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1.\(\dfrac{8}{11}+\dfrac{8}{33}\times\dfrac{3}{4}=\dfrac{8}{11}+\dfrac{8\times3}{33\times4}=\dfrac{8\times12}{11\times12}+\dfrac{8\times3}{33\times4}=\dfrac{8\times15}{132}=\dfrac{120}{132}=\dfrac{10}{11}\)
2.\(\dfrac{7}{9}\times\dfrac{3}{14}:\dfrac{5}{8}=\dfrac{7}{9}\times\dfrac{3}{14}\times\dfrac{8}{5}=\dfrac{4}{15}\)
3.\(\dfrac{5}{12}-\dfrac{7}{32}:\dfrac{21}{16}=\dfrac{5}{12}-\dfrac{7}{32}\times\dfrac{16}{21}=\dfrac{5}{12}-\dfrac{1}{6}=\dfrac{5-2}{12}=\dfrac{3}{12}=\dfrac{1}{4}\)
`@V.Tr.V`
a) \(\dfrac{3}{5}+\dfrac{7}{25}=\dfrac{15}{25}+\dfrac{7}{25}=\dfrac{15+7}{25}=\dfrac{22}{25}\)
b) \(\dfrac{8}{11}-\dfrac{19}{33}=\dfrac{24}{33}-\dfrac{19}{33}=\dfrac{24-19}{33}=\dfrac{5}{33}\)
c) \(\dfrac{16}{21}\times\dfrac{3}{5}=\dfrac{16\times3}{21\times5}=\dfrac{48}{105}=\dfrac{16}{35}\)
d) \(\dfrac{14}{41}\div\dfrac{7}{9}=\dfrac{14}{41}\times\dfrac{9}{7}=\dfrac{14\times9}{41\times7}=\dfrac{126}{287}=\dfrac{18}{41}\)
\(a)\frac{2}{5}+\frac{3}{10}-\frac{1}{2}\)
\(=\frac{4}{10}+\frac{3}{10}-\frac{5}{10}=\frac{1}{5}\)
\(b)\frac{8}{11}+\frac{8}{33}.\frac{3}{4}\)
\(=\frac{8}{11}+\frac{2}{11}=\frac{10}{11}\)
\(c)\frac{7}{9}.\frac{3}{14}:\frac{5}{8}\)
\(=\frac{1}{6}:\frac{5}{8}=\frac{4}{15}\)
\(d)\frac{5}{12}-\frac{7}{32}:\frac{21}{16}\)
\(=\frac{5}{12}-\frac{1}{6}=\frac{5}{12}-\frac{2}{12}=\frac{1}{4}\)
2/5 + 3/10 - 1/2
= 4/10 + 3/10 -5/10
=2/10
=1/5.
8/11 + 8/33 *3/4
=8/11 + 2/11
=10/11
7/9 *3/14 : 5/8
=1/3 *1/2 : 5/8
=1/6: 5/8
=1/3 * 4/5
=4/15
5/12 - 7/32 : 21/16
=5/12 - 1/6
=5/12 - 2/12
=1/4
98775 - 32 x 85
=98775 -2720
=96055
67500 - 24 x 236
= 67500 -5664
=61836
568 + 101598 : 287
= 568 +354
=922
6875 + 980 -180
=7855 -180
=7675
\(\dfrac{2}{5}+\dfrac{3}{10}-\dfrac{1}{2}\)
\(=\dfrac{7}{10}-\dfrac{1}{2}\)
= \(\dfrac{1}{5}\)
\(\dfrac{8}{11}+\dfrac{8}{33}x\dfrac{3}{4}\)
\(=\dfrac{8}{11}+\dfrac{2}{11}\)
\(=\dfrac{10}{11}\)
\(\dfrac{7}{9}x\dfrac{3}{14}:\dfrac{5}{8}\)
\(=\dfrac{1}{6}:\dfrac{5}{8}\)
\(=\dfrac{1}{6}x\dfrac{8}{5}\)
\(=\dfrac{8}{30}\)
\(=\dfrac{4}{15}\)
\(\dfrac{5}{12}-\dfrac{7}{32}:\dfrac{21}{16}\)
\(=\dfrac{5}{12}-\dfrac{7}{32}x\dfrac{16}{21}\)
\(=\dfrac{5}{12}-\dfrac{1}{6}\)
\(=\dfrac{5}{12}-\dfrac{2}{12}\)
\(=\dfrac{3}{12}=\dfrac{1}{4}\)
\(\frac{3}{7}x\frac{16}{33}+\frac{16}{33}x\frac{4}{7}\)
\(C1:=\frac{16}{77}+\frac{64}{231}=\frac{16}{33}\)
\(C2:=\frac{16}{33}\left(\frac{3}{7}+\frac{4}{7}\right)=\frac{16}{33}.1=\frac{16}{33}\)
học tốt ~~~
C1:3/7×16/33+16/33×4/7
=48/231+64/231
=112/231
C2:3/7×16/33+16/33×4/7
=16/33×(3/7+4/7)
=16/33×7/7
=113/231
Cách 1:
\(\dfrac{3}{7}\) x \(\dfrac{16}{33}\) + \(\dfrac{16}{33}\) x \(\dfrac{4}{7}\)
= \(\dfrac{48}{231}\) + \(\dfrac{64}{231}\)
= \(\dfrac{112}{231}\)
= \(\dfrac{16}{33}\)
cách 2: \(\dfrac{3}{7}\) x \(\dfrac{16}{33}\) + \(\dfrac{16}{33}\) x \(\dfrac{4}{7}\)
= \(\dfrac{16}{33}\) x ( \(\dfrac{3}{7}\) + \(\dfrac{4}{7}\))
= \(\dfrac{16}{33}\) x \(\dfrac{7}{7}\)
= \(\dfrac{16}{33}\)
Cách 1: (Tính bình thường)
= 16/77 + 64/231 (Quy đồng đi nha, mẫu chung là 231)
= 16/33
Cách 2: (Tính nhanh)
= 16/33 x ( 3/7 + 4/7 )
= 16/33 x 1
= 16/33
=17,49
3/16 + 14/33
= 99/528 + 224/528
= 323/528