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4 3.5 + 4 5.7 + 4 7.9 + 4 9.11 = 4 2 5 − 3 3.5 + 7 − 5 5.7 + 9 − 7 7.9 + 11 − 9 9.11 = 2. 1 3 − 1 5 + 1 5 − 1 7 + 1 7 − 1 9 + 1 9 − 1 11 = 2. 1 3 − 1 11 = 2. 8 33 = 16 33
45 . 7 + 15 . 80 - 15
= 15.3.7 + 15.80 - 15
= 15.21 + 15.80 - 15
= 15.(21 + 80 - 1)
= 15.100
= 1500
45 . 7 + 15 . 80 - 15
= 15 . 3 . 7 + 15 . 80 - 15 . 1
= 15 . (21 + 80 - 1)
= 15 . 100
= 1500
M=\(\frac{4}{1.3}+\frac{4}{3.5}+...+\frac{4}{2011.2013}=2.\left(\frac{2}{1.3}+\frac{2}{3.5}+..+\frac{2}{2011.2013}\right)\)
=\(2\left(\frac{3-1}{1.3}+\frac{5-3}{3.5}+..+\frac{2013-2011}{2011.2013}\right)\)
=\(2\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{2011}-\frac{1}{2013}\right)\)
=\(2\left(1-\frac{1}{2013}\right)\)
=\(2.\frac{2012}{2013}=\frac{4024}{2013}\)
đề hình như sai rồi cái tổng cuối là 2011.2013 ms làm được
a) \(\left(-5\right)\left(x-2\right)^2+360=\left(-150\right)\cdot3+43\cdot5\)
\(-5\cdot\left(x-2\right)^2+360=-235\)
\(-5\cdot\left(x-2\right)^2=-595\)
\(\left(x-2\right)^2=119\)
\(\left(x-2\right)^2=\left(\pm\sqrt{199}\right)^2\)
\(\Rightarrow\orbr{\begin{cases}x-2=\sqrt{119}\\x-2=-\sqrt{119}\end{cases}\Rightarrow\orbr{\begin{cases}x=\sqrt{119}+2\\x=2-\sqrt{119}\end{cases}}}\)
b) \(\left(x+5\right)-\left(3x+9\right)=-16\)
\(x+5-3x-9=-16\)
\(-2x-4=-16\)
\(-2x=-12\)
\(x=6\)
c) \(3\left(x+2\right)-\left(15-x\right)\cdot6=160+\left(-1\right)^{1005}\)
\(3x+6-90+6x=160-1\)
\(9x-84=159\)
\(9x=243\)
\(x=27\)
d) \(x\left(x-1\right)\left(x^2-4\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x\left(x-1\right)=0\\x^2-4=0\end{cases}\Rightarrow\orbr{\begin{cases}x=\left\{0;1\right\}\\x=\left\{2;-2\right\}\end{cases}}}\)
\(\frac{x}{8}=\frac{-15}{30}\)
\(\Rightarrow x=\frac{-15.8}{30}\)
\(\Rightarrow x=-4\)
\(\frac{y}{6}=\frac{15}{-45}\)
\(\Rightarrow y=\frac{15.6}{-45}\)
\(\Rightarrow y=-2\)
A) \(\frac{x}{8}=\frac{-15}{30}\)
\(\Leftrightarrow\)\(x=\frac{\left(-15\right).8}{30}=-4\)
Vậy...
B) \(\frac{y}{6}=\frac{15}{-45}\)
\(\Leftrightarrow\)\(y=\frac{15.6}{-45}=-2\)
Vậy....
Bài làm
1.
a) \(\frac{5.7}{14.3}=\frac{5.7}{2.7.3}=\frac{5}{6}\)
b) \(\frac{3.55}{22.9}=\frac{3.5.11}{2.11.3.3}=\frac{5}{6}\)
c) \(\frac{10.63}{15.21}=\frac{2.5.7.3.3}{3.5.7.3}=2\)
d) \(\frac{3.11.13}{26.15}=\frac{3.11.13}{2.13.3.5}=\frac{11}{10}\)
2.
a) \(\frac{7.29+7.14}{43.5-43.11}=\frac{7\left(29+14\right)}{43\left(5-11\right)}=\frac{7.43}{43.-6}=-\frac{7}{6}\)
b) \(\frac{19.15-7.14}{38}=\frac{285-98}{38}=\frac{187}{38}\)
c) \(\frac{53.19-19.2}{7-60}=\frac{19\left(53-2\right)}{7-60}=\frac{19.51}{-53}=-\frac{969}{53}\)
d) \(\frac{120}{24.13-24.2}=\frac{120}{24\left(13-2\right)}=\frac{24.5}{24.11}=\frac{5}{11}\)