Cần gấp ạ
1, 6/7 . 8/13+6/13.9/7-3/13.6/7
2, 3/11.7/9+17/11.3/19-3/19.25/11
3, 5/7.-2/11+5/7.9/11-5/7
4, 3/13.15/11+3/11.7/13-3/13
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-57.(75 - 36) - 75.(36 - 57)
= -57.75 + 57.36 - 75.36 + 75.57
= (-57.75 + 75.57) +36.(57 - 75)
= 0 + 36.(-18)
= -648
1) \(\dfrac{6}{7}\cdot\dfrac{8}{13}+\dfrac{6}{13}\cdot\dfrac{9}{7}-\dfrac{3}{13}\cdot\dfrac{6}{7}\)
\(=\dfrac{6}{7}\cdot\dfrac{8}{13}+\dfrac{9}{13}\cdot\dfrac{6}{7}-\dfrac{3}{13}\cdot\dfrac{6}{7}\)
\(=\dfrac{6}{7}\cdot\left(\dfrac{8}{13}+\dfrac{9}{13}-\dfrac{3}{13}\right)\)
\(=\dfrac{6}{7}\cdot\dfrac{14}{13}\)
\(=\dfrac{12}{13}\)
2) \(\dfrac{3}{11}\cdot\dfrac{7}{9}+\dfrac{17}{11}\cdot\dfrac{3}{19}-\dfrac{3}{19}\cdot\dfrac{25}{11}\)
\(=\dfrac{7}{33}+\dfrac{3}{19}\cdot\left(\dfrac{17}{11}-\dfrac{25}{11}\right)\)
\(=\dfrac{7}{33}+\dfrac{3}{19}\cdot\dfrac{-8}{11}\)
\(=\dfrac{7}{33}+\dfrac{-24}{209}\)
\(=\dfrac{61}{627}\)
3) \(\dfrac{5}{7}\cdot\dfrac{-2}{11}+\dfrac{5}{7}\cdot\dfrac{9}{11}-\dfrac{5}{7}\)
\(=\dfrac{5}{7}\cdot\left(\dfrac{-2}{11}+\dfrac{9}{11}-1\right)\)
\(=\dfrac{5}{7}\cdot-\dfrac{4}{11}\)
\(=\dfrac{-20}{77}\)
4) \(\dfrac{3}{13}\cdot\dfrac{15}{11}+\dfrac{3}{11}\cdot\dfrac{7}{13}-\dfrac{3}{13}\)
\(=\dfrac{3}{13}\cdot\dfrac{15}{11}+\dfrac{7}{11}\cdot\dfrac{3}{13}-\dfrac{3}{13}\)
\(=\dfrac{3}{13}\cdot\left(\dfrac{15}{11}+\dfrac{7}{11}-1\right)\)
\(=\dfrac{3}{13}\cdot\left(\dfrac{22}{11}-1\right)\)
\(=\dfrac{3}{13}\cdot1\)
\(=\dfrac{3}{13}\)
Lời giải:
Ta có:
\(\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{2021^2}+\frac{1}{2022^2}<\underbrace{ \frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2021.2022}}_{M}\)
\(M=\frac{2-1}{1.2}+\frac{3-2}{2.3}+\frac{4-3}{3.4}+...+\frac{2022-2021}{2021.2022}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2021}-\frac{1}{2022}=1-\frac{1}{2022}<1\)
\(\Rightarrow \frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{2021^2}+\frac{1}{2022^2}< M< 1\)
Ta có đpcm.
Lời giải:
\(A=\frac{10^{2021}+1}{10^{2020}+1}=\frac{10(10^{2020}+1)-9}{10^{2020}+1}=10-\frac{9}{10^{2020}+1}<10-\frac{9}{10^{2021}+1}=\frac{10^{2022}+1}{10^{2021}+1}=B\)
Vậy $A<B$
-3/7 + 17/26 - (2/13 - 3/7)
= -3/7 + 17/26 - 2/13 + 3/7
= (-3/7 + 3/7) + (17/26 - 2/13)
= 0 + 13/26
= 1/2
\(\dfrac{5}{2.7}+\dfrac{16}{7.9}-\dfrac{2}{9.11}-\dfrac{29}{11.18}\)
\(=\dfrac{5-2}{2.7}+\dfrac{7+9}{7.9}-\dfrac{11-9}{9.11}-\dfrac{11+18}{11.18}\)
\(=\dfrac{1}{2}-\dfrac{1}{7}+\dfrac{1}{7}+\dfrac{1}{9}-\dfrac{1}{9}+\dfrac{1}{11}-\dfrac{1}{11}-\dfrac{1}{18}\)
\(=\dfrac{1}{2}-\dfrac{1}{18}=\dfrac{4}{9}\)
A = \(\dfrac{5}{2.7}\) + \(\dfrac{16}{7.9}\) - \(\dfrac{2}{9.11}\) - \(\dfrac{29}{11.18}\)
A = \(\dfrac{1}{2}\) - \(\dfrac{1}{7}\) + \(\dfrac{1}{7}\) + \(\dfrac{1}{9}\) - \(\dfrac{1}{9}\) + \(\dfrac{1}{11}\) - \(\dfrac{1}{11}\) - \(\dfrac{1}{18}\)
A = \(\dfrac{1}{2}\) - \(\dfrac{1}{18}\)
A = \(\dfrac{4}{9}\)