Hình...đâu bạn..?

Tất cả các bộ ba điểm thẳng hàng là: A, B, C;  A, B, D;  A, C, D và  B, C, D.

D=\(\frac{-21}{9}-\frac{4}{11}.\frac{-7}{2}+\frac{2}{3}.\left(\frac{-5}{2}\right)\)

=\(\left(-3\right)-\frac{-14}{11}+\frac{-5}{3}=\frac{-99}{33}-\frac{-42}{33}+\frac{-55}{33}=\frac{-112}{33}\)

E=\(\frac{5}{36}:\frac{-1}{6}+\frac{7}{12}.\frac{5}{-2}-\frac{11}{3}.\frac{-1}{4}\)

=\(\frac{-5}{6}+\frac{-35}{24}-\frac{-11}{12}=\frac{-20}{24}+\frac{-35}{24}-\frac{-22}{24}=\frac{-33}{24}=\frac{-11}{8}\)

G=\(\frac{-3}{4}+\frac{-1}{3}.\left(\frac{1}{2}-\frac{5}{18}\right)\)

=\(\frac{-3}{4}+\frac{-1}{3}.\frac{2}{9}=\frac{-3}{4}+\frac{-2}{27}=\frac{-89}{108}\)

I=\(\frac{-19}{9}.\left(2-\frac{4}{-11}-\frac{-2}{3}\right)\)

=\(\frac{-19}{9}.\left(\frac{26}{11}-\frac{-2}{3}\right)=\frac{-19}{9}.\frac{100}{33}=\frac{-1900}{297}\)

J=\(\frac{-5}{6}:\left(\frac{1}{2}.\frac{3}{5}+\frac{-7}{12}-\frac{1}{3}\right)\)

=\(\frac{-5}{6}:\left(\frac{3}{10}+\frac{-11}{12}\right)=\frac{-5}{6}:\frac{-37}{60}=\frac{-5}{6}.\frac{60}{-37}=\frac{50}{37}\)

K=\(\frac{-3}{4}:\left(\frac{11}{3}.\frac{-9}{2}-\frac{5}{18}.\frac{-9}{3}\right)\)

=\(-\frac{3}{4}:\left(-\frac{33}{2}-\frac{-5}{6}\right)=\frac{-3}{4}:\frac{-47}{3}=\frac{-3}{4}.\frac{3}{-47}=\frac{9}{188}\)

1152-(374+1152)+(-65+374)

=1152-374-1152-65+374

=(1152-1152)+(374-374)-65

=0+0-65

=-65

thank you!

= -222 . (-222)

= 49284

hết

= - 222 - ( - 222 )

= 0

hết

\(=-345+123+345-123=0\)

\(A=\frac{-19}{9}.\frac{1}{2}-\frac{4}{11}\times\frac{-11}{9}+\frac{-2}{3}\)

=\(\frac{-19}{18}-\frac{-4}{9}+\frac{-2}{3}=\frac{-19}{18}-\frac{-8}{18}+\frac{-12}{18}=\frac{-23}{18}\)

B=\(\frac{-15}{6}:\frac{-1}{2}+\frac{7}{-12}-\frac{1}{3}.\frac{-11}{2}=5+\frac{-7}{12}-\frac{-11}{6}=\frac{60}{12}+\frac{-7}{12}-\frac{-22}{12}=\frac{75}{12}\)=\(\frac{25}{4}\)

C=\(\frac{3}{4}.\left(-8\right)-\frac{1}{3}.\frac{-7}{2}-\frac{5}{18}=\left(-6\right)-\frac{-7}{6}-\frac{5}{18}=\frac{-108}{18}-\frac{-21}{18}-\frac{5}{18}=\frac{-92}{18}\)=\(\frac{-46}{9}\)

Sói sai 5 câu nhé

HT

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