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27.75 +25.27 -150
= 27. ( 75+25 ) -150
= 27.100 - 150
= 2700 - 150 = 2550
2, 34.35 -25 .12 + 105
= 1190 - 300 + 105
= 890 + 105 = 995
51.8 + 25.15 - 63
=408 + 375 - 63
= 783 - 63
= 720
4,918 : 9 + 20 . 46 - 132
=102 + 20 . 46 - 132
= 102 + 920 - 132
= 1022 - 132
= 890
a) x = 25 - 16
x = 9
b) 2x = 156-82
2x = 74
x = 74 : 2
x = 37
c) 150 : (18-x) = 150-125
150 : (18-x) = 25
18-x = 150 : 25
18-x = 6
x =18-6
x= 12
d) 6.6 :x = 8-4
36 : x = 4
x =36:4
x = 9
e)(99x-x) : 2+1= 50x
Ta có:
50x + (1+3+5+7+9+.....+99)=75.10.10
50x + (99+1).50:2 =7500
50x + 2500=7500
50x=7500-2500
50x=5000
x =5000:50
x = 100
Tim x € N biet :
a / x + 16 = 25
=> x = 25 - 16
=> x = 9
b / 156 - 2x = 82
=> 2x = 156 - 82
=> 2x = 74
=> x = 37
c / 150 -150 : ( 18 - x ) = 125
=> 150 : ( 18 - x ) = 125 -150
=> 150 : ( 18 - x ) = - 25
=> 18 - x = -6
=> x = 18 - ( -6 )
=> x = 24
d / 62 : x = 23 - 4
=> 36 : x = 8 - 4
=> 36 : x = 4
=> x = 36 : 4
=> x = 9
e / x + 3x + 5x + ................. +99x = 75 × 102
=> x + 3x + 5x +....+ 99x = 7500
=> x. ( 1 + 3 + 5 +....+ 99 ) = 7500
Số các số hạng là : ( 99 - 1 ) : 2 + 1 = 50
=> Số cặp là : 50 : 2 = 25
Ta có:
x. ( 1 + 3 + 5 +....+ 99 ) = 7500
=> x. [ ( 1 + 99 ) + ( 2 + 98 ) +.... ] = 7500
=> x. 100 .25 =7500
=> x. 2500 = 7500
=> x = 7500 : 2500
=> x = 3
\(\frac{x}{8}=\frac{y}{12}=\frac{2x+3y}{16+36}=\frac{-156}{52}=-3\)
x=-3.8=-24
y=-3.12=-36
Ta có : \(\frac{x}{8}=\frac{y}{12}=\frac{2x}{16}=\frac{3y}{36}=\frac{2x+3y}{16+36}=\frac{-156}{52}=-3\)
=> x = -3.8 = -24 ; y = -3.12 = -36
\(S=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{132}+\frac{1}{156}\)
\(S=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{11.12}+\frac{1}{12.13}\)
\(S=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}\)
\(S=\frac{1}{1}-\frac{1}{13}\)
\(S=\frac{12}{13}\)
\(S=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{12.13}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+.....+\frac{1}{12}-\frac{1}{13}\)
\(=1-\frac{1}{13}\)
\(=\frac{12}{13}\)
=> 2.( 1 + 2 + 3 + .... + x ) = 156
=> 2.{ [ x.( x + 1 ) ] : 2 } = 156
=> [ x.( x + 1 ) ] : 2 = 156 : 2
=> x.( x + 1 ) = 156 = 12.( 12 + 1 )
=> x .( x + 1 ) = 12.( 12 + 1 )
=> x = 12
2.1+2.2+2.3+2.4+....+2.x
=2.(1+2+3+4+.....+x)=156
1+2+3+4+.........+x=78
=> x=12 nha!
\(\left(-150\right)+156+3+100.9\\ =\left(-150\right)+156+3+900\\ =6+3+900\\ =909\)
=6+3+100.9
=6+3+(100.1).9
=6+3+1+100.9
=6+4+100.9
=10+900
=910