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\(\begin{array}{l}a) - 1,2 + ( - 0,8) + 0,25 + 5,75 - 2021\\ = [ - 1,2 + ( - 0,8)] + (0,25 + 5,75) - 2021\\ = ( - 2) + 6 - 2021\\ = 4 - 2021\\ = - 2017\\b) - 0,1 + \frac{{16}}{9} + 11,1 + \frac{{ - 20}}{9}\\ = [( - 0,1) + 11,1] + \left( {\frac{{16}}{9} + \frac{{ - 20}}{9}} \right)\\ = 11 + \frac{{ - 4}}{9}\\ = \frac{{99}}{9} + \frac{{ - 4}}{9}\\ = \frac{{95}}{9}\end{array}\)
a) 15/11 - (5/7 - 18/11) + 27/7
= 15/11 - 5/7 + 18/11 + 27/7
= (15/11 + 18/11) + (-5/7 + 27/7)
= 3 + 22/7
= 43/7
b) 39/5 + (9/4 - 9/5) - (5/4 + 1,2)
= 39/5 + 9/4 - 9/5 - 5/4 - 6/5
= (39/5 - 9/5 - 6/5) + (9/4 - 5/4)
= 24/5 + 1
= 29/5
c) -1,2 - 0,8 + 0,25 + 5,75 - 2022
= (-1,2 - 0,8) + (0,25 + 5,76) - 2022
= -2 + 6 - 2022
= 4 - 2022
= -2018
d) 0,1 + 16/9 + 5,1 + (-20/9)
= (0,1 + 5,1) + (16/9 - 20/9)
= 5,2 - 4/9
= 419/90
a) \(\dfrac{15}{11}-\left(\dfrac{5}{7}-\dfrac{18}{11}\right)+\dfrac{27}{7}=\dfrac{22}{7}+3=\dfrac{43}{77}\)
b) \(\dfrac{39}{5}+\left(\dfrac{9}{4}-\dfrac{9}{5}\right)-\left(\dfrac{5}{4}+\dfrac{6}{5}\right)=\dfrac{24}{5}+1=\dfrac{29}{5}\)
c) \(-1,2-0,8+0,25+5,75-2022=-2+6-2022=-2018\)
d) \(0,1+\dfrac{16}{9}+5,1+\dfrac{-20}{9}=\dfrac{26}{5}-\dfrac{4}{9}=\dfrac{214}{45}\)
a, - 1,2 + (- 0,8) + 0,25 + 5,75 - 2021
= - (1,2 + 0,8) + (0,25 + 5,75) - 2021
= - 2 + 6 - 2021
= 4 - 2021
= - 2017
b, - 0,1 + \(\dfrac{16}{9}\) + 11,1 - \(\dfrac{20}{9}\)
= (11,1 - 0,1) - (\(\dfrac{20}{9}\) - \(\dfrac{16}{9}\))
= 11 - \(\dfrac{4}{9}\)
= \(\dfrac{95}{5}\)
12,5 . (-0,75) . (-0,8) - 0,25 . ( -5,14) . (-4)
= [12,5 . (-0,8)] . (-0,75) - [ 0,25 . (-4)] . (-5,14)
= -10 . ( -0,75) - (-1) . (-5,14)
= 7,5 - 5,14
= 2,36
\(\frac{x+1}{x+2}=\frac{0,8}{1,2}\)
\(\Rightarrow\frac{x+1}{x+2}=\frac{2}{3}\)
Để \(\frac{x+1}{x+2}=\frac{2}{3}\)
<=> (x+1).3=(x+2).2
=> 3x+3.1=2x+2.2
=> 3x+3 =2x+4
=> 3x-2x =4-3
=> (3-2).x =1
=> x =1
Vậy x=1
Chúc các bạn học tốt
x+1x+2 =0,81,2
⇒x+1x+2 =23
Để x+1x+2 =23
<=> (x+1).3=(x+2).2
=> 3x+3.1=2x+2.2
=> 3x+3 =2x+4
=> 3x-2x =4-3
=> (3-2).x =1
=> x =1
Vậy x=1
\(\text{Áp dụng t/c tỉ lệ thức ta có thể b/đ như sau:}\)
\(\frac{x+1}{x+2}=\frac{2}{3}\Rightarrow\left(x+1\right)3=\left(x+2\right)2\)
\(\Rightarrow3x+3=2x+4\)
\(\Rightarrow2x-3x=3-4\)
\(\Rightarrow-x=-1\)
\(\Rightarrow x=1\)
\(=\dfrac{25}{4}+\dfrac{2}{15}\cdot\dfrac{3}{2}-1+\dfrac{1}{4}=\dfrac{26}{4}-1+\dfrac{1}{5}=\dfrac{22}{4}+\dfrac{1}{5}=\dfrac{114}{20}=\dfrac{57}{10}\)
Ta có: \(\frac{x+1}{x+2}=\frac{0,8}{1,2}\)
\(\Rightarrow1,2.\left(x+1\right)=0,8.\left(x+2\right)\)
\(\Rightarrow1,2x+1,2=0,8x+1,6\)
\(\Rightarrow1,2x+0,8x=1,6+1,2\)
\(\Rightarrow2,8x=2,8\)
\(\Rightarrow x=2,8:2,8\)
\(\Rightarrow x=1\)
Vậy x = 1
\(\dfrac{x+1}{x+2}=\dfrac{0,8}{1,2}\) \(\Leftrightarrow0,8\left(x+2\right)=1,2\left(x+1\right)\)
\(\Leftrightarrow0,8x+1,6=1,2x+1,2\) \(\Leftrightarrow0,4x=0,4\Leftrightarrow x=1\)
vậy \(x=1\)
`-1,2 + (-0,8)+0,25 + 5,75 - 2021`
`= (-1,2 - 0,8) + (0,25 + 5,75) - 2021`
`= -2 + 6 - 2021`
`= 4 - 2021`
`= -2017`
-1,2+(-0,8)+0,25+5,75-2021
= -1,2-0,8+0,25+5,75-2021
= (-1,2-0,8)+(0,25+5,75)-2021
= -2+6-2021
= 4-2021
= -2017