muốn biết thì tra goolge bằng 260/100

\(\frac{4}{3x}+\frac{3}{4\left(2x-\frac{4}{5}\right)}=\frac{1}{2}\left(đkxđ:x\ne0;\frac{2}{5}\right)\)

\(< =>\frac{4}{3x}+\frac{3}{8x-\frac{16}{5}}=\frac{1}{2}\)

\(< =>\frac{4\left(8x-\frac{16}{5}\right)}{3x\left(8x-\frac{16}{5}\right)}+\frac{3\left(3x\right)}{\left(8x-\frac{16}{5}\right)3x}=\frac{1}{2}\)

\(< =>\frac{32x-\frac{64}{5}+9x}{24x^2-\frac{48x}{5}}=\frac{1}{2}\)

\(< =>\left(41x-\frac{64}{5}\right)2=24x^2-\frac{48x}{5}\)

\(< =>82x-\frac{128}{5}=24x^2-\frac{48x}{5}\)

\(< =>24x^2-82x-\frac{48x}{5}+\frac{128}{5}=0\)

\(< =>24x^2-x\left(82+\frac{48}{5}\right)+\frac{128}{5}=0\)

\(< =>\orbr{\begin{cases}x_1=-0,3036\\x_2=-3,513\end{cases}}\)(giải delta)

Vậy tập nghiệm của phương trình trên là \(\left\{-0,3036;-3,513\right\}\)

\(\frac{4}{3}x+\frac{3}{4}\left[2x-\frac{4}{5}\right]=\frac{1}{2}\)

\(\Leftrightarrow\frac{4}{3}x+\frac{3}{2}x-\frac{3}{5}=\frac{1}{2}\)

\(\Leftrightarrow\frac{17}{6}x=\frac{11}{10}\)

\(\Leftrightarrow x=\frac{187}{60}\)

\(=-|\frac{1}{12}|-\frac{25}{36}.\frac{-16}{3}\)

\(=-\frac{1}{12}-\left(-\frac{100}{27}\right)\)

\(=-\frac{1}{12}+\frac{100}{27}\)

\(=\frac{391}{108}\)

Bài làm

\(2x-\frac{5}{6}=\frac{1}{3}\)

\(\Rightarrow2x=\frac{1}{3}+\frac{5}{6}\)

\(\Rightarrow2x=\frac{2}{6}+\frac{5}{6}\)

\(\Rightarrow2x=\frac{7}{6}\)

\(\Rightarrow x=\frac{7}{6}:2\)

\(\Rightarrow x=\frac{7}{6}.\frac{1}{2}\)

\(\Rightarrow x=\frac{7}{12}\)

Vậy \(x=\frac{7}{12}\)

\(2x-\frac{5}{6}=\frac{1}{3}\)

\(2x=\frac{7}{6}\)

\(x=\frac{7}{6}:2\)

\(x=\frac{7}{12}\)

Vậy \(x=\frac{7}{12}\)