Question

[Nhã Đan 6/8_04 Đỗ Nguyễn]

x \(\dfrac{2}{3}\)=\(\dfrac{1}{5}\)

\(\dfrac{2}{x}\)=\(\dfrac{12}{5}\)

\(\dfrac{1}{2}\)x-\(\dfrac{3}{5}\)=\(\dfrac{-4}{5}\)

3x+2x=-5,05

Answer 1

[Nguyễn Ngọc Huy Toàn]

1.\(x\times\dfrac{2}{3}=\dfrac{1}{5}\)

\(x=\dfrac{1}{5}:\dfrac{2}{3}\)

\(x=\dfrac{3}{10}\)

2.\(\dfrac{2}{x}=\dfrac{12}{5}\)

\(12x=2.5\)

\(x=\dfrac{10}{12}=\dfrac{5}{6}\)

3.\(\dfrac{1}{2}x-\dfrac{3}{5}=-\dfrac{4}{5}\)

\(\dfrac{1}{2}x=\dfrac{-4}{5}+\dfrac{3}{5}\)

\(\dfrac{1}{2}x=-\dfrac{1}{5}\)

\(x=-\dfrac{1}{5}:\dfrac{1}{2}\)

\(x=-\dfrac{2}{5}\)

4.\(3x+2x=-5,05\)

\(5x=-5,05\)

\(x=-\dfrac{5,05}{5}\)

\(x=-1,01\)

Answer 2

[★彡✿ทợท彡★]

\(x\cdot\dfrac{2}{3}=\dfrac{1}{5}\)

\(x=\dfrac{1}{5}:\dfrac{2}{3}\)

\(x=\dfrac{1}{5}\cdot\dfrac{3}{2}\)

\(x=\dfrac{3}{10}\)

\(\dfrac{2}{x}=\dfrac{12}{5}\)

\(x=\dfrac{\left(2\cdot5\right)}{12}\)

\(x=\dfrac{10}{12}\)

\(x=\dfrac{5}{6}\)

\(\dfrac{1}{2}x-\dfrac{3}{5}=\dfrac{-4}{5}\)

\(\dfrac{1}{2}x=\left(\dfrac{-4}{5}+\dfrac{3}{5}\right)\)

\(\dfrac{1}{2}x=-\dfrac{1}{5}\)

   \(x=\left(-\dfrac{1}{5}\right):\dfrac{1}{2}\)

   \(x=\left(-\dfrac{1}{5}\right)\cdot2\)

   \(x=-\dfrac{2}{5}\)

\(3x+2x=-5,05\)

\(\left(3+2\right)x=-5,05\)

\(5x=-5,05\)

  \(x=\left(-5,05\right):5\)

  \(x=-1,01\)