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a/ (y+2/9):7/4=11/7
y+2/9=11/7.7/4
y+2/9=11/4
y=11/4-2/9
y=91/36
a, \(y=\dfrac{7}{11}-\dfrac{5}{14}=\dfrac{98-55}{154}=\dfrac{43}{154}\)
b, \(y=\dfrac{8}{9}.\dfrac{4}{7}=\dfrac{32}{63}\)
y + y x 9 : 3 - y x 4 + y x 7 = 105
y x 1 + y x 3 - y x 4 + y x 7 = 105
y x ( 1 + 3 - 4 + 7 ) = 105
y x 7 = 105
y = 105 : 7
y = 15
Vậy y = 15
y+y*9:3-y*4+y*7=105
y+y*3-y*4+y*7=105
y*(1+3-4+7)=105
y*7=105
y=105:7
y=15
a) y + 3/7 x 21/9 = 5
y + 3/7 x 7/3 = 5
y + 1 = 5
y = 4
b) y x 3/5 - 1/2 = 4/5
y x 3/5 = 4/5 + 1/2
y x 3/5 = 13/10
y = 13/6
c) 9/8 - y + 2/5 = 1/4
y - 2/5 = 9 /8 - 1/4
y - 2/5 = 7/8
y = 51/40
d) y - 6/5 : 2/3 = 5/6
y - 9/5 = 5/6
y = 79/30
e) y : 7/8 + 3/4 = 7/4
y : 7/8 = 1
y = 7/8
a: =>y-7/10=4/10
=>y=11/10
b: \(\Leftrightarrow y\cdot\dfrac{4}{9}=\dfrac{3}{2}\)
hay y=27/8
Câu 10:
\(a,y\times7+y\times3=70\\ \Rightarrow y\times\left(7+3\right)=70\\ \Rightarrow y\times10=70\\ \Rightarrow y=7\\ b,18:y+12:y=3\\ \Rightarrow\left(18+12\right):y=3\\ \Rightarrow30:y=3\\ \Rightarrow y=10\)
câu 11:
\(a,9\times365+2\times365-365=\left(9+2-1\right)\times365=10\times365=3650\\ b,108:9-18:9=\left(108-18\right):9=90:9=10\\ c,43\times95+4\times43+43=43\times\left(95+4+1\right)=43\times100=4300\)
a) y : 4/11 x 3/5 = 27/4
y : 4/11 = 27/4 : 3/5
y : 4/11 = 45/4
y = 45/4 x 4/11
y = 45/11
b) y + 7/2 - 5/9 = 14/3
y + 7/2 = 14/3 + 5/9
y + 7/2 = 47/9
y = 47/9 - 7/2
y = 31/18
a) y : 4/11 x 3/5 = 27/4
y : 4/11 = 27/4 : 3/5
y : 4/11 = 45/4
y = 45/4 x 4/11
y = 45/11
b) y + 7/2 - 5/9 = 14/3
y + 7/2 = 14/3 + 5/9
y + 7/2 = 47/9
y = 47/9 - 7/2
y = 31/18