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= 2/21
=9/5
=37/6:\(6\frac{1}{6}\)
=79/20: tự đổi nhe bạn
=3/5__________-
\(\frac{4}{15}x\frac{5}{14}=\frac{4x5}{15x14}=\frac{2x1}{3x7}=\frac{2}{21}\)
\(\frac{3}{4}:\frac{5}{12}=\frac{3}{4}x\frac{12}{5}=\frac{3x12}{4x5}=\frac{3x3}{1x5}=\frac{9}{5}=1,8\)
\(\frac{7}{2}+\frac{8}{3}=\frac{7x3}{2x3}+\frac{8x2}{3x2}=\frac{21}{6}+\frac{16}{6}=\frac{21+16}{6}=\frac{37}{6}\)

\(3+\frac{2}{5}-\frac{3}{4}\times\frac{4}{5}\)
\(=3+\frac{2}{5}+\frac{3}{5}\)
\(=3+1\)
\(=4\)

\(\frac{2}{3}.\frac{4}{5}+\frac{1}{3}.\frac{4}{5}=\frac{4}{5}\left(\frac{2}{3}+\frac{1}{3}\right)=\frac{4}{5}.\frac{3}{3}=\frac{4}{5}.1=\frac{4}{5}\)
\(\frac{1}{2}:\frac{3}{4}+\frac{1}{6}:\frac{3}{4}=\frac{3}{4}:\left(\frac{1}{2}+\frac{1}{6}\right)=\frac{3}{4}:\frac{2}{3}=\frac{9}{8}\)
\(\frac{2}{3}.\frac{4}{5}-\frac{1}{3}.\frac{4}{5}=\frac{4}{5}\left(\frac{2}{3}-\frac{1}{3}\right)=\frac{4}{5}.\frac{1}{3}=\frac{4}{15}\)
\(\frac{1}{2}:\frac{3}{4}-\frac{1}{6}:\frac{3}{4}=\frac{3}{4}:\left(\frac{1}{2}-\frac{1}{6}\right)=\frac{3}{4}:\frac{1}{3}=\frac{9}{4}\)
\(\frac{2}{3}.\frac{4}{5}+\frac{1}{3}.\frac{4}{5}=\left(\frac{2}{3}+\frac{1}{3}\right).\frac{4}{5}=1.\frac{4}{5}=\frac{4}{5}\)
\(\frac{1}{2}:\frac{3}{4}+\frac{1}{6}:\frac{3}{4}=\frac{1}{2}.\frac{4}{3}+\frac{1}{6}.\frac{4}{3}=\left(\frac{1}{2}+\frac{1}{6}\right).\frac{4}{3}=\frac{2}{3}.\frac{4}{3}=\frac{8}{9}\)
c,d tương tự

\(3+\frac{2}{5}-\frac{3}{4}\)X \(\frac{4}{5}\)
\(=\frac{3}{1}+\frac{2}{5}-\frac{3}{5}\)
\(=\frac{17}{5}-\frac{3}{5}\)
\(=\frac{14}{5}\)
\(3+\frac{2}{5}-\frac{3}{4}\times\frac{4}{5}\)
\(=3+\frac{2}{5}-\frac{3}{5}\)
\(=3+\frac{-1}{5}\)
\(=\frac{15}{5}+\frac{-1}{5}\)
\(=\frac{14}{5}\)

\(8\frac{7}{10}+2\frac{3}{4}=\frac{87}{10}+\frac{11}{4}=\frac{174}{20}+\frac{55}{20}=\frac{229}{20}\)
Bạn chỉ cần đưa về phân số xong tính bình thường. Muốn đổi từ hỗn số sang phân số, ta chỉ cần lấy phần nguyên nhân cho mẫu rồi cộng với tử là xong. Chứ bạn cứ hỏi mấy bài dễ như thế này thì k giỏi đc đâu!!!

