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Câu a:
\(\frac27\) + \(\frac{-3}{8}\) + \(\frac{11}{7}\) + \(\frac17\) + \(\frac{5}{-8}\)
= (\(\frac27+\frac{11}{7}+\frac17\)) -(\(\frac38\) + \(\frac58\))
= (\(\frac{13}{7}+\frac17\)) - \(\frac88\)
= \(\frac{14}{7}-1\)
= 2 - 1
= 1
Câu b:
\(\frac{3}{17}+\frac{-5}{13}+\frac{-18}{35}+\frac{14}{17}+\frac{17}{-35}+\frac{-8}{13}\)
= (\(\frac{3}{17}+\frac{14}{17}\)) - (\(\frac{5}{13}\) + \(\frac{8}{13}\)) - (\(\frac{18}{35}+\frac{17}{35}\))
= \(\frac{17}{17}-\frac{18}{18}-\) \(\frac{35}{35}\)
= 1 - 1 - 1
= 0 - 1
= -1

-3/8+12/25+5/-8+2/-5+13/25
=(3/8+5/-8)+12/25+2/-5+13/25
=-1+12/25+2/-5+13/25
=-13/25+2/-5+13/25
=-23/25+13/25
=-2/5

\(\dfrac{-3}{8}+\dfrac{12}{25}+\dfrac{5}{-8}+\dfrac{2}{-5}+\dfrac{13}{25}\)
\(=\dfrac{-3}{8}+\dfrac{12}{25}+\dfrac{-5}{8}+\dfrac{-2}{5}+\dfrac{12}{25}\)
\(=\left(\dfrac{-3}{8}+\dfrac{-5}{8}\right)+\left(\dfrac{12}{25}+\dfrac{12}{25}+-\dfrac{2}{5}\right)\)
Còn lại bn tự tính nhé!
\(\dfrac{-3}{8}\) + \(\dfrac{12}{25}\) + \(\dfrac{5}{-8}\) + \(\dfrac{2}{-5}+\dfrac{13}{25}\)
= \(\left(\dfrac{-3}{8}+\dfrac{5}{-8}\right)+\left(\dfrac{12}{25}+\dfrac{13}{25}\right)+\dfrac{2}{-5}\)
= \(\left(\dfrac{-3}{8}+\dfrac{-5}{8}\right)+1+\dfrac{-2}{5}\)
= 1 + 1 + \(\dfrac{-2}{5}\)
= \(\dfrac{8}{5}\)

A=2/7+-3/8+11/7+1/3+1/7+5/-8
A=(2/7 + 1/7 + 11/7) + (-3/8 + 5/-8) + 1/3
A=2 + (-1) + 1/3
A=1 + 1/3
A=4/3
B=-3/8+12/25+5/-8+2/-5+13/25
B=(-3/8 + 5/-8) + (12/25 + 13/25) + 2/-5
B=-1 + 1 + 2/-5
B=-2/5

\(A=\left(\dfrac{2}{7}+\dfrac{11}{7}+\dfrac{1}{7}\right)+\left(\dfrac{-3}{8}+\dfrac{-5}{8}\right)+\dfrac{1}{3}=2-1+\dfrac{1}{3}=1+\dfrac{1}{3}=\dfrac{4}{3}\)
\(B=\dfrac{-3}{8}+\dfrac{12}{25}+\dfrac{-5}{8}+\dfrac{-2}{5}+\dfrac{13}{25}=1+1-\dfrac{5}{8}=-\dfrac{5}{8}\)
`-3/8 + 12/25 - 5/8 + 2/(-5) + 13/25`
`= -(3/8 + 5/8) + (12/25 + 13/25) - 2/5 `
`= -1 + 1 - 2/5`
`= -2/5`
\(\dfrac{-3}{8}+\dfrac{12}{25}-\dfrac{5}{8}+\dfrac{2}{-5}+\dfrac{13}{25}\)
\(=\left(\dfrac{-3}{8}-\dfrac{5}{8}\right)+\left(\dfrac{12}{25}+\dfrac{13}{25}\right)-\dfrac{2}{5}\)
\(=\dfrac{-8}{8}+\dfrac{25}{25}-\dfrac{2}{5}\)
\(=-1+1-\dfrac{2}{5}\)
\(=\dfrac{-2}{5}\)