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câu 1:
\(\left(9x+2\right)\cdot3=50\)
\(\Leftrightarrow9x+2=\frac{50}{3}\)
\(\Leftrightarrow9x=\frac{44}{3}\)
\(\Leftrightarrow x=\frac{44}{27}\)
Câu2
\(\left(9x+5\right)\cdot4=200\)
\(\Leftrightarrow9x+5=50\)
\(\Leftrightarrow9x=45\)
\(\Leftrightarrow x=5\)
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\(9x+x=2^3\cdot5^2\)
\(10x=8\cdot25\)
\(10x=200\)
\(x=\frac{200}{10}\)
\(x=20\)
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\(-7\left(5-x\right)-2\left(x-10\right)=15\)
\(\Leftrightarrow-35+7x-2x+20=15\)
\(\Leftrightarrow5x-5=15\)
\(\Leftrightarrow5x=20\)
\(\Leftrightarrow x=4\)
Vậy \(x=4\)
\(4\left(x-1\right)-3\left(x-2\right)=-|-5|\)
\(\Leftrightarrow4x-4-3x+6=-5\)
\(\Leftrightarrow x+2=-5\)
\(\Leftrightarrow x=-7\)
Vậy \(x=-7\)
~ học tốt ~
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=>(36-25)x + (9-1)x - 9x =100
=>11x + 8x -9x =100
=>x.( 11+8-9) =100
=>x . 10 =100
=> x= 100: 10
=> x=10
Vậy x=10
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a)
<=> 3x - 3 + x - 2 = 2x - 2 - x + 1
<=> 3x + x - 2x + x = -2 + 1 + 3 + 2
<=> 3x = 4
<=> x = 4/3
Các câu sau làm tương tự
\(\left(3x-3\right)+\left(x-2\right)=\left(2x-2\right)-\left(x-1\right)\)
<=> \(3x-3+x-2=2x-2-x+1\)
<=> \(4x-5=x-1\)
<=> \(3x=4\)
<=> \(x=\frac{4}{3}\)
Vậy....
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a) 5( x + 7 ) - 10 = 23.5 b) 72 - 7( 13 - x ) = 14
5( x + 7 ) - 10 = 40 49 - 7( 13 - x ) = 14
5( x + 7 ) = 40 + 10 7( 13 - x ) = 49 - 14
5( x + 7 ) = 50 7( 13 - x ) = 35
x + 7 = 50 : 5 13 - x = 35 : 7
x + 7 = 10 13 - x = 5
x = 10 - 7 x = 13 - 5
x = 3 x = 8
c) 5x - 52 = 10 d) 9x - 2.32 = 34
5x - 25 = 10 9x - 2.9 = 81
5x = 10 + 25 9x - 18 = 81
5x = 35 9x = 81 + 18
x = 35 : 5 9x = 99
x = 7 x = 99 : 9
x = 11
~ Hok tốt ~ ( Giờ mik mới thấy bài của bạn ỌwỌ )
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a)(9x+2)x3=60
9x+2 =60:3
9x+2 =20
9x =20-2
9x=18
x=18:9
x=2
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a) ( 2x - 3 ) - ( x - 5 ) = ( x + 7 ) - ( x + 2 )
<=> 2x - 3 - x + 5 = x + 7 - x - 2
<=> x = 3
b)(7x-5)-(6x+4)=(2x+3)-(2x+1)
<=> 7x - 5 - 6x - 4 = 2x + 3 - 2x - 1
<=> x = 11
c)(9x-3)-(8x+5)=(3x+2)
<=> 9x - 3 - 8x - 5 = 3x + 2
<=> -2x = 10
<=> x = -5
d)(x+7)-(2x+3)=(3x+5)-(2x+4)
<=> x + 7 - 2x - 3 = 3x + 5 - 2x - 4
<=> -2x = -3
<=> x = 3/2
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(9x-8)=2.5
x1=10
x=10:1
x=10
(9x - 2³) : 5 = 2
9x - 2³ = 2.5
9x - 8 = 10
9x = 10 + 8
9x = 18
x = 18 : 9
x = 2