You bought a camera from a store last week, but now it isn’t working. Write a complaint email to the company. Write 120 – 150 words.
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Với `x \ne 0,x \ne 1` có:
`A=([x\sqrt{x}]/[\sqrt{x}-1]-[x^2]/[x\sqrt{x}])(1/\sqrt{x}-1)^2`
`A=([x\sqrt{x}]/[\sqrt{x}-1]-x/\sqrt{x})([1-\sqrt{x}]/\sqrt{x})^2`
`A=[x^2-x(\sqrt{x}-1)]/[\sqrt{x}(\sqrt{x}-1)].[(\sqrt{x}-1)^2]/x`
`A=[x(x-\sqrt{x}-1)]/\sqrt{x}.[\sqrt{x}-1]/x`
`A=[x-\sqrt{x}-1]/[\sqrt{x}-1]`

`a)`Ta có: \(\left\{{}\begin{matrix}AB\perp AC\\HE\perp AC\end{matrix}\right.\) \(\Rightarrow\)`AB////HE`
`b)`Ta có: \(\widehat{A}+\widehat{B}+\widehat{C}=180^o\)
\(\Rightarrow\widehat{C}=180^o-90^o-60^o=30^o\)
Xét tam giác AHC, có:
\(\widehat{HAC}=180^o-30^o-90^o=60^o\)
\(\widehat{A}=\widehat{BAH}+\widehat{HAC}\)
\(\Rightarrow\widehat{BAH}=90^o-60^o=30^o\)
Ta có: \(\widehat{BAH}=\widehat{AHE}=30^o\) ( so le trong )

Vì \(\widehat{xBA}=\widehat{BAD}\left(=50^o\right)\) mà \(\widehat{xBA}\text{ và }\widehat{BAD}\) là 2 góc so le trong
=> Bx//AD (1)
Vì \(\widehat{DAC}=\widehat{ACy}\left(=30^o\right)\) mà \(\widehat{DAC}\text{ và }\widehat{ACy}\) là 2 góc so le trong
=> AD // Cy (2)
Từ (1) và (2) => Bx // Cy
Ta có:
`@` \(\widehat{ABx}=\widehat{DAB}=50^o\)
`=>Bx////AD` ( 2 góc so le trong bằng nhau ) (1)
`@`\(\widehat{ACy}=\widehat{DAC}=30^o\)
`=>Cy////AD` ( 2 góc so le trong bằng nhau ) (2)
\(\left(1\right);\left(2\right)\Rightarrow\)`Bx////Cy`
Read Alex's blog about his hobby. Write a similar blog post about your hobby. Write 120 – 150 words.


số tiền lãi mà mẹ minh được nhận sau 6 tháng là
2062400 - 2000000 = 62400 (đồng)
mỗi tháng số tiền lãi mà mẹ minh nhận được là
62400 : 6 = 10400 (đồng)
% lãi hàng tháng là
10400 : 2000000 x 100 = 0,52%
đs....
số tiền lãi mà mẹ minh được nhận sau 6 tháng là
2062400 - 2000000 = 62400 (đồng)
mỗi tháng số tiền lãi mà mẹ minh nhận được là
62400 : 6 = 10400 (đồng)
% lãi hàng tháng là
10400 : 2000000 x 100 = 0,52%

a + b, A=\(\dfrac{x-3\sqrt{x}+2}{x-4\sqrt{x}+3}\) = \(\dfrac{\left(\sqrt{x}-1\right)\left(\sqrt{x}-2\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}-3\right)}\)=\(\dfrac{\sqrt{x}-2}{\sqrt{x}-3}\)
ĐKXĐ: \(\sqrt{x}-3\)\(\Leftrightarrow\sqrt{x}\)\(\ne\)3\(\Leftrightarrow\) x\(\ne\)9
c, \(\dfrac{\sqrt{x}-2}{\sqrt{x}-3}=\dfrac{\sqrt{x}-3+1}{\sqrt{x}-3}=1+\dfrac{1}{\sqrt{x}-3}\Rightarrow\sqrt{x}-3\inƯ\left(1\right)=\left\{\pm1\right\}\)
\(\sqrt{x}-3\) | 1 | -1 |
x | 16 | 4 |

My sister and I attended the F5 tour at the National Stadium last night. I could sum up the concert in one word, INCREDIBLE. We found our way up to our seats after having a light meal and stood in a queue at the gate of the stadium for 45 minutes. When the curtain was raised to reveal the F5 band, the entire stadium went absolutely crazy. I was thrilled by every of their performances. There was so much emotion in many of their songs, and the way they performed was so terrific. This was such a wonderful experience, a night that I'll never forget. I'm so grateful to have been able to have that experience.
Last week , i went to a charity concert with my sister , it called : FPC ( for poor children ) . Because the fare will be for poor children , I and my sister invited more friends to join us . It was held at Hoang Mai Stadium in Hanoi , at 6p.m. It is 40 minutes form my house to Hanoi if I go by bus , so I and my sister need to be in at 5:30 p.m to catch the bus . At the concert, there were many spectators involved. Featuring famous singers, the concert was more lively than ever. Both the songs and the lively dances are exciting . Although I don't like music, when I came to a charity concert, I felt very happy that I was able to help poor children get food and clothing.
From : ...
To : ...
Subject : The camera
Hi,
I'm ........ Are you the company called : ....... that product camera? I have a litte issue about your camera : Last week, I went to the store and bought a new camera which is made by your company. I like it very much. But this morning, when I'm going to take a picture of a flower, I realize that it isn't working any more. I checked it again and it's still not working. I didn't do anything like drop it to the ground since I bought it. I think there's some problem inside it. I'm really worry about the camera. What do you think the problem is? Can you come to my house and check the camera? I'm free tomorrow. If you can, please come by. Here's my address : ...........
Thank you!