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bài 1:
\(\frac{6}{11}+\frac{1}{3}+\frac{5}{11}\)
\(=\left(\frac{6}{11}+\frac{5}{11}\right)+\frac{1}{3}\)
\(=\frac{11}{11}+\frac{1}{3}=1+\frac{1}{3}=\frac{3}{3}+\frac{1}{3}=\frac{4}{3}\)
bài 2:
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}\)
\(=\left(\frac{1}{2}+\frac{1}{20}\right)+\left(\frac{1}{6}+\frac{1}{12}\right)\)
\(=\frac{11}{20}+\frac{1}{4}=\frac{11}{20}+\frac{5}{20}=\frac{15}{20}=\frac{3}{4}\)
bài 3:
a) \(\frac{3}{2}\cdot\frac{4}{5}\cdot\frac{2}{3}=\left(\frac{3}{2}\cdot\frac{2}{3}\right)\cdot\frac{4}{5}=1\cdot\frac{4}{5}=\frac{4}{5}\)
b) \(\frac{6}{7}\cdot\frac{5}{3}\cdot\frac{7}{6}=\left(\frac{6}{7}\cdot\frac{7}{6}\right)\cdot\frac{5}{3}=1\cdot\frac{5}{3}=\frac{5}{3}\)
bài 4:
a) \(\frac{2}{5}\cdot\frac{1}{4}+\frac{3}{4}\cdot\frac{2}{5}=\frac{2}{5}\cdot\left(\frac{1}{4}+\frac{3}{4}\right)=\frac{2}{5}\cdot1=\frac{2}{5}\)
b) \(\frac{6}{11}:\frac{2}{3}+\frac{5}{11}:\frac{2}{3}=\left(\frac{6}{11}+\frac{5}{11}\right):\frac{2}{3}=1:\frac{2}{3}=\frac{3}{2}\)
Bài 1:
6/11 + 1/3 + 5/11
= ( 6/11 + 5/11) + 1/3
= 11/11 + 1/3
= 1 + 1/3
= 3/3 +1/3
= 4/3
Bài 2:
1/2 + 1/6 + 1/12 + 1/20
= ( 1/2 + 1/6 + 1/12 ) + 1/20
= ( 6/12 + 2/12 + 1/12 ) + 1/20
=9/12 + 1/20
= 3/4 +1/20
= 15/20 + 1/20
= 16/20 = 4/5
Bài 3:
a) \(\frac{3}{2}\times\frac{4}{5}\times\frac{2}{3}\) \(=\left(\frac{3}{2}\times\frac{2}{3}\right)\times\frac{4}{5}\)\(=1\times\frac{4}{5}=\frac{4}{5}\)
b) \(\frac{6}{7}\times\left(\frac{5}{3}\times\frac{7}{6}\right)\) \(=\frac{6}{7}\times\frac{35}{18}\)\(=\frac{1\times5}{7\times3}=\frac{5}{21}\)
Bài 4:
a) 2/5 x 1/4 + 3/4 x 2/5
= 2/5 x ( 1/4 + 3/4)
= 2/5 x 1
= 2/5
b) 6/11 : 2/3 +5/11 : 2/3
= ( 6/11 + 5/11) x 3/2
= 11/11 x 3/2
= 1 x 3/2
= 3/2
....
\(a,\frac{2}{5}+\frac{1}{6}+\frac{3}{5}\)
\(=\left(\frac{2}{5}+\frac{3}{5}\right)+\frac{1}{6}\)
\(=1+\frac{1}{6}\)
\(=\frac{7}{6}\)
Hok tốt!~
a, \(\frac{2}{3}+\frac{2}{3}+\frac{6}{3}=\frac{10}{3}\)
b,\(\frac{3}{4}+\frac{3}{4}+\frac{3}{2}=\frac{6}{4}+\frac{3}{2}=\frac{3}{2}+\frac{3}{2}=\frac{6}{2}=3\)
a) \(\frac{1}{3}+\frac{1}{4}-\frac{1}{5}\)
\(=\frac{23}{60}\)
b) \(\frac{5}{2}+\frac{1}{3}-\frac{1}{4}\)
\(=\frac{31}{12}\)
c) \(\frac{10}{3}-\left(\frac{1}{4}+\frac{1}{12}\right)\)
\(=\frac{9}{3}=3\)
d) \(\frac{1}{3}+\frac{6}{5}-\frac{1}{15}\)
\(=\frac{22}{15}\)
trả lòi:
A)= 23/60
B)= 31/12
C)= 3* vì 3/9 cùng chia hết cho 3*
D)= 22/15
Hc tốt!
