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a)(−2023).33+2023.(−68)+2023�)(-2023).33+2023.(-68)+2023
=2023.(−33−68+1)=2023.(-33-68+1)
=2023.(−100)=2023.(-100)
=−202300=-202300
b)(38−29+43)−(43+38)�)(38-29+43)-(43+38)
=38−29+43−43−38=38-29+43-43-38
=(38−38)−29+(43−43)=(38-38)-29+(43-43)
=−29=-29
=−29=-29
a, 38 - 815 - (65 - 815)
= 38 - 815 - 65 + 815
= 38 - (815 - 815) - 65
= 38 - 0 - 65
= - (65 - 38)
= - 27
b, (43 + 863) - (137 - 57)
= 906 - 80
= 826
( 36 + 79 ) + ( 145 - 79 - 36 )
= 115 + ( 66 - 36 )
= 115 + 30
= 145
10 - [ 12 - ( - 9 - 1 ) ]
= 10 - [ 12 - ( - 10 ) ]
= 10 - 22
= - 12
( 38 - 29 + 43 ) - ( 43 + 38 )
= ( 9 + 43 ) - 81
= 52 - 81
= - 29
271 - [ ( 43 ) + 271 - ( - 17 ) ]
= 271 - [ 314 - ( - 17 ) ]
= 271 - 331
= - 60
- 144 - [ 29 - ( + 144 ) - ( + 144 ) ]
= - 144 - [ ( - 115 ) - ( + 144 ) ]
= - 144 - ( - 259 )
= 115
(36+79)+(145-79-36)
=115+30
=145
10-[12-(-9-1)]
=10-22
=-12
(38-29+43)-(43+38)
=52-81
=(-29)
271-[(43)+271-(17)]
=271-297
=(-26)
-144-[29-(+144)-(+144)
=-144-(-259)
=115
27 + 514 - 486 + 73 = 128
10 - 12 - 9 - 1 = - 12
Tk mik mik làm nốt cho
Mik mới bị trừ 50 chục điểm bùn qúa T_T
a: \(12+2^2+3^2+4^2+5^2\)
\(=12+4+9+16+25\)
\(=16+50=66\)
\(\left(1+2+3+4+5\right)^2=15^2=225\)
=>\(12+2^2+3^2+4^2+5^2< \left(1+2+3+4+5\right)^2\)
b: \(1^3+2^3+3^3+4^3=\left(1+2+3+4\right)^2< \left(1+2+3+4\right)^3\)
c: \(5^{202}=5^2\cdot5^{200}=25\cdot5^{200}>16\cdot5^{200}\)
d: \(18\cdot4^{500}=18\cdot2^{1000}\)
\(2^{1004}=2^4\cdot2^{1000}=16\cdot2^{1000}\)
=>\(18\cdot4^{500}>2^{1004}\)
e: \(2022\cdot2023^{2024}+2023^{2024}=2023^{2024}\left(2022+1\right)\)
\(=2023^{2025}\)
f,(36+79)+(145-79-36)
=36+79+145-79-36
=(36-36)+(79-79)+145
=0+0+145
=145
g,10-[12-(-9-1)]
=10-(12+9+1)
=10-(12+10)
=10-12-10
=(10-10)-12
=0-12
=-12
h,(38-29+43)-(43+38)
=38-29+43-43-38
=(38-38)-29+(43-43)
=0-29+0
=-29
i,271-[(-43)+271-(-17)]
=271-(-43+271+17)
=271+43-271-17
=(271-271)+(43-17)
=0+26
=26
k,-144-[29-(+144)-(+144)]
=-144-(29-144-144)
=-144-29+144+144
=(-144+144)-29+144
=0-29+144
=-29+144
=115
\(\left(-12\right)+\left(-13\right)+36+\left(-11\right)=\left(-12-13-11\right)+36\)
\(=\left(-36\right)+36\)
\(=0\)
a: -12+125+75+12
=(-12+12)+(125+75)
=0+200
=200
b: \(\left(-2023\right)\cdot33+2023\cdot\left(-68\right)+2023\)
\(=\left(-2023\right)\left(33+68-1\right)\)
\(=-2023\cdot100=-202300\)
c: Ta có: (38-29+43)-(43+38)
\(=38-29+43-43-38\)
\(=\left(38-38\right)+\left(43-43\right)-29\)
=0+0-29
=-29
1+1-(-56)×24:3×[26+74] =?