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3-/x-5/=-7+/-8/
3-/x-5/=-7+8
3-/x-5/=1
/x-5/=3-1
/x-5/=2
=>x-5=2 hoặc x-5=-2
x=5+2 x=5+(-2)
x=7 x=3
vậy x\(\in\){3;7}
\(1.\)\(3-\left|X-5\right|=-7+\left|-8\right|\)
\(3-\left|X-5\right|=-7+8\)
\(3-\left|X-5\right|=1\)
\(\left|X-5\right|=3-1\)
\(\left|X-5\right|=2\)
\(\Rightarrow X-5=2\)\(ho\text{ặ}c\)\(X-5=\left(-2\right)\)
\(N\text{ếu}\)\(X-5=2\) \(N\text{ếu}\)\(X-5=\left(-2\right)\)
\(X=5+2\) \(X=\left(-2\right)+5\)
\(X=7\) \(X=3\)
\(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}\) \(\frac{3}{5}.\frac{2}{8}+\frac{-6}{16}.\frac{2}{5}+\frac{-6}{15}:\left(-16\right)\)
\(=\frac{-5}{7}\left(\frac{2}{11}+\frac{9}{11}\right)\) \(=\frac{3}{20}+\frac{-3}{20}+\frac{1}{40}\)
\(=\frac{-5}{7}.1=\frac{-5}{7}\) \(=0+\frac{1}{40}=\frac{1}{40}\)
\(x-\frac{2}{5}=0,24\) \(\left(\frac{7}{3}x-0,6\right):3\frac{2}{5}=1\)
\(\Rightarrow x=0,24+\frac{2}{5}=\frac{16}{25}\) \(\Rightarrow\left(\frac{7}{3}x-0,6\right):\frac{17}{5}=1\)
vậy x = 16/25 \(\Rightarrow\frac{7}{3}x-0,6=\frac{17}{5}\)
\(\Rightarrow\frac{7}{3}x=\frac{17}{5}+0,6=4\)
\(\Rightarrow x=4:\frac{7}{3}=\frac{12}{7}\)
vậy x = 12/7
( 15 - x ) + ( x - 12 ) = ( -5 + x )
( 15 - 12 ) - x + x = -5 + x
3 = -5 + x
x = 3 + 5
x = 8
(x+1)+(x+3)+(x+5)+...+(x+99)=0
( x + x + x + .... + x ) + ( 1 + 3 + 5 + ... + 99 ) = 0
50x + 2500 = 0
50x = -2500
x = -2500 : 50
x = -50
bài 2
a) 2448:[119-(x-6)]=24
119-(x-6)=2448:24
119-(x-6)=102
x-6=119-102
x-6=17
x=17+6
x=23
\(a)\)
\(x+\frac{1}{10}+x+\frac{11}{11}=x+\frac{11}{12}\)
\(\Leftrightarrow x=\frac{11}{12}-\frac{1}{10}-\frac{11}{11}\)
\(\Leftrightarrow x=\frac{-11}{60}\)
\(b)\)
\(-\left|x-\frac{1}{2}\right|=\frac{1}{2}\)
\(\Leftrightarrow\left|x-\frac{1}{2}\right|=\frac{-1}{2}\) (Vô lý)
Vậy \(x\in\varnothing\)
1/
$20\vdots 2x-1$
$\Rightarrow 2x-1$ là ước của $20$. Mà $2x-1$ lẻ và $2x-1\geq -1$ với mọi $x$ tự nhiên
$\Rightarrow 2x-1\in \left\{\pm 1; 5\right\}$
$\Rightarrow x\in \left\{0; 1; 3\right\}$
2/
$120\vdots 5x+1$
$\Rightarrow 5x+1$ là ước của $120$
Mà $5x+1\geq 1$ với mọi $x$ tự nhiên
$\Rightarrow 5x+1\in \left\{1;2; 3;4; 5;6; 8; 10;12; 15; 20; 24; 30; 40; 60;120\right\}$
$\Rightarrow x\in \left\{0; \frac{1}{5}; \frac{2}{5}; \frac{3}{5}; \frac{4}{5}; 1; \frac{7}{5}; \frac{9}{5}; \frac{11}{5}; \frac{14}{5}; \frac{19}{5}; \frac{23}{5}; \frac{29}{5}; \frac{39}{5}; \frac{59}{5}; \frac{119}{5}\right\}$
Do $x$ tự nhiên nên $x\in \left\{0; 1\right\}$
a) x + 30%x = -1,31
(1 + 30%)x = -1,31
13/10x = -1,31
x = -1,31 : 13/10
x = -131/130
b) (x - 1/2) : 1/33 + 5/7 = 68/7
(x - 1/2) : 1/33 = 68/7 - 5/7
(x - 1/2) : 1/33 = 9
(x - 1/2) = 9 x 1/33
x - 1/2 = 3/11
x = 3/11 + 1/2
x = 17/22
c) (4,5 - 2x) . ( -11) = 11/14
(4,5 - 2x) = 11/14 : (-11)
(4,5 - 2x) = -1/14
2x = 4,5 + 1/14
2x = 32/7
x = 16/7
a,x + 30%x = -1,31
x.130%= -1,31
x = -131/130
b, (x-1/2) : 1/33 + 5/7 = 68/7
(x-1/2) . 33 = 68/7 -5/7
(x-1/2).33 = 9
x-1/2 = 9:33
x-1/2 = 3/11
x = 3/11 + 1/2
x =17/22
c,(4,5 - 2x).(-11) = 11/14
4,5 - 2x = 11/14 : (-11)
4,5 - 2x = -1/14
2x = 4,5 -(-1/14)
2x = 32/7
\(\dfrac{11}{2}\cdot2+x=\dfrac{1}{7}\\ 11+x=\dfrac{1}{7}\\ x=\dfrac{1}{7}-11\\ x=\dfrac{1}{7}-\dfrac{77}{7}\\ x=\dfrac{-76}{77}\)
\(\dfrac{11}{2}.2+x=\dfrac{1}{7}\)
\(11+x=\dfrac{1}{7}\)
\(x=\dfrac{1}{7}-11\)
\(x=-10\dfrac{6}{7}\)