5x = 625
3.2 x = 96
8 x + 1 = 16 5
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\(9^{70}=\left(9^{70}\right)^5=9^{350}\)
\(29^{50}=\left(29^{50}\right)^7=29^{350}\)
\(=>9^{70}< 29^{50}\)
\(a,25^3:5^2=5^{2^3}:5^2=5^6:5^2=5^4=625\)
\(b,\frac{390^4}{130^4}=\left(\frac{390}{130}\right)^4=3^4=81\)
\(c,32^4:4^3=2^{5^4}:2^{2^3}=2^{20}:2^6=2^{14}\)
TÌM X
a,\(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\)
b, \(\left(x-\frac{1}{2}\right)^2=\frac{4}{25}\)
\(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}=\left(\frac{1}{3}\right)^3\)
\(\Leftrightarrow x-\frac{1}{2}=\frac{1}{3}\)
\(\Leftrightarrow x=\frac{1}{3}+\frac{1}{2}\)
\(\Leftrightarrow x=\frac{5}{6}\)
Bài làm
a) \(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\) b) \(\left(x-\frac{1}{2}\right)^2=\frac{4}{25}\)
=> \(\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\) => \(\left(x-\frac{1}{2}\right)^2=\left(\frac{2}{5}\right)^2\)
=> \(x-\frac{1}{2}=\frac{1}{3}\) => \(x-\frac{1}{2}=\frac{2}{5}\)
\(x=\frac{1}{3}+\frac{1}{2}\) \(x=\frac{2}{5}+\frac{1}{2}\)
\(x=\frac{2}{6}+\frac{3}{6}\) \(x=\frac{4}{10}+\frac{5}{10}\)
\(x=\frac{5}{6}\) \(x=\frac{9}{10}\)
Vậy \(x=\frac{5}{6}\) Vậy \(x=\frac{9}{10}\)
# Chúc bạn học tốt #
a) 3 - (-6/7)0 + (1/2)2 : 2
= 3 + 1 + 1/4 : 2
= 3 + 1 + 1/8
= 33/8
b) (-2)3 + 22 + (-1)20 + (-2)0
= (-8) + 4 - 1 - 1
= -6
c) [(3)2]2 - [(-5)2]2 - [(-2)3]2
= 81 - 625 - 64
= -608
d) 24 + 8.[(-2)2 : 1/2]0 - 2-2.4 + (-2)2
= 16 + 8.1 - 1/4.4 + 4
= 16 + 8 - 4 + 4
= 27
e) 23 + 3.(1/2)0 - 2-2.4 + [(-2)2 : 1/2].8
= 8 + 3 - 1/4.4 + 8.8
= 8 + 3 - 1 + 64
= 74
5x = 625
=> 5x = 54
=> x = 4
3 . 2x = 96
=> 2x = 96 : 3
=> 2x = 32
=> 2x = 25
=> x = 5
c) 8x + 1 = 165
=> (23)x + 1 = (24)5
=> 23(x + 1) = 24.5
=> 23(x + 1) = 220
=> 3(x + 1) = 20
=> x + 1 = 20:3
=> x + 1 = 20/3
=> x = 20/3 - 1
=> x = 17/3
1) 5x = 625
<=. 5x = 54
<=> x = 4
=> x = 4
2) 3.2x = 96
<=> 2x = 96 : 3
<=> 2x = 32
<=> 2x = 25
<=> x = 5
=> x = 5
3) 8x + 1 = 165
<=> (23)x + 1 = (24)5
<=> 23.(x + 1) = 24.5
<=> 3.(x + 1) = 4.5
<=> 3.(x + 1) = 20
<=> x + 1 = 20 : 3
<=> x + 1 = 20/3
<=> x = 20/3 - 1
<=> x = 17/3
=> x = 17/3