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a. \(\frac{1}{4}=\frac{12}{y}\)
\(\Leftrightarrow1y=4.12\)
\(\Leftrightarrow y=48\)
b. \(47,5y+52,5y=2,69\)
\(\Leftrightarrow y\left(47,5+52,5\right)=2,69\)
\(\Leftrightarrow100y=2,69\)
\(\Leftrightarrow y=2,69\div100\)
\(\Leftrightarrow y=0,0269\)

Ta có : \(\frac{1}{4}+\frac{1}{3}:\frac{1}{x}=\frac{11}{12}\)
\(\Rightarrow\frac{1}{3}:\frac{1}{x}=\frac{11}{12}-\frac{1}{4}\)
\(\frac{1}{3}:\frac{1}{x}=\frac{2}{3}\)
\(\frac{1}{x}=\frac{1}{3}:\frac{2}{3}\)
\(\frac{1}{x}=\frac{1}{3}\times\frac{3}{2}\)
\(\frac{1}{x}=\frac{1}{2}\)
=> x = 2
a) \(\frac{x\div3-16}{2}+21=38\)
\(\frac{x\div3-16}{2}=38+21\)
\(\frac{x\div3-16}{2}=59\)
\(x\div3-16=59.2\)
\(x\div3-16=118\)
\(x\div3=118+16\)
\(x\div3=134\)
\(x=134.3\)
\(x=402\)
b) \(\frac{1}{4}+\frac{1}{3}\div\frac{1}{x}=\frac{11}{12}\)
\(\frac{1}{3}\div\frac{1}{x}=\frac{11}{12}-\frac{1}{4}\)
\(\frac{1}{3}\div\frac{1}{x}=\frac{2}{3}\)
\(\frac{1}{x}=\frac{1}{3}\div\frac{2}{3}\)
\(\frac{1}{x}=\frac{1}{2}\)
Vậy x = ....

= 2/21
=9/5
=37/6:\(6\frac{1}{6}\)
=79/20: tự đổi nhe bạn
=3/5__________-
\(\frac{4}{15}x\frac{5}{14}=\frac{4x5}{15x14}=\frac{2x1}{3x7}=\frac{2}{21}\)
\(\frac{3}{4}:\frac{5}{12}=\frac{3}{4}x\frac{12}{5}=\frac{3x12}{4x5}=\frac{3x3}{1x5}=\frac{9}{5}=1,8\)
\(\frac{7}{2}+\frac{8}{3}=\frac{7x3}{2x3}+\frac{8x2}{3x2}=\frac{21}{6}+\frac{16}{6}=\frac{21+16}{6}=\frac{37}{6}\)

câu 1: 3,2
câu 2: 40
câu 3: 12
câu 4: 42
nhớ cho mình nhé !

\(a,\)\(71+65\times4=\frac{x+140}{x}+260\)
\(\Rightarrow71+260=\frac{x-140}{x}+260\)
\(\Rightarrow71=\frac{x-140}{x}\)
\(\Rightarrow71x=x-140\)
\(\Rightarrow71x-x=-140\)
\(\Rightarrow70x=-140\)
\(\Rightarrow x=-2\)
\(b,\)\(y\times\frac{15}{2}-\frac{1}{3}\times\left(\frac{1}{4}+y\right)=90\frac{2}{3}\)
\(\Rightarrow\frac{15y}{2}-\frac{1}{12}-\frac{y}{3}=\frac{272}{3}\)
\(\Rightarrow\frac{90y}{12}-\frac{1}{12}-\frac{4y}{12}=\frac{1088}{12}\)
\(\Rightarrow90y-1-4y=1088\)
\(\Rightarrow86y=1089\)
\(\Rightarrow y=\frac{1089}{86}\)

Xin lỗi bạn nhé mình chỉ làm được bài 2 thôi!
Bài 2:
a) y + y x 1/3 : 2/9 + y : 2/7 = 252
y x 1 + y x 1/3 x 9/2 + y x 7/2 = 252
y x 1 + y x 3/2 + y x 7/2 = 252
y x ( 1 + 3/2 + 7/2) = 252
y x 6 = 252
y = 252 : 6
y =42
b) ( 324 : 3 + 12 - y) : 7 = 3
( 108 + 12 - y) = 3 x 7
120 - y = 21
y = 120 - 21
y 99
\(\frac14-\frac13+\frac{x}{y}=\frac{1}{12}\)
\(\frac{x}{y}=\frac{1}{12}-\frac14+\frac13\)
\(\frac{x}{y}=\frac16\)
⇒ x = 1; y = 6
\(\frac14\) - \(\frac13\) + \(\frac{x}{y}\) = \(\frac{1}{12}\)
\(\frac{x}{y}\) = \(\frac{1}{12}\) -(\(\frac14\) - \(\frac13\))
\(\frac{x}{y}\) = \(\frac{1}{12}\) - \(\frac14\) + \(\frac13\)
\(\frac{x}{y}\) = (\(\frac{1}{12}\) + \(\frac13\)) - \(\frac14\)
\(\frac{x}{y}\) = (\(\frac{1}{12}\) + \(\frac{4}{12}\)) - \(\frac14\)
\(\frac{x}{y}\) = \(\frac{5}{12}\) - \(\frac{3}{12}\)
\(\frac{x}{y}=\frac{2}{12}\)
\(\frac{x}{y}\) = \(\frac16\)