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tao là N nè kqua phần a ra 20/3, phần b là 2.5 còn phần c tao làm rồi nhưng không chắc
(-1).(-1)\(^2\).(-1)\(^3\).....(-1)\(^{100}\)
\(\Rightarrow\)(-1).1.(-1).1.....(-1).1
có tất cả 50 số -1
có tất cả 50 số 1
\(\Rightarrow\) \([\)(-1).50\(]\).\([\)1.50\(]\)
=-50.50=0
(2\(x-\dfrac{4}{3}\)): \(\dfrac{4}{15}\) - 75% = 9\(\dfrac{1}{4}\)
(2\(x\) - \(\dfrac{4}{3}\)) : \(\dfrac{4}{15}\) - 0,75 = 9,25
(2\(x\) - \(\dfrac{4}{3}\)): \(\dfrac{4}{15}\) = 9,25 + 0,75
(2\(x\) - \(\dfrac{4}{3}\)): \(\dfrac{4}{15}\) = 10
2\(x\) - \(\dfrac{4}{3}\) = 10 \(\times\) \(\dfrac{4}{15}\)
2\(x\) - \(\dfrac{4}{3}\) = \(\dfrac{8}{3}\)
2\(x\) = \(\dfrac{8}{3}\) + \(\dfrac{4}{3}\)
2\(x\) = \(\dfrac{12}{3}\)
2\(x\) = 4
\(x\) = 4:2
\(x\) = 2
\(\left(2x-\dfrac{4}{3}\right)\div\dfrac{4}{15}-75\%=9\dfrac{1}{4}\)
\(\left(2x-\dfrac{4}{3}\right)\div\dfrac{4}{15}-\dfrac{3}{4}=\dfrac{37}{4}\)
\(\left(2x-\dfrac{4}{3}\right)\div\dfrac{4}{15}=10\)
\(2x-\dfrac{4}{3}=\dfrac{8}{3}\)
\(2x=\dfrac{8}{3}+\dfrac{4}{3}\)
\(2x=4\)
\(x=2\)
a, \(\left|x-3\right|-16=-4\Leftrightarrow\left|x-3\right|=12\)
\(\Leftrightarrow\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}\Leftrightarrow\orbr{\begin{cases}x=15\\x=-9\end{cases}}}\)
b, \(26-\left|x+9\right|=-13\Leftrightarrow\left|x+9\right|=39\)
\(\Leftrightarrow\orbr{\begin{cases}x+9=39\\x+9=-39\end{cases}\Leftrightarrow\orbr{\begin{cases}x=30\\x=-48\end{cases}}}\)
f, \(9x+25=-\left(2x-58\right)\Leftrightarrow9x+25=-2x+58\)
\(\Leftrightarrow11x-33=0\Leftrightarrow x=3\)
Làm nốt nhé !
a. \(\left|x-3\right|-16=-4\)
\(\Rightarrow\left|x-3\right|=12\)
\(\Rightarrow\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=15\\x=-9\end{cases}}\)
b. \(26-\left|x+9\right|=-13\)
\(\Rightarrow\left|x+9\right|=39\)
\(\Rightarrow\orbr{\begin{cases}x+9=39\\x+9=-39\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=30\\x=-48\end{cases}}\)
c. \(5-\left(10-x\right)=7\)
\(\Rightarrow10-x=-2\)
\(\Rightarrow x=12\)
d. \(11+\left(15-x\right)=1\)
\(\Rightarrow15-x=-10\)
\(\Rightarrow x=25\)
e. \(8x-75=5x+21\)
\(\Rightarrow8x-5x=75+21\)
\(\Rightarrow3x=96\)
\(\Rightarrow x=32\)
f. \(9x+25=-\left(2x-58\right)\)
\(\Rightarrow9x+25=-2x+58\)
\(\Rightarrow9x+2x=58-25\)
\(\Rightarrow11x=33\)
\(\Rightarrow x=3\)
g. \(\left|x+3\right|=4\)
\(\Rightarrow\orbr{\begin{cases}x+3=4\\x+3=-4\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x=-7\end{cases}}\)
h. \(15-\left|2x-1\right|=\left|-8\right|\)
\(\Rightarrow15-\left|2x-1\right|=8\)
\(\Rightarrow\left|2x-1\right|=7\)
\(\Rightarrow\orbr{\begin{cases}2x-1=7\\2x-1=-7\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=4\\x=-4\end{cases}}\)
x+2 là ước cảu x+ 7
\(\Rightarrow x+7⋮x+2\)
\(\Rightarrow x+2+5⋮x+2\)
mà \(x+2⋮x+2\)
\(\Rightarrow x+2\inƯ\left(5\right)=\left\{\pm1;\pm5\right\}\)
\(\Rightarrow x\in\left\{-1;\pm3;-7\right\}\)
[x+1]:25=3
x+1=25*3
x+1=75
x=75-1=74
12:[x-3]=6x-3=12:6
x-3=2
x=3+2
x=5
4[x-1]:5=8
4[x-1]=5.8
4[x-1]=40
x-1=40:4
x-1=10
x=10+1=11
9[x+3]-25=11
9[x+3]=25+11=36
x+3=36:9=4
x=4-3=1
75:[x-2]=1
x-2=75:1=75
x=75+2=77
[2x-5]-7=6
2x-5=7+6=13
2x=13+5=18
x=18:2=9
k mk nha mk cầu xin bn đó công mk làm mà
\(\left(2x-1\right)+\dfrac{1}{4}=75\%\)
\(\left(2x-1\right)+\dfrac{1}{4}=\dfrac{3}{4}\)
\(2x-1=\dfrac{3}{4}-\dfrac{1}{4}\)
\(2x-1=\dfrac{2}{4}\)
\(2x-1=\dfrac{1}{2}\)
\(2x=\dfrac{1}{2}+1\)
\(2x=\dfrac{1}{2}+\dfrac{2}{2}\)
\(2x=\dfrac{3}{2}\)
\(x=\dfrac{3}{2}:2\)
\(x=\dfrac{3}{2}.\dfrac{1}{2}\)
\(x=\dfrac{3}{4}\)
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