3/5.5/7+3/7:5/3-1/7:5/3
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a) A = 124125+(−1815+1125)+315124125+(−1815+1125)+315
= (124125+1125)+(−1815++315)(124125+1125)+(−1815++315)
= 124+1125+−18+315124+1125+−18+315
= 1 + (-1)
= 0
b) B = (19−517)+36+(−1217+−12)+59(19−517)+36+(−1217+−12)+59
= (19+59)+(−1217−517)+(36+−12)(19+59)+(−1217−517)+(36+−12)
= 1+59+−12−5−17+1+(−1)21+59+−12−5−17+1+(−1)2
= 23−1+023−1+0
= −1 3 like đê
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`500 - {5.[409 - (2^3 . 3 - 21)^3 ] - 1724}`
`=500 - {5.[409 - (8.3-21)^3 ] - 1724}`
`=500- {5 . [409 - (24-21)^3 ] - 1724}`
`=500 - {5 .[409 - 3^3] - 1724}`
`=500 - {5.382 - 1724}`
`=500 - {1910 - 1724}`
`=500 - 186`
`=314`
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`375 : { 32 - [4 + ( 5.3^2 - 42)]} -14`
`=375 :{ 32 - [4 + ( 5 . 9 - 42)]} -14`
`=375 : { 32 - [4 + (45-42)]}-14`
`=375 :{32-[4+3]}-14`
`=375 : 25-14`
`=15-14`
`=1`
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\(\dfrac{3}{5}.\dfrac{5}{7}+\dfrac{3}{5}:\dfrac{5}{3}-\dfrac{1}{7}:\dfrac{5}{3}\)
= \(\dfrac{3}{5}.\dfrac{5}{7}-\dfrac{3}{7}.\dfrac{3}{5}-\dfrac{1}{7}.\dfrac{3}{5}\)
=\(\dfrac{3}{5}.\left(\dfrac{5}{7}+\dfrac{3}{7}-\dfrac{1}{7}\right)\)
=\(\dfrac{3}{5}.1\)
=\(\dfrac{3}{5}\)