\(A=1+2^1+2^2+2^3+...+2^{2021}\\2A=2+2^2+2^3+2^4+...+2^{2022}\\2A-A=(2+2^2+2^3+2^4+...+2^{2022})-(1+2^1+2^2+2^3+...+2^{2021})\\A=2^{2022}-1\\\Rightarrow A+1=2^{2022}\)

Mặt khác: \(2^x=A+1\)

\(\Rightarrow 2^x=2^{2022}\\\Rightarrow x=2022(tm)\)

Vậy x = 2022.

`#3107.101107`

a,

\([(6.x - 39) \div3] .28 =5628\)

`\Rightarrow (6x - 39) \div 3 = 5628 \div 28`

`\Rightarrow (6x - 39) \div 3 = 201`

`\Rightarrow 6x - 39 = 201 . 3`

`\Rightarrow 6x - 39 = 603`

`\Rightarrow 6x = 42`

`\Rightarrow x = 42 \div 6`

`\Rightarrow x = 7`

Vậy, `x = 7`

b,

`5(7x - 45) = 2^3 . 5^2 - 3^2 . 20`

`\Rightarrow 5(7x - 45) = 8.5.5 - 9.4.5`

`\Rightarrow 5(7x - 45) = 5.(8.5 - 9.4)`

`\Rightarrow 5(7x - 45) = 5.(40 - 36)`

`\Rightarrow 7x - 45 = 5.(40 - 36) \div 5`

`\Rightarrow 7x - 45 = 4`

`\Rightarrow 7x = 49`

`\Rightarrow x = 7`

Vậy, `x = 7.`

`#3107.101107`

a,

`2x + 3x = 5^7 \div 5^5`

$\Rightarrow (2 + 3)x = 5^{7 - 5}$

$\Rightarrow 5x = 5^2$

$\Rightarrow 5x = 25$

$\Rightarrow x = 25 \div 5$

$\Rightarrow x = 5$

Vậy, `x = 5`

b,

`5(7x - 45) = 2^3 . 5^2 - 3^2 . 20`

`\Rightarrow 5(7x - 45) = 8.25 - 9.20`

`\Rightarrow 5(7x - 45) = 40.5 - 36.5`

`\Rightarrow 5(7x - 45) = 5.(40 - 36)`

`\Rightarrow 5(7x - 45) = 5.4`

`\Rightarrow 7x - 45 = 4`

`\Rightarrow 7x = 49`

`\Rightarrow x = 49 \div 7`

`\Rightarrow x = 7`

Vậy, `x = 7.`

A) (2+3).x=5 mũ 2

 5.x=5 mũ 2

5.x=25

x=25:5

x=5 

vậy x=5 

câu B ko bt làm bn ạ

Trả lời giúp mình ik

`#3107.101107`

`(5x - 1)(2x - 6) = 0`

\(\Rightarrow\left[{}\begin{matrix}5x-1=0\\2x-6=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}5x=1\\2x=6\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=3\end{matrix}\right.\)

Vậy, \(x\in\left\{3;\dfrac{1}{5}\right\}.\)

(5x-1).(2x-6) = 0
5x-1 = 0 hoặc 2x-6 = 0
+) 5x-1 = 0 suy ra x = 0,2
+) 2x-6 = 0 suy ra x = 6
Vậy x = 0,2 ; x = 6.

`#3107.101107`

a,

$2014^{15} . (2x - 60) = 2014^{16}$

$\Rightarrow 2x - 60 = 2014^{16} \div 2014^{15}$

$\Rightarrow 2x - 60 = 2014$

$\Rightarrow 2x = 2074$

$\Rightarrow x = 1037$

Vậy, `x = 1037`

b,

`x + 18 \div 3^2 = 5.4^2`

`\Rightarrow x + 18 \div 9 = 5.16`

`\Rightarrow x + 9 = 80`

`\Rightarrow x = 80 - 9`

`\Rightarrow x = 71`

Vậy, `x = 71`

c,

`7.(42 - x) = 5^3 + 134`

`\Rightarrow 7.(42 - x) = 125 + 134`

`\Rightarrow 7(42 - x) = 259`

`\Rightarrow 42 - x = 259 \div 7`

`\Rightarrow 42 - x = 37`

`\Rightarrow x = 42 - 37`

`\Rightarrow x = 5`

Vậy, `x = 5.`

`#3107.101107`

\(A=1+2+2^2+2^3+...+2^{49}+2^{50}\)

\(2A=2+2^2+2^3+...+2^{50}+2^{51}\)

\(2A-A=\left(2+2^2+2^3+...+2^{51}\right)-\left(1+2+2^2+...+2^{50}\right)\)

\(A=2+2^2+2^3+...+2^{51}-1-2-2^2-...-2^{50}\)

\(A=2^{51}-1\)

Vậy, \(A=2^{51}-1.\)

Mình cần gấp 

5^2\(x+1\)  + 3¹ = 128

5^\(2x+1\)  + 3 = 128

5^{\(^{2x+1}\)}     = 128 - 3

5\(^{2x+1}\)   = 125

5\(^{2x+1}\)   = 5³

2\(x\) + 1 = 3

2\(x\)       = 3 - 1

2\(x\)       =   2

 \(x\)        = 2: 2

 \(x\)        = 1

Gọi ƯCLN ( 2n + 3; 3n + 2 ) là d

=> 2n + 3 $⋮$d => 6n + 9 $⋮$d

=> 3n + 2 $⋮$d => 6n + 4 $⋮$d

Vì 2 biểu thức cùng chia hết cho d

=> 6n + 9 - 6n - 4 $⋮$d

hay 5 $⋮$d

Mà d lớn nhất => d = 5

Vậy..............☺