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\(a)9+\frac{24}{25}=\frac{9\cdot25+24}{25}=\frac{249}{25}\)
\(b)\frac{1}{20}+\frac{1}{4}+\frac{2}{5}=\frac{1}{20}+\frac{5}{20}+\frac{8}{20}=\frac{1+5+8}{20}=\frac{14}{20}=\frac{7}{10}\)
\(c)\frac{7}{12}+4=\frac{7}{12}+\frac{4}{1}=\frac{7+48}{12}=\frac{55}{12}\)
\(d)10+\frac{9}{8}=\frac{10}{1}+\frac{9}{8}=\frac{80+9}{8}=\frac{89}{8}\)
\(e)\frac{1}{4}+\frac{2}{25}+\frac{9}{100}=\frac{25}{100}+\frac{8}{100}+\frac{9}{100}=\frac{25+8+9}{100}=\frac{42}{100}=\frac{21}{50}\)
Còn 3 câu làm tương tự
Ba câu còn lại mình làm luôn :D
\(f)\frac{28}{90}+6=\frac{14}{45}+6=\frac{14}{45}+\frac{6}{1}=\frac{14+270}{45}=\frac{284}{45}\)
\(g)\frac{3}{7}+\frac{4}{9}+\frac{4}{7}+\frac{7}{11}=(\frac{3}{7}+\frac{4}{7})+\frac{4}{9}+\frac{4}{11}=1+\frac{4}{9}+\frac{4}{11}\)
\(=\frac{7}{7}+\frac{4}{9}+\frac{4}{11}=\frac{693+308+252}{693}=\frac{1253}{693}=\frac{179}{99}\)
\(h)\frac{1}{8}+\frac{1}{12}+\frac{3}{8}+\frac{5}{12}=(\frac{1}{8}+\frac{3}{8})+(\frac{1}{12}+\frac{5}{12})=\frac{4}{8}+\frac{6}{12}=\frac{1}{2}+\frac{1}{2}=1\)

b, 3/5 + 4/7 + 2/8 + 10/25 + 9/21 + 28/16
= 3/5 + 4/7 + 2/8 + 2/5 + 3/7 + 14/8
= (3/5 + 2/5) + ( 4/7 + 3/7) + ( 2/8 + 14/8)
= 1 + 1 + 7/4
= 2 + 7/4 = 15/4
c , 8/7 + 7/6 + 5/8 + 10/12 + 24/28 + 6/16
= c , 8/7 + 7/6 + 5/8 + 5/6 + 6/7 + 1/2
= (8/7 + 6/7) + (7/6 + 5/6) + 5/8 + 1/2
= 14/7 + 12/6 + 5/8 + 1/2
= 2 + 2 + 5/8 + 1/2
= 4 + 9/8 = 41/8

b)1/2*2/3*3/4*4/5*5/6*6/7*7/8*8/9*9/10
=1x2x3x4x5x6x7x8x9
2x3x4x5x6x7x8x9x10
= 1
10


\(\frac{1}{2}+\frac{2}{4}+\frac{3}{6}+\frac{4}{8}+\frac{5}{10}+\frac{6}{12}+\frac{7}{14}+\frac{8}{16}+\frac{9}{18}+\frac{10}{20}\)
\(=\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}\)
\(=\frac{1}{2}\times10\)
\(=\frac{10}{2}\)
\(=5\)
\(\frac{1}{2}\)+ \(\frac{2}{4}\)+ \(\frac{3}{6}\)+ \(\frac{4}{8}\)+ \(\frac{5}{10}\)+ \(\frac{6}{12}\)+ \(\frac{7}{14}\)+ \(\frac{8}{16}\)+ \(\frac{9}{18}\)+ \(\frac{10}{20}\)
= \(\frac{1}{2}\)+ \(\frac{1}{2}\)+ \(\frac{1}{2}\)+ \(\frac{1}{2}\)+ \(\frac{1}{2}\)+ \(\frac{1}{2}\)+ \(\frac{1}{2}\)+ \(\frac{1}{2}\)+ \(\frac{1}{2}\)+ \(\frac{1}{2}\)
= \(\frac{1}{2}\)x 10
= 5

a) \(\frac{7}{20}-\left(\frac{5}{8}-\frac{2}{5}\right)=\frac{7}{20}-\left(\frac{25}{40}-\frac{16}{40}\right)=\frac{7}{20}-\frac{9}{40}=\frac{14}{40}-\frac{9}{40}=\frac{3}{20}\)
b) \(\frac{5}{6}-\left(\frac{5}{9}-\frac{1}{4}\right)=\frac{5}{6}-\left(\frac{50}{36}-\frac{9}{36}\right)=\frac{5}{6}-\frac{41}{36}=\frac{30}{36}-\frac{41}{36}=-\frac{11}{36}\)
c) \(\frac{9}{10}-\left(\frac{2}{5}+\frac{3}{10}\right)+\frac{7}{20}\)
\(=\frac{9}{10}-\frac{2}{5}+\frac{3}{10}+\frac{7}{20}\)
\(=\frac{18}{20}-\frac{8}{20}+\frac{6}{20}+\frac{7}{20}\)
\(=\frac{23}{20}\)
Mình làm vội nên không chắc nhé ! Nhưng lớp 4 chưa học số ân thật .
a.7/20-(5/8-2/5) b.5/6-(5/9-1/4) c.9/10-(2/5+3/10)+7/20
=7/20-9/40 =5/6-11/36 =9/10-7/10+7/20
=5/40=1/8 =19/36 =2/10+7/20
=11/20
(1+2+3+4+5+6+7+8+9+10)−20:2×26(28+78)
=(1+2+3+4+5+6+7+8+9+10)−20:2×26(106)
=(1+2+3+4+5+6+7+8+9+10)−20:2×26×106
=55−20:2×26×106
=55−10×26×106
=55−2756
=−2701
đây bạn nhé
(1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10) - 20: 2 x 26 x (28 + 78)
= (10 + 1) x 10: 2 - 20: 2 x 26 x (28 + 78)
= 11 x (10 : 2) - 10 x 26 x 106
= 11 x 5 - 260 x 106
= 55 - 27560
= - 27505
Lớp 4 chưa học số âm, em nhé!