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Đặt:
\(X=\left(1+\dfrac{1}{9}\right)\left(1+\dfrac{1}{10}\right)\left(1+\dfrac{1}{11}\right).....\left(1+\dfrac{1}{200}\right)\)
\(X=\dfrac{10}{9}.\dfrac{11}{10}.\dfrac{12}{11}......\dfrac{201}{200}\)
\(X=\dfrac{10.11.12......201}{9.10.11......200}\)
\(X=\dfrac{201}{9}\)
\(Y=\left(1-\dfrac{1}{10}\right)\left(1-\dfrac{1}{11}\right)\left(1-\dfrac{1}{12}\right).....\left(1-\dfrac{1}{99}\right)\)
\(Y=\dfrac{9}{10}.\dfrac{10}{11}.\dfrac{11}{12}.....\dfrac{98}{99}\)
\(Y=\dfrac{9.10.11......98}{10.11.12.....99}\)
\(Y=\dfrac{9}{99}=\dfrac{1}{11}\)
=\(\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.\dfrac{4}{5}....\dfrac{2016}{2017}.\dfrac{2017}{2018}\)
\(\dfrac{1.2.3.4....2017}{2.3.4....2017.2018}\)
=\(\dfrac{1}{2018}\)
\(\text{Ta có: }\) \(\frac{1}{4}x+\frac{1}{8}x+\frac{1}{16}x=1\)
\(\Rightarrow\left(\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)x=1\)
\(\Rightarrow\frac{7}{16}x=1\)
\(\Rightarrow x=1:\frac{7}{16}\)
\(\Rightarrow x=\frac{16}{7}\)
Tìm x :
a, 1/4 * x + 1/8 * x + 1/16 * x = 1
x * ( 1/4 + 1/8 + 1/16 ) = 1
x * 7/16 = 1
x = 1 : 7/16
x = 16/7
b, 1/5 + 1/3 x ( x + 1 ) = 1/4
1/3 x ( x + 1 ) = 1/4 - 1/5
1/3 x ( x + 1 ) = 1/20
x + 1 = 1/20 : 1/3
x + 1 = 3/20
x = 1 - 3/20
x = 7/20
Tính nhanh :
1/5 x 27 + 1/5 x 33 + 1/5 x 40
= 1/5 x ( 27 + 33 + 40 )
= 1/5 x 100
= 20
Ta có:
\(\dfrac{2x+1}{x-1}=\dfrac{2x-2+3}{x-1}=\dfrac{2\left(x-1\right)+3}{x-1}=2+\dfrac{3}{x-1}\)
Để \(2x+1\) chia hết cho x-1 thì:
\(x-1\in U\left(3\right)=\left\{1;-1;3;-3\right\}\)
Ta có bảng:
\(x-1\) | 1 | -1 | 3 | -3 |
x | 2 | 0 | 4 | -2 |
Vậy: \(x\in\left\{0;2;-2;4\right\}\)
Giải:
a) \(\left(1-\dfrac{1}{2}\right).\left(1-\dfrac{1}{3}\right).\left(1-\dfrac{1}{4}\right).\left(1-\dfrac{1}{5}\right)\)
\(=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.\dfrac{4}{5}\)
\(=\dfrac{1.2.3.4}{2.3.4.5}\)
\(=\dfrac{1}{5}\)
b) \(\left(1-\dfrac{3}{4}\right).\left(1-\dfrac{3}{7}\right).\left(1-\dfrac{3}{10}\right).\left(1-\dfrac{3}{13}\right).....\left(1-\dfrac{3}{97}\right).\left(1-\dfrac{3}{100}\right)\)
\(=\dfrac{1}{4}.\dfrac{4}{7}.\dfrac{7}{10}.\dfrac{10}{13}.....\dfrac{94}{97}.\dfrac{97}{100}\)
\(=\dfrac{1.4.7.10.....94.97}{4.7.10.13.....97.100}\)
\(=\dfrac{1}{100}\)
Chúc bạn học tốt!
\(\left(1+\dfrac{1}{2}\right)\times\left(1+\dfrac{1}{3}\right)\times\left(1+\dfrac{1}{4}\right)\times....\times\left(1+\dfrac{1}{98}\right)\times\left(1+\dfrac{1}{99}\right)\)
\(=\dfrac{3}{2}\times\dfrac{4}{3}\times\dfrac{5}{4}\times...\times\dfrac{99}{98}\times\dfrac{100}{99}\)
\(=\dfrac{1\times100}{2\times1}\)
\(=\dfrac{100}{2}\\ =50\)
\(\left(\dfrac{1}{2}-1\right)\left(\dfrac{1}{3}-1\right)\left(\dfrac{1}{4}-1\right)......\left(\dfrac{1}{99}-1\right)\left(\dfrac{1}{100}-1\right)\)
\(=\left(-\dfrac{1}{2}\right)\left(-\dfrac{2}{3}\right)\left(-\dfrac{3}{4}\right)......\left(-\dfrac{98}{99}\right)\left(-\dfrac{99}{100}\right)\)
\(=\dfrac{1}{100}\) ( do có 100 số hạng nên tích ra 1 số dương nhé ! ( chẵn mà )
Nhi có 10 viên bi,Nhi cho Oanh 5 viên bi.Hỏi Nhi còn lại bao nhiêu viên bi?
`(x-1)^2=1`
`(x-1)^2=1^2`
`=>x-1=1` hoặc `x-1=-1`
`=>x=2` hoặc `x=0`
Vậy `x=2` hoặc `x=0`
`(x-1)^2 =1`
`=> (x-1)^2 = (+-1)^2`
\(\Rightarrow\left[{}\begin{matrix}x-1=1\\x-1=-1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=2\\x=0\end{matrix}\right.\)