giúp mình giải bài này với
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c= 2017
a + b + 2017 = 2018
a - b + 2017 = 2019.
...........
f(2 ) = 4 a + 2 b + 2017
Cách làm bài 4 b giống 4 a là bỏ trị tuyệt đối , bạn có 2 số
đáp số bài 4 b
x = 3/20 hay x = - 7/20
\(\dfrac{2x}{3}\) = \(\dfrac{3y}{4}\) = \(\dfrac{4z}{5}\) và x + y + z = 4
\(\dfrac{12x}{18}\) = \(\dfrac{12y}{16}\) = \(\dfrac{12y}{15}\)= \(\dfrac{12x+12y+12z}{18+16+15}\)= \(\dfrac{12\left(x+y+z\right)}{49}\)= \(\dfrac{12.4}{49}\) =\(\dfrac{48}{49}\)
x = \(\dfrac{48}{49}\): \(\dfrac{12}{18}\)= \(\dfrac{72}{49}\), y = \(\dfrac{48}{49}\): \(\dfrac{12}{16}\) = \(\dfrac{64}{49}\), z = \(\dfrac{48}{49}\): \(\dfrac{12}{15}\) = \(\dfrac{60}{49}\)
1\(\dfrac{2}{3}\): x = - \(\dfrac{4}{3}\)
\(\dfrac{5}{3}\): X = \(\dfrac{-4}{3}\)
X = \(\dfrac{5}{3}\) : \(\dfrac{-4}{3}\)
X = \(\dfrac{5}{3}\) . \(\dfrac{-3}{4}\)
X = \(\dfrac{-5}{4}\)
-\(\dfrac{2}{7}\) . X = \(\dfrac{-1}{4}\)
X = \(\dfrac{-1}{4}\) : \(\dfrac{-2}{7}\)
X = \(\dfrac{1}{4}\) . \(\dfrac{7}{2}\)
X = \(\dfrac{7}{8}\)
- \(\dfrac{2}{7}\).X = - \(\dfrac{-1}{4}\)
X = \(\dfrac{-1}{4}\) : \(\dfrac{-2}{7}\)
X = \(\dfrac{1}{4}\) . \(\dfrac{7}{2}\)
X = \(\dfrac{7}{8}\)
x - 1\(\dfrac{1}{3}\) = 2
X - \(\dfrac{4}{3}\) = 2
X = 2 + \(\dfrac{4}{3}\)
X = \(\dfrac{10}{3}\)
\(x-1\dfrac{1}{3}=2\)
\(x-\dfrac{4}{3}=2\)
\(x=2+\dfrac{4}{3}\)
\(x=\dfrac{10}{3}\)
x + 1,5 = \(\dfrac{5}{3}\)
x = \(\dfrac{5}{3}\) - 1,5
x = \(\dfrac{5}{3}\) - \(\dfrac{3}{2}\)
x = \(\dfrac{10}{6}\) - \(\dfrac{9}{6}\)
x = \(\dfrac{1}{6}\)
\(x+1,5=\dfrac{5}{3}\)
\(x+\dfrac{3}{2}=\dfrac{5}{3}\)
\(x=\dfrac{5}{3}-\dfrac{3}{2}\)
\(x=\dfrac{1}{6}\)