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2x = 43 : 25
2x = (22)3 : 25
2x = 26 : 25
2x = 2
=> x = 1

a, \(2^x-15=17\)
\(\Rightarrow2^x=17+15\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
b, \(\left(7x-11\right)^3=2^5.5^2+200\)
\(\Rightarrow\left(7x-11\right)^3=32.25+200\)
\(\Rightarrow\left(7x-11\right)^3=1000\)
\(\Rightarrow\left(7x-11\right)^3=10^3\)
\(\Rightarrow7x-11=10\)
\(\Rightarrow7x=10+11\)
\(\Rightarrow7x=21\)
\(\Rightarrow x=21:7\)
\(\Rightarrow x=3\)
c, \(x^{10}=1^x\)
\(\Rightarrow x\in\left\{1;0\right\}\)
\(2^x-15=17\)
\(\Rightarrow2^x=17+15\)
\(\Rightarrow2^x=32=2^4\)
\(\Rightarrow x=4\)
\(\left(7x-11\right)^3=2^5.5^2+200\)
Phần này mk ko bt làm đâu
\(x^{10}=1^x\)
\(\Rightarrow\)\(x^{10}=1\)
\(\Rightarrow x=1\)

\(x^{200}=x\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x=0\end{cases}}\)
\(x^{100}=1\)
\(\Rightarrow x=1\)
\(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\Rightarrow2x-15=2x-15\)
\(\Rightarrow x=1\)

\(\frac{10.\left(4^6.9^5+6^9.120\right)}{8^4.3^{12}-6^{11}}\)
=\(\frac{2.5.\left[\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^9.2^3.3.5\right]}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)
=\(\frac{2^{13}.5.3^{10}+2^{13}.5^2.3^{10}}{2^{12}.3^{12}-3^{11}.2^{11}}\)
=\(\frac{2^{13}.5.3^{10}.\left(1+5\right)}{2^{11}.3^{11}.\left(2.3-1\right)}\)
=\(\frac{4.5.6}{3.5}\)
= 8

\(\Leftrightarrow2^{x+1}.3^y=4^x.3^x\)
\(\Leftrightarrow2^{x+1}.3^y=2^{2x}.3^x\)
\(\Leftrightarrow\frac{3^y}{3^x}=\frac{2^{2x}}{2^{x+1}}\)
\(\Leftrightarrow3^{y-x}=2^{x-1}\)
Nếu \(x>1\Rightarrow\) vế trái lẻ, vế phải chẵn pt vô nghiệm
\(\Rightarrow x=1\Rightarrow3^{y-1}=1\Rightarrow y=1\)

\(2^6-(7\times x-15)=3^2\)
\(64-(7\times x-15)=9\)
\(7\times x-15=64-9\)
\(7\times x-15=55\)
\(7\times x=55+15\)
\(7\times x=70\)
\(x=70:7\)
Vậy \(x=10\)
là này hả
\(x^{x+2}+x^{x+3}=192\)