Toán nâng cao 6
So sánh :
a) A= \(\frac{20}{39}\)+ \(\frac{22}{27}\)+\(\frac{18}{43}\) B= \(\frac{14}{39}\)+\(\frac{22}{29}\)+ \(\frac{18}{41}\)
b) A= \(\frac{1+5+5^2+5^3+5^4+...+5^9}{1+5+5^2+...+5^8}\)
B= \(\frac{1+3+3^2+3^3+...+3^9}{1+3+3^2+...+3^8}\)