Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{\left(9^{11}.243^5\right)}{\left(81^5.3^{24}\right)}=\frac{9^{11}.\left(3^5\right)^5}{\left(9^2\right)^5.3^{24}}=\frac{9^{11}.3^{25}}{9^{10}.3^{24}}=9.3=27\)
\(\frac{9^3.2^{10}.27^5}{4^5.81^6}=\frac{\left(3^2\right)^3.2^{10}.\left(3^3\right)^5}{\left(2^2\right)^5.\left(3^4\right)^6}=\frac{3^6.2^{10}.3^{15}}{2^{10}.3^{24}}=\frac{3^{21}.2^{10}}{2^{10}.3^{24}}=\frac{1}{3^3}=\frac{1}{27}\)
a,Vì \(\left|x+1\right|\ge0\forall x\in R\)
\(\left|x+2\right|\) .................
\(\left|x+3\right|\) .................
\(\Rightarrow\left|x+1\right|+\left|x+2\right|+\left|x+3\right|\ge0\forall x\in R\)
=> \(2x\ge0\forall x\in R\Leftrightarrow x\ge0\)
\(\Rightarrow x+1+x+2+x+3=2x\)
\(3x+6=2x\)
\(\Rightarrow x=-6\)
Vậy.............
b) Vì \(\left|x+1\right|\ge0\forall x\in R\)
\(\left|x+2\right|\ge0\forall x\in R\)
\(\Rightarrow\left|x+1\right|+\left|x+2\right|\ge0\forall x\in R\)
=> \(x\ge0\)
\(\Rightarrow x+1+x+2=x\)
\(2x+3=x\)
\(x=-3\)
Vậy x=3
hc tốt
\(4.\left\{3^2\left[\left(5^2+2^3\right):11\right]-26\right\}+2010=4.\left\{3^2\left[\left(25+8\right):11\right]-26\right\}+2010\)
\(4\left\{3^2\left[33:11\right]-26\right\}+2010=4.\left\{3^2.3-26\right\}+2010=4\left\{27-26\right\}+2010\)
\(=4.1+2010=2014\)
\(\left[\left(25-2^2.3\right)+\left(3^2.4+16\right)\right]:5=\left[\left(25-4.3\right)+\left(9.4+16\right)\right]:5\)
\(=\left[\left(25-12\right)+\left(36+16\right)\right]:5=\left[13+52\right]:5=65:5=13\)
\(a,\)\(25+3\left(x-8\right)=106.\)
\(\Rightarrow25+3x-24=106\)
\(\Rightarrow3x+1=106\)
\(\Rightarrow3x=105\)\(\Rightarrow x=35\)
\(b,3^2\left(x+4\right)-5^2=5.22\)
\(\Rightarrow9\left(x+4\right)-25=110\)
\(\Rightarrow9x+36-25=110\)
\(\Rightarrow9x+11=110\)
\(\Rightarrow9x=99\Leftrightarrow x=11\)
\(a,25:3\left(x-8\right)=106\)
\(\Rightarrow25+3x-24=106\)
\(\Rightarrow3x+1=106\)
\(\Rightarrow x=35\)
\(b,3^2\left(x+4\right)-5^2=5.22\)
\(\Rightarrow9x+36-25=110\)
=\(9x+11=110\)
\(\Rightarrow9x=99\)
\(\Rightarrow x=11\)
A=(102000+8)=100..0+8
=> Tổng các chs của A=9 chia hết cho9
200-(2x+6)=43
=>2x-6=200-64=136
=>2x=136+6=142
=>x=142/2=71
\(8^{14}:\left(4^4.64^5\right)=2^{42}:\left(2^8.2^{30}\right)=2^{42}:\left(2^{8+30}\right)=2^{42}:2^{38}=2^{42-38}=2^4=16\)
\(\left(9^{10}.27^7\right):\left(81^7.3^{15}\right)=\left(3^{20}.3^{21}\right):\left(3^{28}.3^{15}\right)=\left(3^{20+21}\right)\left(3^{28+15}\right)\)
\(=3^{41}:3^{43}=3^{41-43}=3^{-2}=\frac{1}{9}\)
d. 2x+2 - 2x = 96 e. (7x-11)3 = 25 . 52
=> 2x.22 - 2x = 96 => (7x-11)3 = 1000 = 103
=> 2x(22 - 1) = 96 => 7x - 11 = 10
=> 2x.3 = 25.3 => 7x = 21
=> x = 5 => x = 3
Câu e đề sai nhé! Mỏi tay ...
d.\(2^{x+2}-2^x=96\)
\(2^x\left(2^2-1\right)=96\)
\(2^x.3=96\)
\(2^x=32=2^5\)
\(\Rightarrow x=5\)
Vậy.......
e)Đề sai hả bạn ?
\(\left(2x+13\right):5=17\)
\(\Rightarrow2x+13=17.5\)
\(\Rightarrow2x+13=85\)
\(\Rightarrow2x=85-13\)
\(\Rightarrow2x=72\Rightarrow x=\frac{72}{2}=36\)
\(360:\left(11x-7\right)=90\)
\(11x-7=\frac{360}{90}\)
\(\Rightarrow11x-7=4\)
\(\Rightarrow11x=4+7=11\)
\(\Rightarrow x=\frac{11}{11}=1\)
\(30:\left(3x-7\right)=15\)
\(\Rightarrow3x-7=\frac{30}{15}=2\)
\(\Rightarrow3x=2+7=9\)
\(\Rightarrow x=\frac{9}{3}=3\)
a,\(\left(2x+13\right):5=17\)
\(2x+13=17.5\)
\(2x=72\)
\(x=72:2\)
\(x=36\)
b,\(360:\left(11x-7\right)=90\)
\(11x-7=4\)
\(11x=11\)
\(x=1\)
c,\(30:\left(3x-7\right)=15\)
\(3x-7=2\)
\(3x=9\)
\(x=3\)
abc+ab+a=1037
= a x 100 + b x 10 + c + a x 10 + b + a = 1037
= a x 111 + b x 11 + c = 1037
= 9 x 111 + 3 x 11 + 5 = 1037
=> a = 9 ; b = 3 ; c = 5
