2^2-1\right)=96\) 

 \(2^x.3=96\) 

 \(2^x=32=2^5\)

\(\Rightarrow x=5\) 

Vậy.......

e)Đề sai hả bạn ?

\(\left(2x+13\right):5=17\)

\(\Rightarrow2x+13=17.5\)

\(\Rightarrow2x+13=85\)

\(\Rightarrow2x=85-13\)

\(\Rightarrow2x=72\Rightarrow x=\frac{72}{2}=36\)

\(360:\left(11x-7\right)=90\)

\(11x-7=\frac{360}{90}\)

\(\Rightarrow11x-7=4\)

\(\Rightarrow11x=4+7=11\)

\(\Rightarrow x=\frac{11}{11}=1\)

\(30:\left(3x-7\right)=15\)

\(\Rightarrow3x-7=\frac{30}{15}=2\)

\(\Rightarrow3x=2+7=9\)

\(\Rightarrow x=\frac{9}{3}=3\)

a,\(\left(2x+13\right):5=17\)

\(2x+13=17.5\)

\(2x=72\)

\(x=72:2\)

\(x=36\)

b,\(360:\left(11x-7\right)=90\)

\(11x-7=4\)

\(11x=11\)

\(x=1\)

c,\(30:\left(3x-7\right)=15\)

\(3x-7=2\)

\(3x=9\)

\(x=3\)

abc+ab+a=1037

= a x 100 + b x 10 + c + a x 10 + b + a = 1037

= a x 111 + b x 11 + c = 1037

= 9 x 111 + 3 x  11 + 5 = 1037

=> a = 9 ; b = 3 ; c = 5

#)Giải :

abc + ab + a = 1037

=> 100a + 10b + c + 10a + b + a = 1037

=> 111a + 11b + c = 1037

=> a = 1037 : 111 = 9 dư 38

=> b = 38 : 11 = 3 dư 5 

=> c = 5 : 1 = 5 

Vậy a = 9; b = 3; c = 5

Số cần tìm là abc = 935

mình đang cần rất gấp mong các bạn giúp ,ngày mai mình phải nộp cho cô rồi .bạn nào làm nhanh mình k luôn nha

\(\left(x+4\right).\left(-3x+9\right)=\)

\(\Leftrightarrow\orbr{\begin{cases}x+4=0\\-3x+9=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0-4\\-3x=0-9\end{cases}\Leftrightarrow}}\orbr{\begin{cases}x=-4\\-3x=-9\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=-4\\x=\left(-9\right):\left(-3\right)\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-4\\x=3\end{cases}}}\)

Vậy .....................

~ Hok tốt ~

Bạn nào biết làm chỉ mifh với

#)Giải :

\(\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}+\frac{1}{256}+\frac{1}{512}\)

\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+...+\frac{1}{256}-\frac{1}{512}\)

\(=\frac{1}{2}-\frac{1}{512}\)

\(=\frac{255}{512}\)

Lời giải 

\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+...+\frac{1}{256}-\frac{1}{512}\)

\(=\frac{1}{2}-\frac{1}{512}\)

\(=\frac{255}{512}\)