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Chất thứ 2 trong sơ đồ phải là Al2O3 bạn nhé!
\(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)
\(2Al_2O_3\underrightarrow{đpnc}4Al+3O_2\)
\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
\(Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_{4\downarrow}\)
Bạn tham khảo nhé!
\(1) 2Fe(OH)_3 \xrightarrow{t^o} Fe_2O_3 + 3H_2O\\ 2) Na_2O + H_2SO_4 \to Na_2SO_4 + H_2O\\ 3) ZnO + H_2SO_4 \to ZnSO_4 + H_2O\\ 4) NaOH + HCl \to NaCl + H_2O\\ 5) 2NaOH + CO_2 \to Na_2CO_3 + H_2O\\ 6) Mg + 2HCl \to MgCl_2 + H)2\\ 7) Cu + 2AgNO_3 \to Cu(NO_3)_2 + 2Ag\\ 8) 2K + S \xrightarrow{t^o} K_2S\)
1, $2Fe(OH)_3\xrightarrow{t^o} Fe_2O_3+3H_2O$
2, $H_2SO_4+2NaOH\to Na_2SO_4+2H_2O$
3, $H_2SO_4+Zn(OH)_2\to ZnSO_4+2H_2O$
4, $NaOH+HCl\to NaCl+H_2O$
5, $2NaOH+CO_2\to Na_2CO_3+H_2O$
6, $Mg+2HCl\to MgCl_2+H_2$
7, $Cu+2AgNO_3\to Cu(NO_3)_2+2Ag$
8, $2K+S\xrightarrow{t^o} K_2S$
CH4 + 2O2 -> (t°) CO2 + 2H2O
C2H2 + 2Br2 -> C2H2Br4
CH4 + Cl2 -> (askt) CH3Cl + HCl
2C2H2 + 5O2 -> (t°) 4CO2 + 2H2O
C2H4 + Br2 -> C2H4Br2
nCH2=CH2 -> (t°, p, xt) n(-CH2-CH2-)
C2H4 + 3O2 -> (t°) 2CO2 + 2H2O
1) 3Fe+3Cl2 -) 2FeCl3
2) FeCl3+3NaOH -) Fe(OH)3+3Nacl
3) 2Fe(OH)3 -t độ-) Fe2O3 + 3H20
4) Fe2O3+ 3H2SO4 -) Fe2(SO4)3 + 3H2O
5) Fe2(SO4)3 + 3Bacl2 -) 2FeCl3 + 3BaSO4
(1) 2Al2O3 + 9C \(^{3000^oC}\rightarrow\) Al4C3 + 6CO
(2) CO + CuO \(^{to}\rightarrow\) Cu + CO2 \(\uparrow\)
(3)Al(OH)3 + NaOH -> NaAlO2 + 2H2O
Al(OH)3 +3 HCl -> AlCl3 + 3H2O
(4)Al4C3 + 5H2O -> 2Al2O3 + 3CH4
(5) 2CH4 + Cl2 -> HCl + CH3Cl
(6)CH3Cl + \(\dfrac{3}{2}\)O2 -> H2O + HCl + CO2
\(Ca+2C\underrightarrow{t^o}CaC_2\\ CaC_2+2H_2O\rightarrow C_2H_2+2H_2O\\ C_2H_2+2Br_2\rightarrow C_2H_2Br_4\)
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\(MnO_2+4HCl\rightarrow MnCl_2+2H_2O+Cl_2\\ 2Fe+3Cl_2\underrightarrow{t^o}2FeCl_3\\ 2FeCl_3\underrightarrow{đpnc}2Fe+3Cl_2\)
$C + O_2 \xrightarrow{t^o} CO_2$
$CO_2 + Ca(OH)_2 \to CaCO_3 + H_2O$
$CaCO_3 + 2HCl \to CaCl_2 + CO_2 + H_2O$
$CO_2 + C \to 2CO$
$C_2H_4 + H_2O \xrightarrow{t^o,H^+} C_2H_5OH$
$C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O$
$CH_3COOH + C_2H_5OH \buildrel{{H_2SO_4,t^o}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O$
$CH_3COOC_2H_5 + NaOH \to CH_3COONa + C_2H_5OH$
\(MnO_2+4HCl_đ\underrightarrow{t^o}MnCl_2+Cl_2+2H_2O\)
\(Cl_2+H_2\underrightarrow{t^o}2HCl\)
\(HCl+NaOH\rightarrow NaCl+H_2O\)
\(2NaCl+2H_2O\xrightarrow[cmn]{đpdd}2NaOH+Cl_2+H_2\)
MnO2 + 4HCl →→ MnCl2 + Cl2 + 2H2O
Cl2 + H2 →→ 2HCl
HCl + NaOH →→ NaCl + H2O
2NaCl + 2H2O →���đ���đpddcmn 2NaOH + H2 + Cl2