Question

[Nguyễn Ngọc Ánh]

(X-1)^2=1

Answer 1

[Nguyễn Lê Phước Thịnh]

Ta có: \(\left(x-1\right)^2=1\)

=>\(\left[{}\begin{matrix}x-1=1\\x-1=-1\\\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=1+1=2\\x=-1+1=0\end{matrix}\right.\)

Answer 2

[Citii?]

\(\left(x-1\right)^2=1 \)

\(\Rightarrow\left[{}\begin{matrix}TH1:x-1=1\\TH2:x-1=-1\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=1+1\\x=-1+1\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2\\x=0\end{matrix}\right.\)