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mình phân phối rồi nhưng rắc rối lắm, bn làm giúp mình 1 câu thôi nhé
ban hay su dung quy tac chuyen ve de pha ngoac sau do lay 73 +(-73) roi lan luot su dung tinh chat phan phoi se giai,
dap an 112
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mình làm ý a hen
25-(30-7)+75-47
=25-(30-7)+28
=25-23+28
=2+28
=30
\(25-\left(30-7\right)+75-47\)
\(=25-30+7+75-47\)
\(=30\)
\(\left(-54-91\right)-\left(59-74\right)\)
\(=-54-91-59+74\)
\(=-130\)
câu kia tương tự nha
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65-63+61-59+...+53-51+49
(65-63)+(61-59)+...+(53-51)+49
=(2+2+...+2)+49
=8+49=57
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=(-359+181)+(-123)+(-172+350)
=-178 +(-123)+178
=(-178+178)+(-123)
=0+(-123)=-123
a)-59+181+-123+350+(-172)
=(-59+181)+[-123+350+(-172)]
=122+55=177
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\(a)\)
= [41 x 54 + 56 x 41] + [59 x 13 + 59 x 97]
= 41 x [54 +56] + 59 x [13 +97]
=41 x 110 + 59 x 110
= 110 x [41 + 59]
= 110 x 100
= 11000
\(b)\)
= 100 -[ 3 x216 - 4 x 25 ] x 20170
= 100 - [648 - 100] x 1
= 100 -548
= -448
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2 . 53 . 27 + 6 . 9 . 87 - 3 . 18 . 40
= 2. 53 . 9 . 3 + 2. 3 .9 .87 - 3 .2 .9 .40
= 54.53+54.87-54.40
=54(53+87-40)
=54. 100=5400
12 . 25 + 29 . 25 + 59 . 25
= 25 . ( 12+29+59)
=25 . 90
=2250
43 . 37 + 93 . 43 + 57 . 61 + 69 . 57
= 43.(37+93)+57(61+69)
=43.130+57.130
=130.(43+57)
=130.100
=13 000
12 . 53 + 53 . 172 - 53
=53(12+172-1)
=53.184
=9752
35 . 54 + 35 . 58 + 65 . 75 + 65 . 45
=35(54+58)+65(75+45)
=35.112+65.120
=3920+7800
=11720
39 . 8 + 70 . 3 + 31 . 8
=8(39+31)+70.3
=8.70+70.3
=70.(8+3)
=70.11
=770
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\(1+2+3+...+n=\frac{n\left(n+1\right)}{2}\)
\(1+3+5+7+...+\left(2n-1\right)=n^2\)
\(2+4+6+8+...+2n=n\left(n+1\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Đặt \(A=\frac{1}{9}+\frac{2}{8}+...+\frac{8}{2}+\frac{9}{1}\)
\(\Rightarrow A=\frac{1}{9}+\frac{2}{8}+\frac{3}{7}+...+\frac{8}{2}+\left(1+1+...+1\right)\left(9cs1\right)\)
\(\Rightarrow A=\left(\frac{1}{9}+1\right)+\left(\frac{2}{8}+1\right)+...+\left(\frac{8}{2}+1\right)+1\)
\(\Rightarrow A=\frac{10}{9}+\frac{10}{8}+...+\frac{10}{2}+\frac{10}{10}\)
\(\Rightarrow A=10.\left(\frac{1}{2}+...+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}\right)\)
Mà \(\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{10}\right).x=A\)
\(\Rightarrow\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right).x=\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right).10\)
\(\Rightarrow x=10\)
Vậy \(x=10\)
![](https://rs.olm.vn/images/avt/0.png?1311)
= \(\frac{17}{8}:\frac{25}{14}-\left(15-\frac{40}{3}\right):\frac{25}{6}\)
= \(\frac{17}{8}.\frac{14}{25}-\left(\frac{45}{3}-\frac{40}{3}\right).\frac{6}{25}\)
= \(\frac{119}{100}-\frac{5}{3}.\frac{6}{25}\) = \(\frac{119}{100}-\frac{2}{5}\)
= \(\frac{119}{100}-\frac{40}{100}=\frac{79}{100}\)
Chúc bạn Hk tốt!!!!!
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