Write a blog (60 – 80 words) for students with the title ‘How to survive homework’.
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a)
\(\begin{matrix}N\left(x\right)=-4x^4+9x^3-x^2+5x+\dfrac{1}{3}\\^-M\left(x\right)=-x^4-9x^3+x^2+9x+\dfrac{4}{3}\\\overline{N\left(x\right)-M\left(x\right)=-3x^4+18x^3-2x^2-4x-1}\end{matrix}\)
b)
\(\begin{matrix}M\left(x\right)=-x^4-9x^3+x^2+9x+\dfrac{4}{3}\\^+N\left(x\right)=-4x^4+9x^3-x^2+5x+\dfrac{1}{3}\\\overline{M\left(x\right)+N\left(x\right)=-5x^4+14x+\dfrac{5}{3}}\end{matrix}\)

Rõ ràng các góc $\angle AOD,\angle BOC $ được đề cập là các góc không lớn hơn $180^o$.
Khi đó ta thấy rằng $\angle AOD,\angle BOC$ là hai góc đối đỉnh nên $\angle AOD=\angle BOC$, từ đó kết hợp giả thiết ta thu được $2\angle AOD=100^o$ hay $\angle AOD=\angle BOC=50^o$
Khi đó $\angle BOD=\angle AOC=180^o-\angle 50^o=130^o$

Vì a \(\perp\) c và b \(\perp\) c nên a//b
=>\(\hat{B_1}=\hat{A_2}\)=600 (hai góc đồng vị)
Mà \(\hat{A_2}\) và \(\hat{A_1}\)là hai góc kề bù
=> \(\hat{A_1}+\hat{A_2}=180^o\)
hay \(\hat{A_1}\) + 60o=180o
=> \(\hat{A_1}\) = 180o-60o=120o
Vậy \(\hat{A_1}\)=1200

Đổi: 0,9=9/10
Vì vận tốc và thời gian tỉ lệ nghịch với nhau
=>Thời gian mới bằng 10/9 lần thời gian cũ
Thời gian ô tô đó đi từ A đến B nếu nó đi với vận tốc mới bằng 0,9 lần vận tốc cũ là: 10,8x10/9=12 (giờ)
Đáp số: 12 giờ
Cho 2 đa thức f(x)=2x2+ax+4f(x)=2x2+ax+4 và g(x)=x2−5x−bg(x)=x2−5x−b (a,ba,b là hằng số)
Tìm các hệ số a,ba,b sao cho f(1)=g(2)f(1)=g(2) và

\(P=\dfrac{2x+3}{3x+1}\) là số nguyên suy ra \(3P=\dfrac{6x+9}{3x+1}=\dfrac{6x+2+7}{3x+1}=2+\dfrac{7}{3x+1}\inℤ\)
\(\Leftrightarrow\dfrac{7}{3x+1}\inℤ\Rightarrow3x+1\inƯ\left(7\right)=\left\{-7,-1,1,7\right\}\) (vì \(x\) nguyên)
\(\Leftrightarrow x\in\left\{0,2\right\}\) (vì \(x\) nguyên)
Thử lại đều thỏa mãn.

b.ta có M là trung điểm NC nên MC=MB
ta lại có N là trung điểm MB => MN=NB
vậy MC=2323MN
xét tgac ACD có NC là đường trung tuyến ứng với cạnh AD
mà M thuộc CN và MC=2323MN nên theo định nghĩa M là trọng tâm tgiac ACD
mặt khác E là trung điểm CD vậy AE là đường trung tuyến ứng với CD vậy A; M;E thẳng hàng
Tam giác ABC cân tại A do đó trung tuyến AM vuông góc với BC
Tam giác AMB vuông tại M theo định lý pi-ta-go ta có
AM.AM + MB.MB = AB.AB
=> AM.AM = 13x13 -5x5 =144
=> AM = 12cm

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Homework is oftenly described as boring and challenging to many students. To be able to survive it, many ways have been suggested as followed. Firstly, pupils have to pay attention to teachers in classes. One of many reasons why homework is so difficult is that students don’t listen to their teachers, causing lack of knowledge required to finish homework; therefore, students will face multiple issues when doing their exercises. Secondly, students should try their best to focus when doing homework. Finishing homework require sitting down, which is considered boring to many kids. Picking a quite place to study and balancing the amount of time resting and working can greatly improve one’s concentration. Finally, youngster need to understand that homework is given for their own good. Doing homework not only will strengthen your knowledge, but also give you a brighter future. In conclusion, despite the fact that homework is a great trouble to many students, every kid should try their best to finish them.
Everyone has their own study habits which are suitable to their routines. Personally, I have to go to school in the morning on weekdays, therefore, I spend the afternoon doing the homework. At night, after eating dinner, I often relax for a while by surfing Facebook or Youtube, and then come back to my desk. If the homework is completed, I normally practice some extra English exercises. My mother has bought several English learning books for me. On Monday and Tuesday, I have an extra course in Mathematics, so I’m a little bit busy those days. In addition, being interested in editing videos, I usually spend my free time watching videos on Youtube about this topic and practicing it myself.