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\(\dfrac{3}{11}\text{×}\dfrac{7}{19}+\dfrac{3}{11}\text{×}\dfrac{10}{19}+\dfrac{3}{11}\text{×}\dfrac{1}{19}=\dfrac{3}{11}\text{×}\left(\dfrac{7}{19}+\dfrac{10}{19}+\dfrac{2}{19}\right)=\dfrac{3}{11}\text{×}1=\dfrac{3}{11}\)
a) \(19\times\left(52+38\right)-9\times\left(52+38\right)=\)
\(=\) \(19\times90-9\times90\)
\(=90\times\left(19-9\right)\)
\(=90\times10\)
\(=900\)
b) \(\dfrac{2}{5}\div\dfrac{3}{7}\times\dfrac{3}{7}\div\dfrac{2}{5}+2019=\)
\(=\left(\dfrac{2}{5}\div\dfrac{2}{5}\right)\times\left(\dfrac{3}{7}\div\dfrac{3}{7}\right)+2019\)
\(=1\times1+2019\)
\(=2019\)
\(\left(a\right)\frac{3}{5}\cdot\frac{8}{21}\cdot\frac{5}{3}=\left(\frac{3}{5}\cdot\frac{5}{3}\right)\cdot\frac{8}{21}=1\cdot\frac{8}{21}=\frac{8}{21}\)
(b) sai đề
\(\left(c\right)x\cdot\frac{1}{2}=\frac{1}{3}\)
\(x=\frac{\frac{1}{3}}{\frac{1}{2}}=\frac{2}{3}\)
\(\left(d\right)\frac{x}{\frac{4}{5}}=\frac{5}{2}\)
\(x=\frac{5}{2}\cdot\frac{4}{5}=2\)
\(\left(e\right)\frac{\frac{2}{9}}{x}=\frac{2}{3}\)
\(x=\frac{\frac{2}{9}}{\frac{2}{3}}=\frac{1}{3}\)
a) ( 2/5 + 3/5) + 7/8
= 5/5 +7/8
= 1+ 7/8
=15/8 ( tính lại hộ mk nha, sợ ko đúng)
b)( 19/11 + 3/11 ) + 5/13
= 22/11 +5/13
= 2 + 5/13
= ...( bn tính nốt nha, vì mk ko có nháp ở đây )
k nha!!!
a) (2/5 + 7/8) + 3/5
= 2/5 + 7/8 + 3/5
= (2/5 + 3/5) + 7/8
= 1 + 7/8
= \(1\frac{7}{8}\)
b) 19/11 + (5/13 + 3/11)
= 19/11 + 5/13 + 3/11
= (19/11 + 3/11) + 5/13
= 2 + 5/13
= \(2\frac{5}{13}\)
\(\dfrac{14}{19}+\dfrac{5}{19}-\dfrac{5}{7}+\dfrac{47}{7}=\dfrac{19}{19}+\dfrac{42}{7}=1+6=7\)
= 7/19 x (1/3 + 2/3)
= 7/19 x 1 = 7/19
`7/19 xx 1/3+7/19 xx 2/3`
`=7/19 xx(1/3+2/3)`
`=7/19 xx 3/3`
`=7/19 xx 1`
`=7/19`