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\(\frac{x+10}{2008}+\frac{x+9}{2009}=\frac{x+8}{2010}+\frac{x+7}{2011}\)
\(\left(\frac{x+10}{2008}+1\right)+\left(\frac{x+9}{2009}+1\right)=\left(\frac{x+8}{2010}+1\right)+\left(\frac{x+7}{2011}+1\right)\)
\(\frac{x+2018}{2008}+\frac{x+2018}{2009}=\frac{x+2018}{2010}+\frac{x+2018}{2011}\)
\(\frac{x+2018}{2008}+\frac{x+2018}{2009}-\frac{x+2018}{2010}-\frac{x+2018}{2011}=0\)
\(x+2018\cdot\left(\frac{1}{2008}+\frac{1}{2009}-\frac{1}{2010}-\frac{1}{2011}\right)=0\)
mà \(\left(\frac{1}{2008}+\frac{1}{2009}-\frac{1}{2010}-\frac{1}{2011}\right)\ne0\)
\(\Rightarrow x+2018=0\)
\(\Rightarrow x=-2018\)
Vậy,.............
Ta có: \(\frac{x+10}{2008}+\frac{x+9}{2009}=\frac{x+8}{2010}+\frac{x+7}{2011}\)
\(\Rightarrow\frac{x+10}{2008}+1+\frac{x+9}{2009}+1=\frac{x+8}{2010}+1+\frac{x+7}{2011}+1\)
\(\Rightarrow\frac{x+2018}{2008}+\frac{x+2018}{2009}=\frac{x+2018}{2010}+\frac{x+2018}{2011}\)
\(\Rightarrow\frac{x+2018}{2008}+\frac{x+2018}{2009}-\frac{x+2018}{2010}-\frac{x+2018}{2011}=0\)
\(\Rightarrow x+2018\cdot\left(\frac{1}{2008}+\frac{1}{2009}-\frac{1}{2010}-\frac{1}{2011}\right)=0\)
Do \(\frac{1}{2008}+\frac{1}{2009}-\frac{1}{2010}-\frac{1}{2011}\ne0\)
\(\Rightarrow x+2018=0\)
\(\Rightarrow x=-2018\)
Vậy \(x=-2018\)
3^2.1/243.81^2.1/3^2
=9/243.81^2/3^2
=1/27.27^2/1
=27^2/27
=27
Xem anh thể hiện đây mấy em:
Ta có: 2x=3y
=> x/3 =y/2. Áp dụng tính chất dãy tỉ số bằng nhau ta có:
x/3 =y/2 =x+y/3+2= 180/5=36
=> x= 36x3=108
y= 36x2=72
Ti ck bố nha con :V
a) (2x-3)15 = (2x-3)7
=> (2x-3)15 - (2x-3)7 = 0
(2x-3)7.[(2x-3)8 -1] = 0
=> (2x-3)7 = 0 => 2x-3 = 0 => 2x = 3 => x = 3/2
(2x-3)8 - 1 = 0 => (2x-3)8 = 1 => 2x - 3 = 1 => 2x = 4 => x = 2
=> 2x - 3 = - 1 => 2x = 2 => x = 1
KL:...
b) ta có: \(\left(x-3\right)^{16}\ge0;\left(3y-5\right)^4\ge0.\)
Để (x-3)16 + (3y-5)4 = 0
=> (x-3)16 = 0 => x-3 = 0 => x = 3
(3y-5)4 = 0 => 3y - 5 = 0 => 3y = 5 => y = 5/3
KL:...
\(\frac{x-3}{x-5}\)\(=\frac{5}{7}\)
\(\Rightarrow\frac{x}{x}\)\(=\frac{5-3}{7-5}\)
\(\Rightarrow\frac{x}{x}\) \(=\frac{2}{2}\)
Vậy \(x=2\)
\(\frac{x-3}{x-5}=\frac{5}{7}\)
<=> (x - 3) . 7 = (x - 5) . 5
<=> 7x - 21 = 5x - 25
<=> 7x = 5x - 25 + 21
<=> 7x = 5x - 4
<=> 7x = 5x - 4 - 5x
<=> 2x = -4
<=> x = -4 : 2
<=> x = -2
=> x = -2
\(\left(x+2\right)^3=125=5^3\)
\(\Rightarrow x+2=5\)
\(\Rightarrow x=3\)
Vậy,...........
\(5\cdot2^x+4\cdot2^x=72\)
\(2^x\cdot\left(5+4\right)=72\)
\(2^x=72\div9\)
\(2^x=8=2^3\)
\(\Rightarrow x=3\)
5.\(2^x\)+4.\(2^x\)=72
(=)\(2^x\).(5+4)=72
(=)\(2^x\)=8
(=)\(2^x=2^3\)
=>x=3
a) \(10^6-5^7\)
\(=2^6\cdot5^6-5^6\cdot5\)
\(=5^6\cdot\left(2^6-5\right)\)
\(=5^6\cdot59⋮59\)
b) Ko hiểu đề, bạn viết cẩn thận đc k ?
ta có: 106 - 57 = (5.2)6 - 57 = 56.26 - 57
= 56.(2^6 - 5)
= 5^6.59 chia hết cho 59
...