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a) 19 x 64 + 76 x 34 = 19 x 64 + 19 x 4 x 34 = 19 x (64 + 4 x 34) = 19 x 200 = 3800
b) 35 x 12 + 65 x 13 = 35 x 12 + 65 x 12 + 65 = 12 x (35 + 65) + 65 = 12 x 100 + 65 = 1265
c) 136 x 68 + 16 x 272 = 136 x 68 + 16 x 2 x 136 = 136 x (68 + 16 x 2) = 136 x 100 = 13600
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136 x 68 + 16 x 272
= 136 x 68 + 16 x 2 x 136
= 136 x 68 + 32 x 136
= ( 68 + 32 ) x 136
= 100 x 136
= 13600
136 x 68 + 16 x 272
= 136 x 68 + 16 x 2 x 136
= 136 x 68 + 32 x 136
= ( 68 + 32 ) x 136
= 100 x 136
= 13600
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a. 19.64 + 76.34 = 19.64 + 19.4.34 = 19.64 + 19.136 = 19.(136 + 64) = 19.200 = 3800
b. 35.12 + 65.13 = 35.12 + 65.(12 + 1) = 35.12 + 35.12 + 65 = (35 + 65).12 + 65 = 1200 + 65 = 1265
c. 136.68 + 16.272 = 136.68 + 16.136.2 = 136.68 + 136.32 = 136.(68 + 32) = 136.100 = 13600
d. (2 + 4 + 6 + ... + 100) x (36 x 333 - 108 x 111) = (2 + 4 + 6 + ... + 100) x 0 = 0
e. 19991999 x 1998 - 19981998 x 1999 = 1999 x 10001 x 1998 - 1998 x 10001 x 1999 = 0
a) 19 .64 + 76.34
= 19.64 + 19.4.34
= 19(64 + 4.34)
= 19.200 = 3800
b) 35.12 + 65.13
= 35.12 + 65.12 + 65
= 12(35 + 65) + 65
= 12.100 + 65 = 1265
c) 136.68 + 16.272
= 136.68 + 16.2.136
= 136(68 + 16.2)
= 136.100= 13600
d) ( 2 + 4 + 6 + ...... + 100 ).( 36 x 333 - 108 x 111 )
= ( 2 + 4 + 6 + ...... + 100 ).(36.3.111 - 108.1110
= ( 2 + 4 + 6 + ...... + 100 ).(108.111 - 108.111)
= ( 2 + 4 + 6 + ...... + 100 ).0 = 0
e ) 19991999 x 1998 - 19981998 x 1999
= 1999.10001.1998 - 1998.10001.1999 = 0
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m, 136.48 + 16:272 + 68.20.2
xem lại đề đi em
n, 35.34 + 35.86 + 65.75 + 65.45
= (35.34 + 35.86) + (65.75 + 65.45)
= 35.(34 + 86) + 65.(75 + 45)
= 35. 120 + 65.120
= 120.(35 + 65)
= 120.100
= 12000
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a ; 29 x 64 +116 x 34
= 29 x 2 x 32 + 116 : 2 x 2 x 34
= 58 x 32 + 58 x 68
= 58 ( 32 + 68)
= 58 x 100
= 5800
b, 136 x 68 + 16 x 272
= 136 x 68 + 16 x 2 x 136
= 136 x 68 + 136 x 32
= 136 ( 68 + 32)
= 136 x 100
= 13600
![](https://rs.olm.vn/images/avt/0.png?1311)
a ) x + 16 chia hết cho x + 1
=> x + 1 + 15 chia hết cho x + 1
=> x + 1 thuộc Ư ( 15 )
Ư ( 15 ) = { 1;3;5;15 }
Ta có :
x + 1 = 1 => x = 0
x + 1 = 3 => x = 2
x + 1 = 5 => x = 4
x + 1 = 15 => x = 14
Vậy x thuộc {0;2;4;14 }
b )
x + 11 chia hết cho x + 1
=> x + 1 + 10 chia hết cho x + 1
=> x + 1 thuộc Ư ( 10 )
Ư ( 10 ) = { 1;2;5;10 }
Ta có :
x + 1 = 1 => x = 0
x + 1 = 2 => x = 1
x + 1 = 5 => x = 4
x + 1 = 10 => x = 9
Vậy x thuộc {0;1;4;9 }
Nhớ tick mik nha !!!
a) x+16 = (x+1) + 15 chia hết cho x+1
=> 15 chia hết cho x+1
=> x+1 thuộc U(15) = {1;3;5;15}
=> x thuộc { 0;2;4;14}
b) x+11 = (x+1) +10 chia hết cho x+1
=> 10 chia hết cho x+1
=> x +1 thuộc U(10) ={1;2;5;10}
=> x thuộc {0;1;4;9}
![](https://rs.olm.vn/images/avt/0.png?1311)
19 x 64 + 76 x 34
= 19 x 64 + 19 x 4 x 34
= 19 x (64 + 4 x 34)
= 19 x 200
= 3 800
*****
35 x 12 + 65 x 13
= 35 x 12 + 65 x (12 + 1)
= 35 x 12 + 65 x 12 + 65
= 12 x (35 + 65) + 65
= 12 x 100 + 65
= 1 200 + 65
= 1 265
*****
136 x 68 + 16 x 272
= 136 x 68 + 16 x 4 x 68
= 68 x (136 + 16 x 4)
= 68 x (136 + 64)
= 68 x 200
= 13 600
*****
(2 + 4 + 6 + ... + 100) x (36 x 333 - 108 x 111)
= (2 + 4 + 6 + ... + 100) x (36 x 111 x 3 - 36 x 3 x 11)
= (2 + 4 + 6 + ... + 100) x 0
= 0
*****
19991999 x 1998 - 19981998 x 1999
= 10 001 x 1999 x 1998 - 1998 x 10 001 x 1999
= 0
\(136\times48+16\times272+68\times20\times2\\ =136\times\left(48+32+20\right)\\ =136\times100\\ =13600.\)
\(136\times48+16\times272+68\times20\times2\)
\(=136\times48+16\times2\times136+136\times20\)
\(=136\times48+32\times136+136\times20\)
\(=136\times\left(48+32+20\right)\)
\(=136\times100\)
\(=13600\)