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1,
\(\frac{25}{12}+\left(\frac{-4}{12}\right)=\frac{7}{4}\)
\(\frac{-10}{8}+\frac{15}{4}=\frac{5}{2}\)
\(\frac{3}{8}+\frac{-14}{6}=\frac{-47}{24}\)
\(\frac{350}{150}+\left(\frac{-200}{360}\right)=\frac{16}{9}\)
\([\frac{5}{8}+\left(\frac{-3}{4}\right)]+\frac{15}{6}=\frac{-1}{8}+\frac{15}{6}=\frac{19}{8}\)
\(\frac{7}{3}+[\left(\frac{-5}{6}\right)+\left(\frac{-2}{3}\right)]=\frac{7}{3}+\left(\frac{-3}{2}\right)=\frac{5}{6}\)
Bài làm :
\(\frac{125^6.3^{61}.8^{10}}{4^{15}.25^9.9^{30}}\)
\(=\frac{\left(5^3\right)^6.3^{61}.\left(2^3\right)^{10}}{\left(2^2\right)^{15}.\left(5^2\right)^9.\left(3^2\right)^{30}}\)
\(=\frac{5^{18}.3^{61}.2^{30}}{2^{30}.5^{18}.3^{60}}\)
\(=3\)
Học tốt nhé
Bài làm :
Ta có :
\(\frac{125^6.3^{61}.8^{10}}{4^{15}.25^9.9^{30}}\)
\(=\frac{\left(5^3\right)^6.3^{61}.\left(2^3\right)^{10}}{\left(2^2\right)^{15}.\left(5^2\right)^9.\left(3^2\right)^{30}}\)
\(=\frac{5^{18}.3^{61}.2^{30}}{2^{30}.5^{18}.3^{60}}\)
\(=\frac{3^{61}}{3^{60}}\)
\(=3\)
a) 4 . 7^10 - 10.7^10 / 7^0
=7^10 . (4-10) / 7^10
=-6/1=-6
b)5^60.30^5 / 15^5.5^61
= 5^60 . (2 . 3. 5)^5 / (3.5)^5 . 5^61
=5^60 . 2^5 . 3^5 . 5^5 / 3^5.5^5 . 5^61
=5^65 . 2^5 . 3^5 / 3^5 . 5^5 . 5^66
=32/5
c)4^32 . 5^25 / 25^10 . 16^8
=(2^2)^32 . 5^25 / (5^2)^10 . (2^4)^8
=2^64 . 5^25 / 5^20 . 2^32
=2^32 . 5^5
d)12.3^10 + 3^11 / 3^10
=2^2 . 3 . 3^10 + 3^11 / 3^10
=2^2 . 3^11 + 3^11 / 3^10
=3^11(4+1)/3^10
=3.5=15