Ta có: \(x^3-6x^2+12x-8=\left(2x+1\right)^3\)

=>\(\left(x-2\right)^3=\left(2x+1\right)^3\)

=>2x+1=x-2

=>2x-x=-2-1

=>x=-3

x^3 - 6x^2 + 12x - 8 = (2x + 1)^3

→ (x - 2)^3 = (2x + 1)^3

→ x - 2 = 2x + 1

→ -x = 3

→ x = -3

Vậy x = -3.

9987 - 1262 : 5

= 9987 - 252,4

= 9734,6

9734 .6

170 - (52 - x/5) = 133

⇔ 52 - x/5 = 170 - 133

⇔ 52 - x/5 = 37

⇔ x/5 = 52 - 37

⇔ x/5 = 15

⇔ x = 15 * 5

⇔ x = 75

Vậy x = 75.

170-(52-x:5)=133

⇒52-x:5=170-133

⇒52-x:5=37

⇒x:5=52-37

⇒x:5=15

⇒x=15*5

⇒x=75

vậy x=75

(2x - 16) . 2024 = 188 . 2024

⇒ 2x - 16 = 188

2x = 188 + 16

2x = 204

x = 204 : 2

x = 102

(2x - 16) * 2024 = 188 * 2024

⇔ 2x - 16 = 188

⇔ 2x = 188 + 16

⇔ 2x = 204

⇔ x = 204 / 2

⇔ x = 102

Vậy x = 102.

Ta có :

(x+3)^4=4*(x+3)^3

hay (x+3)^4-4*(x+3)^3=0

(x+3)^3*(x+3−4)=0

(x+3)^3*(x−1)=0

TH1: x+3=0⇒x=−3

TH2: x−1=0⇒x=1

Vậy x=-3 hoặc x=1

(3+x)^4 = 4*(x+3)^3

(3+x)^3 * [(3+x) - 4] = 0

(3+x)^3 * (x - 1) = 0

x = -3 hoặc x = 1

\(\frac{5}{2x}-3=\frac{1}{x}\)

\(\frac{5}{2x}-\frac{1}{x}=3\)

\(\frac{5}{2x}-\frac{2}{2x}=3\)

\(\frac{3}{2x}=3\)

\(\frac{1}{2x}=\frac11\)

\(2x=1\)

\(x=\frac12\)

vậy x = \(\frac12\)

5/2.x - 3 = 1/x

⇔ 5x² - 6x = 2

⇔ 5x² - 6x - 2 = 0

Giải phương trình bậc 2:

x = (3 ± √19) / 5

Vậy x = (3 + √19) / 5 hoặc x = (3 - √19) / 5.

\(-\frac57-\left(-\frac{3}{21}\right)\)

\(=-\frac57+\frac{3}{21}\)

\(=-\frac{15+3}{21}\)

\(=-\frac{12}{21}=-\frac47\)

\(\frac{5}{-7}-\frac{-3}{21}\)

\(=\frac{-5}{7}-\frac{-3}{21}\)

\(=\frac{-105}{147}-\frac{-21}{147}\)

\(=\frac{-105-\left(-21\right)}{147}\)

\(=\frac{-105+21}{147}\)

\(=\frac{-84}{147}\)

\(=\frac{-4}{7}\)

\(\left(\frac17\right)^{x+1}\) \(=\frac{1}{49}\)

\(\left(\frac17\right)^{x+1}\) \(=\left(\frac17\right)^2\)

\(x+1=2\)

\(x=2-1\)

\(x=1\)

LMV gamer ơi, cậu thông minh thế

\(\frac{-30}{17}:\frac{-15}{-34}\)

\(=-\frac{30}{17}:\frac{15}{34}\)

\(=-\frac{30}{17}\cdot\frac{34}{15}=-\frac{34}{17}\cdot\frac{30}{15}=-2\cdot2=-4\)

\(\frac{-30}{17}:\frac{-15}{-34}\)

\(=\frac{-30}{17}:\frac{15}{34}\)

\(=\frac{-30}{17}.\frac{34}{15}\)

\(=\frac{-1020}{255}\)

\(=-4\)

\(\left(\frac{x}{7}+0,25\right)=\frac{-1}{28}\)

\(\frac{x}{7}+0,25=\frac{-1}{28}\)

\(\) \(\frac{x}{7}=\frac{-1}{28}-0,25\)

\(\frac{x}{7}=\frac{-2}{7}\)

\(x=2\)

Vậy \(x=2\)

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