\(a,\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(=\frac{1}{2}-\frac{1}{6}=\frac{1}{3}\)
\(b,\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times\left(1-\frac{1}{4}\right)=\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\)
\(=\frac{1\times2\times3}{2\times3\times4}=\frac{1}{4}\)
Bài 5:
Bài giải
Bác An đã bán được số gạo là:
\(45\times\frac{2}{5}=18\left(kg\right)\)
Bác An còn lại số gạo là:
\(45-18=27\left(kg\right)\)
Đ/S: 27 kg
Bài 1:
\(\frac{3}{4}-\frac{1}{6}=\frac{7}{12}\)
Bài 2:
\(\frac{9}{10}-x=\frac{1}{3}\)
\(x=\frac{9}{10}-\frac{1}{3}\)
\(x=\frac{17}{30}\)
Bài 3:
\(\frac{9}{8}-\frac{9}{14}=\frac{27}{56}\)
Bài 4:
\(\frac{4}{7}\times\frac{5}{3}=\frac{20}{21}\)
Bài 5:
Bài giải
Bác An đã bán được số gạo là:
- a B,b D
- a \(\frac{1}{2}\)b \(\frac{2}{5}\)
- \(\frac{2}{3};\frac{10}{17};\frac{5}{11};\frac{4}{9}\)
- a\(\frac{5}{12}\)b\(\frac{97}{36}\)
\(a.\dfrac{3\times4\times7}{12\times8\times9}=\dfrac{3\times4\times7}{3\times4\times4\times2\times9}\\ =\dfrac{7}{4\times2\times9}=\dfrac{7}{72}\\ b.\dfrac{4\times5\times6}{12\times10\times8}=\dfrac{4\times5\times2\times3}{4\times3\times5\times2\times4\times2}=\dfrac{1}{8}\\ c.\dfrac{5\times6\times7}{12\times14\times15}=\dfrac{5\times6\times7}{2\times6\times7\times2\times5\times3}\\ =\dfrac{1}{2\times2\times3}=\dfrac{1}{12}\)
a: \(\dfrac{14}{9}-\dfrac{1}{6}-\dfrac{1}{3}-\dfrac{1}{2}+\dfrac{4}{9}\)
\(=\left(\dfrac{14}{9}+\dfrac{4}{9}\right)-\left(\dfrac{1}{6}+\dfrac{1}{3}+\dfrac{1}{2}\right)\)
\(=\dfrac{18}{9}-\left(\dfrac{1}{6}+\dfrac{2}{6}+\dfrac{3}{6}\right)\)
=2-1
=1
b: \(\dfrac{3}{4}-\dfrac{1}{3}-\dfrac{1}{6}\)
\(=\dfrac{9}{12}-\dfrac{4}{12}-\dfrac{2}{12}\)
\(=\dfrac{9-4-2}{12}=\dfrac{3}{12}=\dfrac{1}{4}\)
A) \(\frac{14}{9} - \frac{1}{6} - \frac{1}{3} - \frac{1}{2} + \frac{4}{9}\)
\(\frac{14}{9} = \frac{28}{18} , \frac{4}{9} = \frac{8}{18} , \frac{1}{6} = \frac{3}{18} , \frac{1}{3} = \frac{6}{18} , \frac{1}{2} = \frac{9}{18}\)
\(\frac{28}{18} - \frac{3}{18} - \frac{6}{18} - \frac{9}{18} + \frac{8}{18} = \frac{18}{18} = 1\)
Kết quả A: 1
B) \(\frac{3}{4} - \frac{1}{3} - \frac{1}{6}\)
\(\frac{3}{4} = \frac{9}{12} , \frac{1}{3} = \frac{4}{12} , \frac{1}{6} = \frac{2}{12}\)
\(\frac{9}{12} - \frac{4}{12} - \frac{2}{12} = \frac{3}{12} = \frac{1}{4}\)
Kết quả B: \(\frac{1}{4}\)