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\(a,250:\left(10-x\right)=25\\ \Rightarrow10-x=250:25\\ \Rightarrow10-x=10\\ \Rightarrow x=10-10=0\\ b,3x-2018:2=23\\ \Rightarrow3x-1009=23\\ \Rightarrow3x=23+1009\\ \Rightarrow3x=1032\\ \Rightarrow x=1032:3=344\\ c,\left(9x-21\right):3=2\\ \Rightarrow9x-21=2\times3\\ \Rightarrow9x-21=6\\ \Rightarrow9x=21+6\\ \Rightarrow9x=27\\ \Rightarrow x=27:9=3\)
\(d,53\left(9-x\right)=53\\ \Rightarrow9-x=53:53\\ \Rightarrow9-x=1\\ \Rightarrow x=9-1=8\)
\(a,250:\left(10-x\right)=25\\ \Rightarrow10-x=10\\ \Rightarrow x=0.\\b,3x-2018:2=23\\ \Rightarrow3x-1009=23\\ \Rightarrow3x=1032\\ \Rightarrow x=344. \)
a) \(250:\left(10-x\right)=25\)
\(10-x=250:25\)
\(10-x=10\)
\(x=10-10\)
\(x=0\)
b) \(3x-2018:2=23\)
\(3x-1009=23\)
\(3x=23+1009\)
\(3x=1032\)
\(x=1032:3\)
\(x=344\)
a. \(\left(27-x\right)\cdot2018=0\)
\(\left(27-x\right)=0\text{ : }2018\)
\(\left(27-x\right)=0\)
\(x=0+27\)
\(x=27\)
b. \(27\cdot x+23\cdot x=100\)
\(\left(27+23\right)\cdot x=100\)
\(50\cdot x=100\)
\(x=100\text{ : }50\)
\(x=2\)
a, (27-x).2018=0
27-x=0:2018
27-x=0
x=27-0
x=27
b,27.x+23.x=100
x.(27+23)=100
x.50=100
x=100:50
x=2
tk mk nha
\(2^{x-3}=128\Leftrightarrow2^{x-3}=2^7\Rightarrow x-3=7\Leftrightarrow x=10\)
\(\left(x+6\right)^4=4096\Leftrightarrow\left(x+6\right)^4=2^{12}=\left(2^3\right)^4=8^4\Rightarrow x+6=8\Leftrightarrow x=2\)
\(2^{2018}=\left(2^4\right)^{504}.2^2==16^{504}.4< 16^{900}\\ \)
\(17^{20}>16^{20}=\left(4^2\right)^{20}=4^{40}\)
\(3^{444}=\left(3^4\right)^{111}=81^{111}>64^{111}=\left(4^3\right)^{111}=4^{333}\\ \)
3.x-2018=23
3.x=23+2018
3.x=2041
x=2041/3
Vậy x = 2041/3