\(\dfrac{3}{4}\times\dfrac{8}{5}:1\dfrac{1}{6}\)
=\(\dfrac{6}{5}:\) \(\dfrac{7}{6}\)
=\(\dfrac{6}{5}\times\dfrac{6}{7}=\dfrac{36}{35}\)
2\(\dfrac{1}{3}\) x 1\(\dfrac{1}{4}\) -\(\dfrac{7}{5}\)
\(\dfrac{7}{3}\times\dfrac{5}{4}-\) \(\dfrac{7}{5}\)
\(\dfrac{35}{12}-\dfrac{7}{5}\)
\(\dfrac{175}{60}-\dfrac{84}{60}=\dfrac{91}{60}\)
4\(\dfrac{2}{3}+1\dfrac{1}{4} +2\dfrac{1}{3}+2\dfrac{3}{7}\)
(4 +2) + \(\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\) +1\(\dfrac{1}{4}\) + \(2\dfrac{3}{7}\)
6 + 1 + \(\dfrac{5}{4}\) + \(\dfrac{17}{7}\)
7 + \(\dfrac{103}{28}\)
\(\dfrac{299}{28}\)

đưa hết hỗn số về dạng phân số rồi quy đồng bình thường ạ !
Hoàng_Linh_Nga làm đc thì làm nhé.
Giải:
\(2\frac{1}{6}+3\frac{2}{3}\)
\(=\frac{13}{12}+\frac{11}{9}\)
\(=\frac{249}{108}\)
\(4\frac{3}{4}-3\frac{5}{6}\)
\(=\frac{19}{16}-\frac{23}{18}\)
\(=\frac{342}{288}-\frac{368}{288}\)
\(=\frac{-26}{288}\)xem lại đề đi nhé
\(9\frac{1}{6}\times4\frac{2}{3}\)
\(=\frac{55}{18}\times\frac{15}{12}\)
\(=\frac{825}{216}\)
\(2\frac{5}{7}:\frac{14}{5}\)
\(=\frac{19}{7}:\frac{14}{5}\)
\(=\frac{95}{98}\)

\(a.\) \(3\frac{3}{4}+\left(4\frac{2}{4}-3\frac{1}{2}\right):\frac{3}{4}\)
\(=\frac{15}{4}\left(\frac{18}{4}-\frac{7}{2}\right):\frac{3}{4}\)
\(=\frac{15}{4}+\frac{4}{4}:\frac{3}{4}=\frac{15}{4}+\frac{4}{3}\)
\(=\frac{15}{4}+\frac{4}{3}=\frac{61}{12}\)
\(b.\) \(7\cdot\frac{2}{3}-\frac{2}{5}:\frac{1}{2}-\frac{2}{3}\)
\(=\frac{7}{3}-\frac{2}{5}\cdot2-\frac{2}{3}\)
\(=\frac{7}{3}-\frac{4}{5}-\frac{2}{3}=\frac{35-12-10}{15}\)
\(=\frac{13}{15}\)
\(c.\) \(68,7-100:20+70,8\)
\(=68,7-5+70,8\)
\(=63,7+70,8\)
\(=134,5\)
\(d.\)\(\left(5915+445:5\right)-76\cdot25\)
\(=\left(5915+89\right)-1900\)
\(=6004-1900=4104\)
a)=\(\frac{15}{4}+\left(\frac{18}{4}-\frac{7}{2}\right)\)/ \(\frac{3}{4}\)
=\(\left(\frac{33}{4}-\frac{14}{4}\right)\)/ \(\frac{3}{4}\)
= \(\frac{19}{4}\cdot\frac{4}{3}\)
=\(\frac{19}{3}\)
b) = \(\frac{2}{3}\cdot\left(7-1\right)-\frac{2}{5}\cdot\frac{2}{1}\)
= \(\frac{2}{3}\cdot6-\frac{4}{5}\)
= 1-\(\frac{4}{5}\)
= \(\frac{1}{5}\)
c) = 68.7 - 5 + 70.8
= 63.7 + 70.8
=134.5
d) = (5915 - 89) -76*25
= 5826 - 1900
= 3926
\(\frac23+\frac45=\frac{10}{15}+\frac{12}{15}=\frac{22}{15}\)
\(\frac23+\frac45=\frac{10}{15}+\frac{12}{15}=\frac{10+12}{15}=\frac{22}{15}\)