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a,
143,8 x 2,25 + 143,8 x 7,75
= 143,8 x ( 2,25 + 7,75 )
= 143,8 x 10
= 1438
b, 12% x 5 + 0,4 x 2 + 2
= 0,12 x 5 + 0,4 x 2 + 2
= 0,6 + 0,8 + 2
= 0,6 + 3
= 3,6
#Giang
\(\left(x-\dfrac{1}{2}\right).\dfrac{5}{2}=\dfrac{7}{4}-\dfrac{1}{2}\)
\(\Rightarrow\left(x-\dfrac{1}{2}\right).\dfrac{5}{2}=\dfrac{5}{4}\)
\(\Rightarrow x-\dfrac{1}{2}=\dfrac{1}{2}\)
=> x = 1
Ta có: \(\left(x-\dfrac{1}{2}\right)\cdot\dfrac{5}{2}=\dfrac{7}{4}-\dfrac{1}{2}\)
\(\Leftrightarrow\left(x-\dfrac{1}{2}\right)\cdot\dfrac{5}{2}=\dfrac{5}{4}\)
\(\Leftrightarrow x-\dfrac{1}{2}=\dfrac{1}{2}\)
hay x=1
= 2,5 giờ x 7 + 2,5 giờ x 1 + 2,5 giờ x 2
= 2,5 giờ x (1 + 2 + 7)
= 2,5 giờ x 10
= 25 giờ
HT
Tìm X
\(\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times\left(1-\frac{1}{4}\right)\times\left(1-\frac{1}{5}\right)\)
\(=\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times\frac{4}{5}\)
\(=\frac{1}{5}\)
\(\Rightarrow x-100=\frac{1}{5}\)
\(x=\frac{1}{5}+100\)
\(x=\frac{1}{5}+\frac{500}{5}\)
\(x=\frac{501}{5}\)
\(y+\frac{1}{2}y=\frac{4}{5}\\ 1y+\frac{1}{2}y=\frac{4}{5}y\\ \left(1+\frac{1}{2}\right)y=\frac{4}{5}\\ \frac{3}{2}y=\frac{4}{5}\\ y=\frac{4}{5}:\frac{3}{2}\\ y=\frac{4}{5}\times\frac{2}{3}\\ y=\frac{8}{15}\)
y + 1/2 x y =4/5
y x 2 = 4/5-1/2
y x 2 = 3/10
y= 3/10 x2
y = 6/10=3/5
y x ( 2 + 1/5 ) = 8/5
y x 11 /5 = 8/5
Đến đây bạn tự giải đi nha
1/2 x y + 1/3 x y + 1/4 x y = 11/4
y x ( 1/2 + 1/3 + 1/4 ) = 11/4
y x 13/12 = 11/4
y = 11/4 : 13/12
y = 11/4 x 12/13
y = 33/13
^^ Học tốt!
\(\frac{1}{2}\times Y+\frac{1}{3}\times Y+\frac{1}{4}\times Y=\frac{11}{4}\)
\(3Y=\frac{11}{4}\div\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\right)\)
\(3Y=\frac{33}{13}\)
\(Y=\frac{33}{13}\div3\)
\(Y=\frac{11}{13}\)
~ Chúc bạn học tốt
=>15/4y=3/2
hay y=2/5
\(y\times3+\dfrac{y}{2}+\dfrac{y}{4}=1\dfrac{1}{2}\\ \Rightarrow y\times3+y\times\dfrac{1}{2}+y\times\dfrac{1}{4}=\dfrac{3}{2}\\ \Rightarrow y\times\left(3+\dfrac{1}{2}+\dfrac{1}{4}\right)=\dfrac{3}{2}\\ \Rightarrow y\times\dfrac{15}{4}=\dfrac{3}{2}\\ \Rightarrow y=\dfrac{3}{2}:\dfrac{15}{4}\\ \Rightarrow y=\dfrac{2}{5}\)